Chapter 8: Problem 26
Find all solutions of the equation. $$2 \cos 2 x+1=0$$
Short Answer
Expert verified
The solutions are \(x = \frac{\pi}{3} + k\pi\) and \(x = \frac{2\pi}{3} + k\pi\) for integer \(k\).
Step by step solution
01
Isolate Cosine Expression
The given equation is \( 2 \cos 2x + 1 = 0 \). First, we need to isolate the cosine expression. Subtract 1 from both sides to get: \[ 2 \cos 2x = -1 \]. Next, divide both sides by 2: \[ \cos 2x = -\frac{1}{2} \].
02
Solve for the Angle
We have \( \cos 2x = -\frac{1}{2} \). The cosine of an angle is \(-\frac{1}{2}\) at the angles \(2x = \frac{2\pi}{3} + 2k\pi\) and \(2x = \frac{4\pi}{3} + 2k\pi\), where \(k\) is an integer, representing the general solution for cosine.
03
Solve for x
Now, solve for \(x\) from the equations we found: \(2x = \frac{2\pi}{3} + 2k\pi\) leads to \(x = \frac{\pi}{3} + k\pi\), and \(2x = \frac{4\pi}{3} + 2k\pi\) leads to \(x = \frac{2\pi}{3} + k\pi\). These are the general solutions for \(x\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cosine Function
The cosine function, often represented as \( \cos \theta \), is a fundamental trigonometric function that relates the angle \( \theta \) to the ratio of the adjacent side of a right triangle to its hypotenuse. Within the unit circle framework, cosine corresponds to the x-coordinate of a point located on the circle's circumference.
When analyzing trigonometric equations like \( 2 \cos 2x + 1 = 0 \), understanding the behavior of the cosine function is crucial. The cosine function is periodic, with a standard period of \(2\pi\), meaning it repeats its values every \(2\pi\) radians.
When analyzing trigonometric equations like \( 2 \cos 2x + 1 = 0 \), understanding the behavior of the cosine function is crucial. The cosine function is periodic, with a standard period of \(2\pi\), meaning it repeats its values every \(2\pi\) radians.
- This periodicity allows the cosine function to have the same value at multiple points over its domain.
- This is why multiple angles can satisfy the same cosine value within one cycle.
Angle Solving
Solving for angles in trigonometric equations, such as \( \cos 2x = -\frac{1}{2} \), requires knowledge of the unit circle and several key angles. The equation asks us to determine which angles 2x equates to, where the cosine value is \(-\frac{1}{2}\).
For the cosine function, this specifically occurs at \(\frac{2\pi}{3}\) and \(\frac{4\pi}{3}\) radians within one cycle of the circle.
For the cosine function, this specifically occurs at \(\frac{2\pi}{3}\) and \(\frac{4\pi}{3}\) radians within one cycle of the circle.
- These angles represent the standard solutions when \(x\) is limited to \([-\pi, \pi]\).
- Each corresponding angle marks positions where the horizontal coordinate is negative, matching \(-\frac{1}{2}\).
General Solution
The general solution of a trigonometric equation captures all possible solutions across its infinite, periodic nature. For an equation like \( \cos 2x = -\frac{1}{2} \), it’s essential to provide a solution format that encompasses every instance where the function returns this value.
Cosine's periodicity demands that solutions not only capture angles in a single traversal of the unit circle but also loop infinitely along its entire domain.
Cosine's periodicity demands that solutions not only capture angles in a single traversal of the unit circle but also loop infinitely along its entire domain.
- This is accomplished using integers \(k\), indicating multiple cycles in the solution.
- For our specific example, the general solutions are \(x = \frac{\pi}{3} + k\pi\) and \(x = \frac{2\pi}{3} + k\pi\).
- The parameter \(k\) is an integer that accounts for these infinite cycles.