/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 70 Find the values of the trigonome... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the values of the trigonometric functions of \(t\) from the given information. \(\tan t=-4, \quad \csc t>0\)

Short Answer

Expert verified
The values are \( \sin t = \frac{4}{\sqrt{17}}, \cos t = -\frac{1}{\sqrt{17}}, \tan t = -4, \csc t = \frac{\sqrt{17}}{4}, \sec t = -\sqrt{17} \).

Step by step solution

01

Understanding the Given Information

We are given that \( \tan t = -4 \) and \( \csc t > 0 \). \( \tan t \) is negative, which means that \( t \) must be in either the second or fourth quadrant, because tangent is negative in those quadrants. The condition \( \csc t > 0 \) implies that \( \sin t > 0 \), since \( \csc t = \frac{1}{\sin t} \). Therefore, \( t \) has to be in the second quadrant where sine is positive and tangent is negative.
02

Establishing Relationships with Trigonometric Functions

The tangent of an angle is defined as \( \tan t = \frac{\sin t}{\cos t} \). From \( \tan t = -4 \), we can set \( \sin t = 4k \) and \( \cos t = -k \), where \( k \) is a positive constant, to maintain the relationship \( \tan t = \frac{\sin t}{\cos t} = -4 \).
03

Applying the Pythagorean Identity

Use the Pythagorean identity \( \sin^2 t + \cos^2 t = 1 \). Substitute the values \( \sin t = 4k \) and \( \cos t = -k \) into the identity: \[(4k)^2 + (-k)^2 = 1\]This simplifies to \( 16k^2 + k^2 = 1 \), or \( 17k^2 = 1 \).
04

Solving for Constant k

Solve for \( k \) by dividing both sides by 17: \( k^2 = \frac{1}{17} \). Take the positive square root to find \( k \): \( k = \frac{1}{\sqrt{17}} \).
05

Calculating Sin and Cos

Substitute \( k = \frac{1}{\sqrt{17}} \) back into the expressions for \( \sin t \) and \( \cos t \): \[\sin t = 4k = \frac{4}{\sqrt{17}}\]\[\cos t = -k = -\frac{1}{\sqrt{17}}\]
06

Finding Secant and Cosecant

Calculate \( \csc t \) and \( \sec t \) using \( \sin t \) and \( \cos t \), respectively:\[\csc t = \frac{1}{\sin t} = \frac{\sqrt{17}}{4}\]\[\sec t = \frac{1}{\cos t} = -\sqrt{17}\]
07

Verification with Given Conditions

Verify that these values match the given conditions. Indeed, \( \csc t > 0 \) is satisfied as \( \csc t = \frac{\sqrt{17}}{4} \) is positive, and \( \tan t = -4 \) confirms \( \tan \) is negative, fitting the requirements for \( t \)'s quadrant.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tangent Function
The tangent function, denoted as \( \tan \), is a fundamental trigonometric function that relates an angle to the ratio of the opposite side to the adjacent side in a right triangle. This relationship is expressed in the formula \( \tan t = \frac{\sin t}{\cos t} \). When we say \( \tan t = -4 \), it indicates that the ratio of the sine of angle \( t \) to its cosine is -4. This negative sign reveals where \( t \) could lie on the unit circle.

Key attributes of the tangent function include:
  • It's periodic with period \( \pi \).
  • It has zeros at every multiple of \( \pi \).
  • It becomes undefined at odd multiples of \( \frac{\pi}{2} \).
Understanding the nature of tangent helps us interpret the behavior and properties of the angle \( t \). A negative tangent value, like in our example, situates the angle in quadrants where sine and cosine have different signs to maintain their ratio's negativity.
Cosecant
The cosecant function, denoted as \( \csc \), is another important trigonometric function. It is defined as the reciprocal of sine: \( \csc t = \frac{1}{\sin t} \). From this definition, we observe that the cosecant function deals with the lengths in the unit circle just like sine but inverted. When given that \( \csc t > 0 \), we understand that \( \sin t \) must also be positive, as a positive cosecant implies a positive sine.

Features of the cosecant function:
  • It is undefined wherever \( \sin t = 0 \), which occurs at integer multiples of \( \pi \).
  • It shares the periodicity of the sine function, repeating every \( 2\pi \).
  • It reaches maximum and minimum values at the midpoint and endpoints of its period.
In our scenario, knowing that \( \csc t > 0 \) helps us isolate which quadrant the angle resides in, fulfilling its role alongside tangent in determining the position of \( t \) on the coordinate plane.
Pythagorean Identity
The Pythagorean identity is a crucial equation in trigonometry that states \( \sin^2 t + \cos^2 t = 1 \). This identity is a tool to connect sine and cosine values for any angle, showing the intrinsic relationship between these functions on the unit circle.

Applying this identity simplifies problem-solving involving trigonometric expressions:
  • Given one trigonometric function, the identity can help derive others.
  • It provides a method for verifying calculations involving sine and cosine.
  • It's central to converting between different trigonometric forms and equations.
In our problem, substituting \( \sin t = 4k \) and \( \cos t = -k \) into the identity let us solve for \( k \), leading to the specific values for \( \sin t \) and \( \cos t \). This identity proves foundational in understanding the behavior and constraints of trigonometric functions.
Quadrant Identification
The quadrants of the coordinate system play a vital role in determining the signs of trigonometric functions. The coordinate plane is divided into four quadrants, each exhibiting different sign characteristics for sine, cosine, and tangent functions. Knowing which quadrant an angle is in can provide insights into the properties of trigonometric values.

Characteristics of each quadrant include:
  • First Quadrant: \( \sin t > 0, \cos t > 0, \tan t > 0 \)
  • Second Quadrant: \( \sin t > 0, \cos t < 0, \tan t < 0 \)
  • Third Quadrant: \( \sin t < 0, \cos t < 0, \tan t > 0 \)
  • Fourth Quadrant: \( \sin t < 0, \cos t > 0, \tan t < 0 \)
In our exercise, with \( \tan t = -4 \) and \( \csc t > 0 \), determining \( t \) to be in the second quadrant reflects the combination of a negative tangent and a positive sine, aligning with the characteristics of the quadrants' signs. This identification assists in not only solving the current problem but also in approach for any trigonometric reasoning involving angles.

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Most popular questions from this chapter

When a car with its horn blowing drives by an observer, the pitch of the horn seems higher as it approaches and lower as it recedes (see the figure). This phenomenon is called the Doppler effect. If the sound source is moving at speed \(v\) relative to the observer and if the speed of sound is \(v_{0},\) then the perceived frequency \(f\) is related to the actual frequency \(f_{0}\) as follows: $$f=f_{0}\left(\frac{v_{0}}{v_{0} \pm v}\right)$$ We choose the minus sign if the source is moving toward the observer and the plus sign if it is moving away. Suppose that a car drives at 110 ft/s past a woman standing on the shoulder of a highway, blowing its horn, which has a frequency of 500 Hz. Assume that the speed of sound is 1130 ft/s. (This is the speed in dry air at \(70^{\circ} \mathrm{F}\) . (a) What are the frequencies of the sounds that the woman hears as the car approaches her and as it moves away from her? (b) Let A be the amplitude of the sound. Find functions of the form $$y=A \sin \omega t$$ that model the perceived sound as the car approaches the woman and as it recedes.

A ferris wheel has a radius of 10 m, and the bottom of the wheel passes 1 m above the ground. If the ferris wheel makes one complete revolution every 20 s, find an equation that gives the height above the ground of a person on the ferris wheel as a function of time.

Reduction Formulas A reduction formula is one that can be used to "reduce" the number of terms in the input for a trigonometric function. Explain how the figure shows that the following reduction formulas are valid: $$ \sin (t+\pi)=-\sin t \quad \cos (t+\pi)=-\cos t $$ $$ \tan (t+\pi)=\tan t $$

Find the sign of the expression if the terminal point determined by \(t\) is in the given quadrant. \(\sin t \cos t, \quad\) quadrant II

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