Chapter 7: Problem 36
7–52 Find the period and graph the function. $$y=5 \sec 2 \pi x$$
Short Answer
Expert verified
The period of the function is 1.
Step by step solution
01
Understand the Function Form
The given function is of the form \( y = a \sec(bx + c) + d \). For the function \( y = 5 \sec(2\pi x) \), the values are \( a = 5 \), \( b = 2\pi \), \( c = 0 \), and \( d = 0 \). This is a transformation of the secant function \( \sec x \).
02
Determine the Period of \( y = \sec(bx) \)
The general period of the secant function \( \sec x \) is \( 2\pi \). For \( \sec(bx) \), the period is \( \frac{2\pi}{|b|} \). Here, \( b = 2\pi \), so the period is \( \frac{2\pi}{2\pi} = 1 \).
03
Identify Critical Points for Graphing
The secant function \( \sec x \) has vertical asymptotes where the cosine function is zero. For \( \sec(2\pi x) \), these points occur at \( 2\pi x = \frac{\pi}{2} + k\pi \) where \( k \) is an integer. Solving for \( x \), we have \( x = \frac{1}{4} + \frac{k}{2} \). These x-values indicate vertical asymptotes.
04
Sketch the Secant Function
Plot the function considering its period \( 1 \) and vertical asymptotes. Within one period \( [0, 1] \), asymptotes occur at \( x = \frac{1}{4} \) and \( x = \frac{3}{4} \). Between these points, sketch the characteristic ups and downs of the secant curve, avoiding where \( \cos(2\pi x) = 0 \). Scale by the factor \( 5 \), which stretches the curve vertically by a factor of 5.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Secant Function
The secant function, often denoted as \( \sec x \), is a trigonometric function related to the cosine function. Specifically, it is the reciprocal of the cosine function, which means it is defined as \( \sec x = \frac{1}{\cos x} \). Understanding this relationship is crucial because it helps to identify the behavior and characteristics of the secant function.
Here are some key points to remember about the secant function:
Here are some key points to remember about the secant function:
- The secant function is undefined wherever the cosine function is zero. This is because division by zero is undefined.
- Vertical asymptotes appear in the graph of \( \sec x \) at these undefined points, where \( \cos x = 0 \).
- The secant function has periodic vertical asymptotes, which contribute to its unique shape on the graph.
Period of a Function
One of the essential characteristics of trigonometric functions, such as the secant function, is their periodic nature. The period of a function refers to the interval after which the function repeats its values. For a basic secant function, \( \sec x \), the period is \( 2\pi \), meaning the function repeats every \( 2\pi \) units.
When the function undergoes transformations, the period can change. Specifically, for a transformed secant function of the form \( \sec(bx) \), the period will be \( \frac{2\pi}{|b|} \). This is crucial for graphing, as it determines the horizontal stretch or compression of the curve. For the function \( y = 5 \sec(2\pi x) \):
When the function undergoes transformations, the period can change. Specifically, for a transformed secant function of the form \( \sec(bx) \), the period will be \( \frac{2\pi}{|b|} \). This is crucial for graphing, as it determines the horizontal stretch or compression of the curve. For the function \( y = 5 \sec(2\pi x) \):
- The value of \( b \) is \( 2\pi \).
- The period is calculated as \( \frac{2\pi}{2\pi} = 1 \).
Graphing Trigonometric Functions
Graphing trigonometric functions, such as the secant function, involves understanding both their mathematical definitions and transformations. For the function \( y = 5 \sec(2\pi x) \), sketching its graph accurately requires identifying key features like its period, vertical asymptotes, and any transformations applied to it.
- Vertical Asymptotes: First, determine where the cosine part of the function equals zero, creating vertical asymptotes. For this function, vertical asymptotes occur when \( \cos(2\pi x) = 0 \), resulting in asymptotes at points \( x = \frac{1}{4} + \frac{k}{2} \) where \( k \) is an integer.
- Plotting the Curve: Between each set of asymptotes, plot the characteristic ups and downs of the secant curve. Ensure you avoid crossing the vertical asymptotes as the function is not defined there.
- Transformation Effects: The multiplication factor of 5 stretches the curve vertically by a factor of 5, amplifying the maximum and minimum points of the secant curve within each period interval.