/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 Solve triangle \(A B C\). \(b=... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve triangle \(A B C\). \(b=125, \quad c=162, \quad \angle B=40^{\circ}\)

Short Answer

Expert verified
Angles: A = 83.53°, C = 56.47°; Side: a ≈ 192.6.

Step by step solution

01

Use the Law of Sines to Find Angle C

According to the Law of Sines, \( \frac{b}{\sin B} = \frac{c}{\sin C} \). Substituting the given values yields \( \frac{125}{\sin 40^{\circ}} = \frac{162}{\sin C} \). Solving this equation gives \( \sin C \approx 0.834 \), hence \( C \approx 56.47^{\circ} \).
02

Determine Angle A

Since the angles of a triangle sum up to \(180^{\circ}\), we can find \( \angle A \) using the expression \( A = 180^{\circ} - B - C \). Substituting the known values gives \( A = 180^{\circ} - 40^{\circ} - 56.47^{\circ} = 83.53^{\circ} \).
03

Use the Law of Sines to Find Side a

Again using the Law of Sines, \( \frac{a}{\sin A} = \frac{b}{\sin B} \). Therefore, \( a = b \cdot \frac{\sin A}{\sin B} \). Substituting \( b = 125 \), \( \sin A = \sin 83.53^{\circ} \), and \( \sin B = \sin 40^{\circ} \), we find \( a \approx 192.6 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solving triangles
Solving a triangle involves finding all the unknown sides and angles when some are already known. In the given exercise, we have a triangle with side lengths and one angle given: side \(b = 125\), side \(c = 162\), and \(\angle B = 40^{\circ}\). Our goal is to calculate the unknown side \(a\) and angles \(\angle A\) and \(\angle C\).

The process starts by finding \(\angle C\) using the Law of Sines. Once we have \(\angle C\), we can determine \(\angle A\) since the sum of angles in any triangle must be \(180^{\circ}\). With all angles known, the Law of Sines is used again to find the length of side \(a\).

By breaking down the problem into these steps, we methodically solve the triangle. Each calculation builds on the previous one, ensuring that all aspects of the triangle are explored thoroughly.
Trigonometry
Trigonometry is the study of the relationships between angles and sides of triangles. It is essential for solving problems involving triangles like the one here. The Law of Sines, a fundamental concept in trigonometry, helps in determining missing sides or angles in a triangle.

The Law of Sines states that \( \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} \). This relationship holds for any triangle and is especially useful when dealing with non-right triangles. In this exercise, we used it to find \(\angle C\) first, and then side \(a\) after the angles were determined.

Understanding trigonometry and its laws allow us to work with triangles in various mathematical and real-world applications, like engineering and physics. It provides the tools required to solve more complex problems and helps us understand the geometric properties of triangles.
Triangle angles
Every triangle is defined by three angles which always sum up to \(180^{\circ}\). Knowing this basic property is crucial for solving triangles when one or two angles are unknown. In our example, we start with just one angle, \(\angle B = 40^{\circ}\), and use the Law of Sines to compute \(\angle C\).

With \(\angle C\) determined to be approximately \(56.47^{\circ}\), we then find \(\angle A\) by subtracting the known angles from \(180^{\circ}\). This gives us \(\angle A = 83.53^{\circ}\).

Remembering that the sum of angles is always \(180^{\circ}\) helps in verifying our solution. If the sum of our calculated angles deviates from this value, it indicates an error in the calculations, allowing us to cross-check and correct any mistakes, ensuring the integrity of our solution.

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