/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 Sketch the graph of the polynomi... [FREE SOLUTION] | 91Ó°ÊÓ

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Sketch the graph of the polynomial function. Make sure your graph shows all intercepts and exhibits the proper end behavior. $$ P(x)=\frac{1}{4}(x+1)^{3}(x-3) $$

Short Answer

Expert verified
Graph intersects x-axis at \( -1 \) and \( 3 \), y-axis at \(-\frac{3}{4}\), rising to infinity both ends.

Step by step solution

01

Identify the degree of the polynomial

The polynomial P(x) is given by \( P(x) = \frac{1}{4}(x+1)^3(x-3) \). **Multiply the exponents to determine the degree:** \( (x+1)^3 \) has degree 3, and \( (x-3) \) has degree 1. Therefore, the total degree of the polynomial is \( 3 + 1 = 4 \). A degree 4 polynomial is a quartic function.
02

Determine the leading coefficient and end behavior

The leading coefficient is the coefficient of the term with the highest power when expanded, which here is \( \frac{1}{4} \). Since the degree is even and the leading coefficient is positive, the end behavior is **upward** on both ends, meaning as \( x \to -\infty \), \( P(x) \to \infty \) and as \( x \to \infty \), \( P(x) \to \infty \).
03

Find the x-intercepts

Set \( P(x) = 0 \) to find the x-intercepts. The function is zero when either \( (x+1)^3 = 0 \) or \( (x-3) = 0 \). Solving these, we find **x-intercepts are** \( x = -1 \) with multiplicity 3, and \( x = 3 \) with multiplicity 1. Multiplicity 3 indicates a point of inflection at \( x = -1 \), and multiplicity 1 indicates a sign change at \( x = 3 \).
04

Find the y-intercept

Evaluate the function at \( x = 0 \) to find the y-intercept: \( P(0) = \frac{1}{4}(0+1)^3(0-3) = \frac{1}{4} \times 1 \times (-3) = -\frac{3}{4} \). Thus, the **y-intercept is** \( (0, -\frac{3}{4}) \).
05

Plot key points and sketch the graph

**Plot the intercepts** on the coordinate plane: \(( -1, 0)\), \((3, 0)\), and \((0, -\frac{3}{4})\). Using the multiplicities, pass through \((-1, 0)\) with a point of inflection, and move straight through \((3, 0)\). Ensure the graph approaches infinite in both directions due to the end behavior.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quartic Function
A quartic function is a type of polynomial that has a degree of four. This means the highest power of the variable, typically denoted as \( x \), is 4. Quartic functions are interesting because they have a variety of shapes and features, including the possibility of having up to four x-intercepts and three turning points or local peaks and valleys in their graphs.

The general form of a quartic function is \( ax^4 + bx^3 + cx^2 + dx + e \), where \( a eq 0 \). The coefficient \( a \) determines the basic shape or stretch of the graph, while \( e \) is often the y-intercept or where the graph crosses the y-axis. In this exercise, the quartic function is expressed as \( \frac{1}{4}(x+1)^3(x-3) \), reflecting a more factored form. This form can help identify key features like roots or intercepts directly from the factorized equation.
End Behavior
The end behavior of a polynomial function is how the graph behaves as \( x \) approaches positive or negative infinity. This behavior is crucial for understanding the long-term trend of the graph. For quartic functions, the end behavior is largely influenced by the leading term, in this case, \( \frac{1}{4}x^4 \).

Since our quartic function has a positive leading coefficient \( \frac{1}{4} \) and even degree, the graph will rise on both sides. This means:
  • As \( x \to -\infty \), \( P(x) \to \infty \).
  • As \( x \to \infty \), \( P(x) \to \infty \).
This consistent upward trend as \( x \) moves away from zero in either direction is typical for servings of quartic functions with a positive coefficient for the term with the highest power.
X-intercepts
X-intercepts are points where the graph of a function crosses the x-axis. These occur when the function's output is zero, or in mathematical terms, \( P(x) = 0 \). For our specific function \( P(x) = \frac{1}{4}(x+1)^3(x-3) \), the intercepts occur at points derived from the roots of the equation.

To find the x-intercepts:
  • Solve \( (x+1)^3 = 0 \) which gives the intercept \( x = -1 \) with multiplicity 3. This indicates a point of inflection, where the graph merely touches and then bends away from the x-axis.
  • Solve \( (x-3) = 0 \) which provides the intercept \( x = 3 \) with multiplicity 1. Here, the graph crosses the x-axis, signifying a change in the sign of the function values.
Each x-intercept tells us where the polynomial equals zero and how the graph interacts with the x-axis at those points.
Polynomial Degree
The polynomial degree is a fundamental characteristic, quickly revealing the highest power of the variable \( x \) in the polynomial expression. It essentially determines the general shape and behavior of the graph. For the polynomial \( P(x) = \frac{1}{4}(x+1)^3(x-3) \), we calculate its degree by adding up the exponents associated with each factor:
  • The degree of \((x+1)^3\) is 3.
  • The degree of \((x-3)\) is 1.
Adding these together gives a total degree of 4, confirming as a quartic function. The degree tells us several important aspects about the polynomial, including:
  • The number of x-intercepts it can have (up to 4 for a quartic).
  • The potential for three turning points, as per the general rule of \( n-1 \), where \( n \) is the degree.
Understanding the degree helps in sketching the graph and predicting the shape and turning behavior of the polynomial.

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