/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 61 Determine whether the equation d... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine whether the equation defines y as a function of x. (See Example 10.) $$ x^{2}+2 y=4 $$

Short Answer

Expert verified
Yes, the equation defines y as a function of x.

Step by step solution

01

Understand the Problem Statement

We want to determine if the equation \(x^2 + 2y = 4\) defines \(y\) as a function of \(x\). A relation is a function if each input \(x\) corresponds to one output \(y\).
02

Isolate y in the Equation

Rearrange the equation to solve for \(y\). Start by moving \(x^2\) to the other side of the equation: \(2y = 4 - x^2\).
03

Solve for y

Divide every term in the equation \(2y = 4 - x^2\) by 2 to isolate \(y\). This gives \(y = rac{4 - x^2}{2}\).
04

Analyze the Result

The expression \(y = rac{4 - x^2}{2}\) is uniquely determined by \(x\), meaning for each \(x\), there is only one corresponding \(y\). This satisfies the definition of a function.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relations
In mathematics, a relation between two variables can often be expressed as an equation, showing how one variable possibly depends on another. When we talk about relations in the context of functions, we are specifically interested in whether the relationship specifies each input with a unique output. In our example, the equation is given by \(x^2 + 2y = 4\). This is a relation between \(x\) and \(y\) that connects the values of these variables to each other.
To determine if this relation is a function, we need to see if for every value of \(x\), there is one and only one corresponding value for \(y\). This is essential to the concept of functions.
  • A function assigns exactly one output value for each input value.
  • If different inputs can yield the same output, that's still a function.
  • However, if a single input could give different outputs, it is not a function.
In this particular case, after rearranging the equation and solving for \(y\), each \(x\) indeed corresponds to one \(y\), affirming that this relation is actually a function.
Solving Equations
Solving equations is a fundamental skill in algebra that helps us find the values of unknown variables. To solve an equation means to isolate one of the variables, typically \(y\) in the context of functions, by manipulating the equation using algebraic principles.
For the given equation \(x^2 + 2y = 4\), we first move the \(x^2\) term to the right side of the equation:
2y = 4 - x^2.

Next, we divide the entire equation by 2 to isolate \(y\):
\(y = \frac{4 - x^2}{2}\).
  • The goal is to express \(y\) solely in terms of \(x\).
  • This process ensures we can clearly see how \(y\) varies with different \(x\) values.
  • Notice the steps involve basic operations: addition, subtraction, and division.
Solving this equation reveals the nature of the relation by helping us understand how \(y\) depends on \(x\), which is crucial when assessing if the relation defines a function.
Function Analysis
After establishing that \(y = \frac{4 - x^2}{2}\), we can perform a function analysis to understand its behavior and confirm its uniqueness and validity as a function. Here are some aspects to consider:
  • Uniqueness: The expression for \(y\) after solving the equation indicates that for each value of \(x\), there is a single specific value of \(y\). This one-to-one correspondence confirms that the equation defines a function.

  • Domain and Range: In general, for the function \(y = \frac{4 - x^2}{2}\), all real \(x\) values are possible unless further restricted by context, determining the function's domain. The range is determined by the possible values that \(y\) can take, which is dictated by the operations involving \(x\).

  • Graphical Representation: Graphing the function gives a visual representation, often making it easier to understand its characteristics and confirm the one-to-one nature of the relation.
Function analysis helps us not only identify the existence of a function from a relation but also predict its behavior and characteristics.

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Most popular questions from this chapter

\(55-56\) : Revenue, Cost, and Profit A print shop makes bumper stickers for election campaigns. If \(x\) stickers are ordered (where \(x<10,000\) ), then the price per sticker is \(0.15-0.000002 x\) dollars, and the total cost of producing the order is \(0.095 x-0.0000005 x^{2}\) dollars. Use the fact that profit \(=\) revenue \(-\) cost to express \(P(x),\) the profit on an order of \(x\) stickers, as a difference of two functions of \(x .\)

Minimizing a Distance When we seek a minimum or maximum value of a function, it is sometimes easier to work with a simpler function instead. (a) Suppose \(g(x)=\sqrt{f(x)},\) where \(f(x) \geq 0\) for all \(x\) . Explain why the local minima and maxima of \(f\) and \(g\) occur at the same values of \(x .\) (b) Let \(g(x)\) be the distance between the point \((3,0)\) and the point \(\left(x, x^{2}\right)\) on the graph of the parabola \(y=x^{2}\) Express \(g\) as a function of \(x .\) (c) Find the minimum value of the function \(g\) that you found in part (b). Use the principle described in part (a) to simplify your work.

\(1-6\) Find \(f+g, f-g, f g,\) and \(f / g\) and their domains. $$ f(x)=\sqrt{9-x^{2}}, \quad g(x)=\sqrt{x^{2}-4} $$

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Advertising The effectiveness of a television com- mercial depends on how many times a viewer watches it. After some experiments an advertising agency found that if the effectiveness \(E\) is measured on a scale of 0 to \(10,\) then $$ E(n)=\frac{2}{3} n-\frac{1}{90} n^{2} $$ where \(n\) is the number of times a viewer watches a given commercial. For a commercial to have maximum effectiveness, how many times should a viewer watch it?

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