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Chapter 3: Problem 40

33鈥�48 ? Sketch the graph of the function, not by plotting points, but by starting with the graph of a standard function and applying transformations. $$ y=2-\sqrt{x+1} $$

Short Answer

Expert verified
The graph is a horizontally shifted left half of an inverted square root, shifted up by 2 units.

Step by step solution

01

Identify the Base Function

The function we begin with is the square root function, which is given by \( y = \sqrt{x} \). This is our base function and will be the starting point for applying various transformations.
02

Apply the Horizontal Shift

The given function is \( y = 2 - \sqrt{x+1} \). The term \( x+1 \) indicates a horizontal shift. To understand how this affects the graph, realize that it shifts the graph of \( \sqrt{x} \) to the left by 1 unit. This change directs us to adjust the way \( x \) is interpreted in the modified function.
03

Apply the Vertical Reflection and Scaling

The presence of the negative sign in front of \( \sqrt{x+1} \) in \( y = 2 - \sqrt{x+1} \) implies reflecting the graph of the shifted function \( \sqrt{x+1} \) across the x-axis. Thus, we transform \( \sqrt{x+1} \) to \( -\sqrt{x+1} \).
04

Apply the Vertical Shift

Finally, the term \( 2 - \sqrt{x+1} \) causes a vertical shift up by 2 units. This is evident from adding 2 to the function \( -\sqrt{x+1} \). Every point on the graph is moved 2 units upwards, completing the transformation.
05

Sketch the Graph

Combine all the transformations step-by-step on the graph of \( \sqrt{x} \): shift left by 1 unit, reflect across the x-axis, then shift up by 2 units. The resulting curve passes through the point (0, 2), descends leftwards, and resembles an inverted half-parabola.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Square Root Function
The square root function, denoted by \( y = \sqrt{x} \), is a fundamental mathematical function. Its graph is characterized by a gentle, upward slope starting from the origin, (0,0). The curve only exists in the first quadrant of the Cartesian plane because you can鈥檛 take the square root of a negative number in the realm of real numbers. This graph will serve as our base or "parent" function for transformations.
  • The domain of \( y = \sqrt{x} \) is \( x \geq 0 \).
  • The range is \( y \geq 0 \).
The function increases gradually and shows a direct relationship between \( x \) and \( y \) values鈥攎eaning as \( x \) increases, \( y \) does too, but at a decreasing rate. This concave down behavior allows for applying transformations like shifts and reflections.
Applying a Horizontal Shift
Horizontal shifts involve moving the graph left or right on the Cartesian plane. In the equation \( y = 2 - \sqrt{x+1} \), the term \( x+1 \) indicates a horizontal shift. We interpret this as the graph of \( \sqrt{x} \) being shifted to the left by 1 unit. Intuitively, you can think of it as preparing for \( x \), thus modifying the input before the square root operation.
  • A positive inside the function, like \( x+1 \), shifts the graph left.
  • A negative value, such as \( x-1 \), would shift it right.
This shift affects the starting point of the square root graph. Instead of beginning at \( (0,0) \), the transformation causes it to start at \( (-1,0) \).
Understanding Vertical Reflection
A vertical reflection changes the direction in which the graph opens. For the square root function, \( y = -\sqrt{x+1} \), the presence of a negative sign outside implies a reflection across the x-axis. This means the range of the function will change in direction: instead of going upwards, it will flip, moving downwards.
  • The graph, originally increasing upwards, will now appear as it descends from its starting point.
  • This does not affect the domain.
Therefore, every point on the graph of \( \sqrt{x+1} \) is reflected vertically, converting what was a rising curve into a falling one.
Executing a Vertical Shift
A vertical shift involves moving the graph up or down on the plane. In the function \( y = 2 - \sqrt{x+1} \), the +2 signals a vertical shift upwards. This means that every point on the graph of \( -\sqrt{x+1} \) is lifted by 2 units.
  • If the number outside is positive, the shift is upwards.
  • If it's negative, the graph moves down.
The transformation results in starting the curve at \( (0,2) \). The overall shape is similar to an inverted version of \( \sqrt{x} \), albeit translated into a new position.

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