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33–48 ? Sketch the graph of the function, not by plotting points, but by starting with the graph of a standard function and applying transformations. $$ f(x)=x^{3}+2 $$

Short Answer

Expert verified
Shift the graph of \(x^3\) upwards by 2 units to obtain \(f(x) = x^3 + 2\).

Step by step solution

01

Identify the Base Function

The given function is \(f(x) = x^3 + 2\). The base function here is \(g(x) = x^3\). This is a standard cubic function.
02

Understand the Transformation

The function \(f(x) = x^3 + 2\) represents a vertical shift of the base function \(g(x) = x^3\). The term '+2' indicates that the graph of \(g(x) = x^3\) should be moved up by 2 units.
03

Sketch the Base Graph

First, visualize or sketch the standard cubic graph \(g(x) = x^3\). This graph passes through the origin and its shape is symmetric around the origin with an inflection point also at the origin.
04

Apply the Vertical Shift

Take the graph of \(g(x) = x^3\) and shift it vertically upwards by 2 units. This means every point on \(g(x)\) will move 2 units higher on the y-axis. For example, the origin (0,0) on \(g(x)\) will become (0,2) on \(f(x)\).
05

Draw the Transformed Graph

Using the transformations identified, sketch the new graph. The shape remains similar to a cubic function but it starts from (0,2) instead of (0,0) and shifts up accordingly.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cubic Functions
Cubic functions are an important type of polynomial function that has the form \( f(x) = ax^3 + bx^2 + cx + d \). The simplest cubic function is \( f(x) = x^3 \). This base function has a distinct "S"-shaped curve and is symmetric around its inflection point, located at the origin (0,0).
\( x^3 \) is continuously increasing, meaning no matter where it is evaluated, it moves upwards. This big-picture behavior is crucial when considering transformations.
Understanding cubic functions is fundamental when learning about graph transformations because they help in predicting how the function's shape will adjust when transformed with additional constants.
Vertical Shift
A vertical shift is a type of transformation that moves the entire graph of a function up or down. In the function \( f(x) = x^3 + 2 \), the term '+2' signifies a vertical shift. This means you will move the graph of \( x^3 \) upwards by 2 units.
It's important to note that vertical shifts do not change the shape of the graph; they only translate it along the y-axis. Thus, each point on the original graph \( g(x) = x^3 \) will be moved two units higher to form the new graph \( f(x) \).
To apply a vertical shift effectively, simply add or subtract the constant from the output (y-value) of every point on the graph of the base function.
Graph Sketching
Graph sketching involves drawing the curve of a function with just an understanding of its algebraic expression and transformations, rather than plotting specific points. Begin with the graph of the basic form, and then apply transformations step by step.
When sketching \( f(x) = x^3 + 2 \), start by drawing the graph of \( x^3 \), which lies at the origin and has the characteristic "S" shape.
Afterward, apply the transformations recognized during analysis. For the graph of \( x^3 + 2 \), shift every point upwards by 2 units. This simple shift retains the shape of the cubic graph but repositions it on the plane.
Sketching focuses on transformations which are crucial to understanding function behavior graphically.
Mathematical Transformations
Mathematical transformations refer to adjustments made to the base form of a function to produce a new graph.
They include translations (vertical and horizontal shifts), reflections, stretches, and compressions.
In transformations, the vertical shift as seen in \( f(x) = x^3 + 2 \) is among the simplest. By moving every point upwards by 2 units, it's easy to visualize how transformations impact a function.
Understanding these foundational transformations helps in graph analysis and tackling complex mathematical problems because they allow prediction of how a graph changes with alterations to the function's equation.
Through practice, these transformations can be recognized and sketched on the fly without extensive computation.

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