Chapter 3: Problem 20
If \(g(x)=x^{2}+4 x\) with \(x \geq-2,\) find \(g^{-1}(5)\)
Short Answer
Expert verified
The inverse value \( g^{-1}(5) \) is 1.
Step by step solution
01
Identify the function
The function given is \( g(x) = x^2 + 4x \) with \( x \geq -2 \). We are tasked with finding \( g^{-1}(5) \), which means we need to find \( x \) such that \( g(x) = 5 \).
02
Set up the equation
To find the value of \( x \) that satisfies \( g(x) = 5 \), we set the equation \( x^2 + 4x = 5 \). This becomes our equation to solve for \( x \).
03
Rearrange the equation
Rearrange \( x^2 + 4x = 5 \) to form a quadratic equation: \( x^2 + 4x - 5 = 0 \).
04
Apply the quadratic formula
Use the quadratic formula to solve for \( x \): \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), where \( a = 1 \), \( b = 4 \), and \( c = -5 \).
05
Calculate the discriminant
Compute the discriminant: \( b^2 - 4ac = 4^2 - 4(1)(-5) = 16 + 20 = 36 \).
06
Solve for x using the quadratic formula
Substitute the discriminant and other values into the quadratic formula: \( x = \frac{-4 \pm \sqrt{36}}{2} \). Simplify to \( x = \frac{-4 \pm 6}{2} \).
07
Determine potential x values
The possible solutions for \( x \) are \( x = \frac{2}{2} = 1 \) and \( x = \frac{-10}{2} = -5 \).
08
Check domain constraints
We are given that \( x \geq -2 \). Thus, \( x = -5 \) is not valid. The only valid solution is \( x = 1 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Equations
Understanding quadratic equations is an important step in solving many algebraic problems. A quadratic equation is a polynomial equation of the second degree, generally written in the form \(ax^2 + bx + c = 0\). Here, \(a\), \(b\), and \(c\) are constants, with \(a eq 0\). The equation can take various forms, but its defining feature is the \(x^2\) term.
The graph of a quadratic equation is a parabola. It opens upwards if \(a > 0\) and downwards if \(a < 0\). Solving a quadratic equation means finding the values of \(x\) that satisfy the equation, also known as the roots of the equation.
The graph of a quadratic equation is a parabola. It opens upwards if \(a > 0\) and downwards if \(a < 0\). Solving a quadratic equation means finding the values of \(x\) that satisfy the equation, also known as the roots of the equation.
- Quadratic equations can have zero, one, or two real roots.
- The nature of the roots depends on the discriminant \(b^2 - 4ac\).
Domain Constraints
Domain constraints are conditions that are put on the variable \(x\) within a function. They determine the set of permissible inputs for which the function is defined. Inverting a function, like finding \(g^{-1}(5)\), often requires evaluating these constraints.
In the given exercise, the function is defined as \(g(x) = x^2 + 4x\) with the restriction \(x \geq -2\). This means the function only considers values of \(x\) that are greater than or equal to \(-2\). Therefore, any solution to our equation must respect this constraint.
In the given exercise, the function is defined as \(g(x) = x^2 + 4x\) with the restriction \(x \geq -2\). This means the function only considers values of \(x\) that are greater than or equal to \(-2\). Therefore, any solution to our equation must respect this constraint.
- Domain constraints limit the valid solutions when finding inverse functions.
- Always verify solutions against domain conditions to ensure they are acceptable.
Quadratic Formula
The quadratic formula is a reliable method for solving any quadratic equation \(ax^2 + bx + c = 0\). The formula is:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]This formula calculates the possible values of \(x\) by substituting the coefficients \(a\), \(b\), and \(c\) from the equation.
The term \(b^2 - 4ac\) under the square root is called the discriminant. It determines the nature of the roots:
In our example, by using \(a = 1\), \(b = 4\), and \(c = -5\), we found that the discriminant is 36, which is positive. This indicates two possible real roots. After calculating, we checked which root falls within the domain constraint of \(x \geq -2\) to find the valid solution \(x = 1\).
The term \(b^2 - 4ac\) under the square root is called the discriminant. It determines the nature of the roots:
- If the discriminant is positive, the equation has two distinct real roots.
- If it is zero, there is one real root (or a repeated root).
- If negative, there are no real roots, only complex roots.
In our example, by using \(a = 1\), \(b = 4\), and \(c = -5\), we found that the discriminant is 36, which is positive. This indicates two possible real roots. After calculating, we checked which root falls within the domain constraint of \(x \geq -2\) to find the valid solution \(x = 1\).