Chapter 3: Problem 2
\(1-6\) Find \(f+g, f-g, f g,\) and \(f / g\) and their domains. $$ f(x)=x^{2}+2 x, \quad g(x)=3 x^{2}-1 $$
Short Answer
Expert verified
Sum: \(4x^2 + 2x - 1\), Difference: \(-2x^2 + 2x + 1\), Product: \(3x^4 + 6x^3 - x^2 - 2x\), Quotient: \(\frac{x^2 + 2x}{3x^2 - 1}\); Domains: All real numbers except for the quotient, which excludes \(\pm\frac{1}{\sqrt{3}}\).
Step by step solution
01
Finding the Sum
To find \((f+g)(x)\), add the functions \(f(x)\) and \(g(x)\). Thus, \((f+g)(x) = (x^2 + 2x) + (3x^2 - 1)\). Combine like terms: \((f+g)(x) = 4x^2 + 2x - 1\).
02
Finding the Domain of the Sum
For the domain of \((f+g)(x) = 4x^2 + 2x - 1\), since there are no restrictions for the variables in a polynomial, the domain is all real numbers \((-fty, fty)\).
03
Finding the Difference
To find \((f-g)(x)\), subtract \(g(x)\) from \(f(x)\). Thus, \((f-g)(x) = (x^2 + 2x) - (3x^2 - 1)\). Combine like terms: \((f-g)(x) = -2x^2 + 2x + 1\).
04
Finding the Domain of the Difference
The domain of \((f-g)(x) = -2x^2 + 2x + 1\), is also all real numbers \((-fty, fty)\) since it is a polynomial.
05
Finding the Product
To find \((f \, g)(x)\), multiply the functions \(f(x)\) and \(g(x)\). Thus, \((f \, g)(x) = (x^2 + 2x)(3x^2 - 1)\). Expand this to get \(3x^4 - x^2 + 6x^3 - 2x\).
06
Finding the Domain of the Product
The domain of \((f \, g)(x) = 3x^4 + 6x^3 - x^2 - 2x\) is all real numbers \((-fty, fty)\) because it is a polynomial.
07
Finding the Quotient
To find \((f/g)(x)\), divide \(f(x)\) by \(g(x)\). Thus, \( (f/g)(x) = \frac{x^2 + 2x}{3x^2 - 1} \).
08
Finding the Domain of the Quotient
The domain of \( (f/g)(x) \) is all real numbers except where the denominator is zero. Solve \(3x^2 - 1 = 0\) to find the restriction. \(x^2 = 1/3\), so \(x = \pm\frac{1}{\sqrt{3}}\). The domain is \((-fty, -\frac{1}{\sqrt{3}}) \cup (-\frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}) \cup (\frac{1}{\sqrt{3}}, fty)\).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Domain of a Function
The domain of a function is critical because it tells us all the possible input values (usually denoted as "x") that a function can have without encountering undefined expressions. Think of it as the set of all possible x-values that will allow the function to work without any issues.
For polynomials like \[f(x) = 4x^2 + 2x - 1\], there are no restrictions on x because polynomials are defined for all real numbers. Thus, their domain is \((-\infty, \infty)\).
This creates a restricted domain. In this case, x cannot be \(\pm\frac{1}{\sqrt{3}}\), so the domain excludes these x-values:
\[(-\infty, -\frac{1}{\sqrt{3}}) \cup (-\frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}) \cup (\frac{1}{\sqrt{3}}, \infty)\].
For polynomials like \[f(x) = 4x^2 + 2x - 1\], there are no restrictions on x because polynomials are defined for all real numbers. Thus, their domain is \((-\infty, \infty)\).
- No division by zero is involved.
- No even roots of negative numbers are present.
- All real numbers are included.
This creates a restricted domain. In this case, x cannot be \(\pm\frac{1}{\sqrt{3}}\), so the domain excludes these x-values:
\[(-\infty, -\frac{1}{\sqrt{3}}) \cup (-\frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}) \cup (\frac{1}{\sqrt{3}}, \infty)\].
Polynomial
Polynomials are powerful tools in mathematics. They are expressions involving variables raised to whole number exponents, combined using addition, subtraction, and multiplication.
For example, \[f(x) = 4x^2 + 2x - 1\] is a polynomial function where each term involves a varying power of x.
The beauty of polynomials includes:
For example, \[f(x) = 4x^2 + 2x - 1\] is a polynomial function where each term involves a varying power of x.
- The highest power of x indicates the degree of the polynomial.
- In \[f(x)\], the degree is 2.
- This often affects the shape and number of turning points on the graph.
The beauty of polynomials includes:
- They are continuous.
- They are smooth, without holes or breaks.
- They extend infinitely in both directions.
Rational Functions
Rational functions are another class of functions that involve the ratio of two polynomials. They have the form \(\frac{P(x)}{Q(x)}\), where both P(x) and Q(x) are polynomial functions.
Our example, \(\frac{x^2 + 2x}{3x^2 - 1}\), is a rational function.
The key feature of rational functions often revolves around their undefined points, usually at the values of x making the denominator zero. These points are values where the function "breaks" and often lead to vertical asymptotes in the graph.
Our example, \(\frac{x^2 + 2x}{3x^2 - 1}\), is a rational function.
The key feature of rational functions often revolves around their undefined points, usually at the values of x making the denominator zero. These points are values where the function "breaks" and often lead to vertical asymptotes in the graph.
- Rational functions can have horizontal or slant asymptotes.
- They can exhibit different behaviors and limitations compared to other function types.
- The domain is usually all real numbers except those causing division by zero.
- They are versatile in representing real-world problems where ratios naturally occur.