/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 80 77–80 ? Sketch the region give... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

77–80 ? Sketch the region given by the set. $$ \left\\{(x, y) | 2 x < x^{2}+y^{2} \leq 4\right\\} $$

Short Answer

Expert verified
The region is the set of points inside the circle \(x^2 + y^2 \leq 4\) and outside \((x-1)^2 + y^2 > 1\).

Step by step solution

01

Understanding the Set

We are given a region defined by the inequality \(2x < x^2 + y^2 \leq 4\). This set involves two conditions that create a region in the Cartesian plane. The inequalities describe the points \((x, y)\) that satisfy both conditions.
02

Rewriting the Inequalities

Firstly, rewrite the inequalities separately: \(2x < x^2 + y^2\) and \(x^2 + y^2 \leq 4\). The second inequality \(x^2 + y^2 \leq 4\) represents the area within a circle centered at the origin with radius 2.
03

Identifying the Circle

The inequality \(x^2 + y^2 \leq 4\) describes all points inside or on the boundary of a circle centered at the origin \((0,0)\) with a radius of 2. Draw this circle on the coordinate plane for visualization.
04

Analyzing the First Inequality

Focus now on the inequality \(2x < x^2 + y^2\). This can be rewritten as \(0 < x^2 - 2x + y^2\), which implies \((x-1)^2 + y^2 > 1\). This represents all points outside a circle centered at \((1,0)\) with a radius of 1.
05

Intersection of the Regions

The region of interest is where both conditions hold: inside the circle of radius 2 centered at the origin, and outside the circle of radius 1 centered at \((1,0)\). Shade this region on the sketch—it is the area within the larger circle but outside the smaller circle on the right.
06

Sketching the Region

On the coordinate plane, draw both circles. The region is where the shaded area of the larger circle does not overlap with the smaller circle. This intersection primarily lies on the left part of the larger circle, avoiding the small circle region.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Circle Equations
In mathematics, a circle's equation in the Cartesian plane is typically expressed in the form \( (x-h)^2 + (y-k)^2 = r^2 \), where \((h,k)\) is the center and \(r\) is the radius. This concise formula describes all points \((x, y)\) that lie exactly \(r\) units away from the center.

The region defined by \(x^2 + y^2 \leq 4\) is a circle centered at the origin with a radius of 2. Here, every point within and on the boundary of this circle satisfies the inequality. This is a fundamental concept in geometry and helps us understand how circles are represented and visualized in a plane.

Moreover, understanding inequalities with circle equations allows us to identify regions either inside \((x^2 + y^2 < r^2)\) or on the circle \((x^2 + y^2 = r^2)\). Such circle equations are essential for defining and visualizing bounded and unbounded regions on the Cartesian plane.
Cartesian Coordinates
Cartesian coordinates form the basis for plotting points in two dimensions. Every point on this plane is precisely determined by a pair of numerical coordinates, \((x, y)\), representing its horizontal and vertical distances from the origin.

The origin, located at \((0,0)\), is the center of the graph where the two axes, \(x\) (horizontal) and \(y\) (vertical), intersect perpendicularly. Understanding Cartesian coordinates is crucial because they allow us to visually represent mathematical concepts like equations and inequalities on a grid.

When dealing with the equation of a circle, say \(x^2 + y^2 \leq 4\), these coordinates make it possible to plot not just the shape, but also the entire region it encompasses. In this system, distances, slopes, and other geometric ideas become explicit and easy to manipulate, aiding greatly in mathematical problem-solving.
Region Sketching
Region sketching involves visually representing areas defined by mathematical conditions on a graph. This technique helps us better understand inequalities by drawing the regions they describe. For example, the set \(\{ (x, y) | 2x < x^2 + y^2 \leq 4 \}\) defines a ring-like area.

Here's how to proceed:
  • Draw both circles from the inequalities: the larger circle with a radius of 2 centered at the origin \((0,0)\) and the smaller circle with a radius of 1 centered at \((1,0)\).
  • The region of interest is inside the larger circle (where \(x^2 + y^2 \leq 4\)) but outside the smaller circle (where \((x-1)^2 + y^2 > 1\)).
This graphical representation helps to clearly identify the area which satisfies both conditions.

Sketching regions is a powerful visual tool in mathematics. It turns abstract algebraic expressions into visual diagrams, making complex problems more approachable and easier to solve, offering a deeper comprehension of areas defined by inequalities.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use a graphing device to graph the given family of lines in the same viewing rectangle. What do the lines have in common? \(y=2+m(x+3) \quad\) for \(m=0, \pm 0.5, \pm 1, \pm 2, \pm 6\)

Distances in a City \(\quad\) A city has streets that run north and south, and avenues that run east and west, all equally spaced. Streets and avenues are numbered sequentially, as shown in the figure. The walking distance between points \(A\) and \(B\) is 7 blocks \(-\) that is, 3 blocks east and 4 blocks north. To find the straight-line distances \(d,\) we must use the Distance Formula. (a) Find the straight-line distance (in blocks) between \(A\) and \(B\) . (b) Find the walking distance and the straight-line distance between the corner of 4 th St. and 2 nd Ave. and the corner of 11 th St. and 26 th Ave. (c) What must be true about the points \(P\) and \(Q\) if the walking distance between \(P\) and \(Q\) equals the straight-line distance between \(P\) and \(Q ?\)

Hooke's Law Hooke's Law states that the force needed to keep a spring stretched \(x\) units beyond its natural length is directly proportional to \(x .\) Here the constant of proportionality is called the spring constant. (a) Write Hooke’s Law as an equation. (b) If a spring has a natural length of 10 cm and a force of 40 N is required to maintain the spring stretched to a length of 15 cm, find the spring constant. (c) What force is needed to keep the spring stretched to a length of 14 cm?

Plot the points \(P(-2,1)\) and \(Q(12,-1) .\) Which (if either) of the points \(A(5,-7)\) and \(B(6,7)\) lies on the perpendicular bisector of the segment \(P Q ?\)

The manager of a furniture factory finds that it costs \(\$ 2200\) to manufacture 100 chairs in one day and \(\$ 4800\) to produce 300 chairs in one day. (a) Assuming that the relationship between cost and the number of chairs produced is linear, find an equation that expresses this relationship. Then graph the equation. (b) What is the slope of the line in part (a), and what does it represent? (c) What is the \(y\) -intercept of this line, and what does it represent?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.