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\(7-14\) A pair of points is graphed. (a) Plot the points in a coordinate plane. (b) Find the distance between them. (c) Find the midpoint of the segment that joins them. $$ (-2,5),(10,0) $$

Short Answer

Expert verified
The distance is 13, and the midpoint is (4, 2.5).

Step by step solution

01

Plot the Points

Start by plotting the two given points on the coordinate plane. The first point is \((-2, 5)\) and the second point is \((10, 0)\). To plot these points, move left 2 units and up 5 units for the first point, and right 10 units with no upward movement for the second point.
02

Use the Distance Formula

To find the distance between the two points, use the distance formula: \[d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\]Substituting the given points \((-2, 5)\) and \((10, 0)\), we have:\[d = \sqrt{(10 - (-2))^2 + (0 - 5)^2}\]\[d = \sqrt{(10 + 2)^2 + (-5)^2}\]\[d = \sqrt{12^2 + 25}\]\[d = \sqrt{144 + 25}\]\[d = \sqrt{169}\]\[d = 13\]
03

Use the Midpoint Formula

Find the midpoint using the midpoint formula:\[M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)\]Substitute \((-2, 5)\) and \((10, 0)\) into the formula:\[M = \left( \frac{-2 + 10}{2}, \frac{5 + 0}{2} \right)\]\[M = \left( \frac{8}{2}, \frac{5}{2} \right)\]\[M = (4, 2.5)\]Thus, the midpoint is \((4, 2.5)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Distance Formula
The distance formula is a handy tool for finding the distance between two points on a coordinate plane. This formula is derived from the Pythagorean theorem and can be used to calculate the straight-line distance, often called as "Euclidean distance."

To compute the distance, you first need the coordinates of both points. Consider the points are
  • First point: \( (x_1, y_1) \)
  • Second point: \( (x_2, y_2) \)
The distance formula is then written as: \[d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\] Plug the coordinates into the formula to calculate the distance.

Let's say the coordinates given are \((-2, 5)\) and \((10, 0)\). Use the formula:
  • \(d = \sqrt{(10 - (-2))^2 + (0 - 5)^2} \)
  • \(d = \sqrt{12^2 + (-5)^2} \)
  • \(d = \sqrt{144 + 25} \)
  • \(d = \sqrt{169} = 13 \)
Thus, the distance between the two points is 13 units. This method provides a clear way to determine how far apart the points are on a grid.
Midpoint Formula
The midpoint formula helps to find the exact middle point between two given points on the coordinate plane. The midpoint formula gives you the average position of the two endpoints.

To find the midpoint, use the coordinates of the endpoints. Assume these points are:
  • First point: \( (x_1, y_1) \)
  • Second point: \( (x_2, y_2) \)
The midpoint formula is expressed as: \[M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)\] You substitute your coordinates in to find the midpoint.

For points \((-2, 5)\) and \((10, 0)\), calculation proceeds as follows:
  • \(M = \left( \frac{-2 + 10}{2}, \frac{5 + 0}{2} \right)\)
  • \(M = \left( \frac{8}{2}, \frac{5}{2} \right)\)
  • \(M = (4, 2.5) \)
Thus, the midpoint is \((4, 2.5)\), dividing the segment equally into two halves. This point represents the middle of the segment joining the two coordinates.
Plotting Points on a Coordinate Plane
Plotting points on a coordinate plane is the fundamental step in understanding how to visually represent data. The coordinate plane is a two-dimensional surface formed by the intersection of a horizontal line known as the x-axis and a vertical line called the y-axis. These axes divide the plane into four quadrants.

To plot a point, you'll need an ordered pair like this:
  • Point: \( (x, y) \)
Here,
  • \(x\) is the horizontal position and \(y\) is the vertical position.
For example, to plot the point \((-2, 5)\), start at the origin \((0, 0)\), move 2 units left on the x-axis, and then move up 5 units on the y-axis.
For \((10, 0)\), start again at the origin, move to the right 10 units on the x-axis, as there's no movement on the y-axis.

Plotting these points accurately is necessary for applying further tools like the distance and midpoint formulas. It lays the groundwork for solving problems in coordinate geometry.

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Most popular questions from this chapter

Distances in a City \(\quad\) A city has streets that run north and south, and avenues that run east and west, all equally spaced. Streets and avenues are numbered sequentially, as shown in the figure. The walking distance between points \(A\) and \(B\) is 7 blocks \(-\) that is, 3 blocks east and 4 blocks north. To find the straight-line distances \(d,\) we must use the Distance Formula. (a) Find the straight-line distance (in blocks) between \(A\) and \(B\) . (b) Find the walking distance and the straight-line distance between the corner of 4 th St. and 2 nd Ave. and the corner of 11 th St. and 26 th Ave. (c) What must be true about the points \(P\) and \(Q\) if the walking distance between \(P\) and \(Q\) equals the straight-line distance between \(P\) and \(Q ?\)

Show that the points \(A(-2,9), B(4,6), C(1,0),\) and \(D(-5,3)\) are the vertices of a square.

Find the point that is one-fourth of the distance from the point \(P(-1,3)\) to the point \(Q(7,5)\) along the segment \(P Q\) .

Find the slope and \(y\)-intercept of the line and draw its graph. \(-3 x-5 y+30=0\)

Boyle’s Law The pressure P of a sample of gas is directly proportional to the temperature T and inversely proportional to the volume V. (a) Write an equation that expresses this variation. (b) Find the constant of proportionality if 100 L of gas exerts a pressure of 33.2 kPa at a temperature of 400 K (absolute temperature measured on the Kelvin scale). (c) If the temperature is increased to 500 K and the volume is decreased to 80 L, what is the pressure of the gas?

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