Chapter 2: Problem 36
19–44 ? Make a table of values and sketch the graph of the equation. Find the x- and y-intercepts and test for symmetry. $$ y=-\sqrt{4-x^{2}} $$
Short Answer
Expert verified
The graph is a semi-circle in the lower half-plane, x-intercepts are (-2, 0) and (2, 0), y-intercept is (0, -2), and it's symmetric about the y-axis.
Step by step solution
01
Identify the Domain
To ensure that the expression under the square root is non-negative, we need to satisfy the inequality \(4 - x^2 \geq 0\). This implies \(-2 \leq x \leq 2\). Therefore, the domain of \(y = -\sqrt{4-x^2}\) is \([-2, 2]\).
02
Create a Table of Values
Choose a set of x-values within the domain \([-2, 2]\), calculate corresponding y-values using the equation. For example: - If \(x = -2\), \(y = -\sqrt{4 - (-2)^2} = -\sqrt{0} = 0\)- If \(x = 0\), \(y = -\sqrt{4 - 0^2} = -2\)- If \(x = 2\), \(y = -\sqrt{4 - 2^2} = 0\)Construct a table listing these x and y values.
03
Sketch the Graph
Plot the points from the table on a coordinate plane. Connect the points with a smooth curve. The graph is expected to be a semi-circle in the lower half of the plane, with endpoints at \((-2, 0)\) and \((2, 0)\) and the lowest point at \((0, -2)\).
04
Find the Intercepts
To find the y-intercept, set \(x = 0\): \[ y = -\sqrt{4 - 0^2} = -2 \]So, the y-intercept is \((0, -2)\).To find x-intercepts, set \(y = 0\): \[ 0 = -\sqrt{4 - x^2} \Rightarrow \sqrt{4 - x^2} = 0 \Rightarrow 4 - x^2 = 0 \Rightarrow x = \pm 2 \]So, the x-intercepts are \((-2, 0)\) and \((2, 0)\).
05
Test for Symmetry
1. **Symmetry with respect to the y-axis**: If \(y = -\sqrt{4-x^2}\), replacing \(x\) with \(-x\) gives the same equation, indicating symmetry about the y-axis.2. **Symmetry with respect to the x-axis**: Not possible as y is negative.3. **Symmetry with respect to the origin**: Neither possible, as replacing both \(x\) and \(y\) with negatives gives a different equation.Thus, this graph is symmetric only about the y-axis.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Domain of a Function
The domain of a function consists of all the input values (or x-values) for which a function is defined. In simpler terms, it's the set of x-values that you can plug into the equation without causing any mathematical mishaps, like division by zero or square roots of negative numbers. For our equation, \( y = -\sqrt{4-x^2} \), we need to be cautious about the square root.
Square roots are defined for non-negative numbers only, meaning the expression inside the square root, \( 4-x^2 \), must be greater than or equal to zero.
- Solve the inequality \( 4-x^2 \geq 0 \): - Rearrange the inequality to \( -x^2 \geq -4 \) - Flip the inequality sign (since we divide by a negative number) to get \( x^2 \leq 4 \) - Find the values of \( x \) that satisfy this, resulting in \( -2 \leq x \leq 2 \) Thus, the domain of our function is the interval \( [-2, 2] \). This means you can plug any number between -2 and 2 into the function without running into problems.
Square roots are defined for non-negative numbers only, meaning the expression inside the square root, \( 4-x^2 \), must be greater than or equal to zero.
- Solve the inequality \( 4-x^2 \geq 0 \): - Rearrange the inequality to \( -x^2 \geq -4 \) - Flip the inequality sign (since we divide by a negative number) to get \( x^2 \leq 4 \) - Find the values of \( x \) that satisfy this, resulting in \( -2 \leq x \leq 2 \) Thus, the domain of our function is the interval \( [-2, 2] \). This means you can plug any number between -2 and 2 into the function without running into problems.
X- and Y-Intercepts
The intercepts of a graph are the points where the graph crosses the axes.These points give insight into the behavior and position of a graph relative to the axis. - **Y-Intercept**: - This is where the graph crosses the y-axis. - To find the y-intercept, we set \( x = 0 \) and solve for \( y \). - Substituting, we get: \( y = -\sqrt{4 - 0^2} = -2 \). - Therefore, the y-intercept is at the point \( (0, -2) \).- **X-Intercepts**: - These are points where the graph crosses the x-axis. - We'll find these by setting \( y = 0 \) and solving for \( x \). - So, \( 0 = -\sqrt{4 - x^2} \) leading to \( \sqrt{4 - x^2} = 0 \). - Solving gives \( 4 - x^2 = 0 \) or \( x^2 = 4 \), hence, \( x = \pm 2 \). - The x-intercepts are \( (-2, 0) \) and \( (2, 0) \).These intercepts help in sketching the general layout of the graph on the coordinate plane.
Symmetry in Graphs
Symmetry in graphs provides a shortcut to understanding graph behavior without plotting numerous points. A graph can show three types of symmetry: with respect to the y-axis, x-axis, or the origin.
For our function, \(y = -\sqrt{4-x^2}\), we will test these symmetries:
For our function, \(y = -\sqrt{4-x^2}\), we will test these symmetries:
- **Y-axis Symmetry**: If replacing \( x \) with \( -x \) in the function gives us the same equation, the graph is symmetric with respect to the y-axis. For our equation, substituting \(-x\) gives \(y = -\sqrt{4-(-x)^2}\), which simplifies back to \(y = -\sqrt{4-x^2}\). Thus, the graph is symmetric about the y-axis.
- **X-axis Symmetry**: A graph is symmetric about the x-axis if replacing \( y \) with \( -y \) results in the same equation, but this cannot hold for \(y = -\sqrt{4-x^2}\) since all \( y \) values would become positive.
- **Origin Symmetry**: Checking for origin symmetry involves replacing both \( x \) and \( y \) with \(-x\) and \(-y\). In our case, this does not yield the original equation, ruling out origin symmetry.