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Eight boys and 12 girls are arranged in a row. What is the probability that all the boys will be standing at one end of the row and all the girls at the other end?

Short Answer

Expert verified
The probability is very small, approximately 0.000000000008.

Step by step solution

01

Identify Total Arrangements

First, calculate the total number of ways to arrange 20 children (8 boys and 12 girls) in a single row. Total arrangements can be found by permuting these 20 children, which is given by the factorial of 20:\[ 20! \]
02

Calculate Arrangements with Boys at One End

Next, consider the arrangement where all 8 boys are standing at one end and all 12 girls are at the other end. There are two possible configurations: boys on the left and girls on the right or girls on the left and boys on the right.For both configurations, boys and girls need to be arranged among themselves, which gives:- The boys' arrangement: \(8!\)- The girls' arrangement: \(12!\)Therefore, the number of favorable arrangements is:\[ 2 \times 8! \times 12! \]
03

Compute the Probability

The probability that all boys will be at one end of the row and all the girls at the other, is the ratio of favorable outcomes to the total outcomes:\[\text{Probability} = \frac{2 \times 8! \times 12!}{20!}\]
04

Simplify the Expression

To find the probability, simplify the expression further by calculating the factorials:- \(8! = 40,320\)- \(12! = 479,001,600\)- \(20! = 2,432,902,008,176,640,000\)Substitute these values into the probability expression:\[\text{Probability} = \frac{2 \times 40,320 \times 479,001,600}{2,432,902,008,176,640,000}\]This results in a very small probability.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factorial
A factorial is a mathematical concept that plays a key role in probability and combinatorics. It is denoted by an exclamation mark (!). The factorial of a number, say \( n \), is the product of all positive integers up to \( n \). For example, \( 5! \) (read as "five factorial") is equal to \( 5 \times 4 \times 3 \times 2 \times 1 = 120 \).

Factorials are fundamental when calculating permutations and combinations because they represent the total number of ways to arrange a set number of items. In the context of our exercise, \( 20! \) is used to find the total possible arrangements of 20 children, depicting how crucial the concept of factorial is in determining probabilities.
Permutations
Permutations relate to the arrangement of objects in a specific order. When we find permutations, the order in which we place the items is significant. This concept is vital in probability when each sequence or arrangement is distinct.

A permutation is represented using factorials. For a group of \( n \) items, the number of permutations is \( n! \). If you have a subset of items, say \( r \) items from \( n \), the permutation is calculated as \( \frac{n!}{(n-r)!} \).

In our exercise, we calculate permutations to determine the ways boys and girls can be arranged separately, which involves \( 8! \) for boys and \( 12! \) for girls. Each group must be ordered internally before being considered together, underscoring the importance of permutations.
Arrangements
Arrangements describe how items can be placed in an orderly sequence. Similar to permutations, arrangements also consider the position of each item. However, arrangements might refer to scenarios where some elements have conditions or restrictions on their positioning. In the exercise, the arrangement of boys at one end and girls at the other illustrates a specific constraint-dependent arrangement.

  • First, arrange all boys together and all girls together.
  • Next, consider two positional options: boys on the left and girls on the right, or vice versa.

By exploring these options, the arrangements become restricted rather than general, demonstrating how specific conditions alter the concept of arrangement in combinatorial problems.
Combinatorics
Combinatorics is the field of mathematics that studies the counting, arrangement, and combination of elements within a set. It provides the tools to calculate probability, arrange sequences, and examine how different choices can be made.

Key components in combinatorics include:
  • Factorials: Used to find the number of ways elements can be arranged.
  • Permutations: Determine sequences where order matters.
  • Combinations: Calculate groupings where order is not important.

In our problem, combinatorics helps us understand the total number of possible arrangements of the children and the specific arrangements where gender groupings are placed at opposite ends. Remember, combinatorics, through its various principles, underpins much of probability theory, offering clarity on how scenarios are configured and analyzed.

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Most popular questions from this chapter

Why is \(\left(\begin{array}{c}{n} \\ {r}\end{array}\right)\) the Same as \(C(n, r) ?\) This exercise explains why the binomial coefficients \(\left(\begin{array}{c}{n} \\ {r}\end{array}\right)\) that appear in the expansion of \((x+y)^{n}\) are the same as \(C(n, r),\) the number of ways of choosing \(r\) objects from \(n\) objects. First, note that expanding a binomial using only the Distributive Property gives $$\begin{aligned}(x+y)^{2} &=(x+y)(x+y) \\ &=(x+y) x+(x+y) y \\ &=x x+x y+y x+y y \end{aligned}$$ $$\begin{aligned}(x+y)^{3}=&(x+y)(x x+x y+y x+y y) \\\=& x x+x x y+x y x+x y y+y x x \\ &+y x y+y y x+y y y \end{aligned}$$ (a) Expand \((x+y)^{5}\) using only the Distributive Property. (b) Write all the terms that represent \(x^{2} y^{3}\) together. These are all the terms that contain two \(x^{\prime}\) s and three \(y^{\prime}\) s. (c) Note that two \(x^{\prime}\) s appear in all possible positions. Conclude that the number of terms that represent \(x^{2} y^{3}\) is \(C(5,2) .\) (d) In general, explain why \(\left(\begin{array}{c}{n} \\\ {r}\end{array}\right)\) in the Binomial Theorem is the same as \(C(n, r) .\)

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55–75 Solve the problem using the appropriate counting principle(s). Seating Arrangements In how many ways can four men and four women be seated in a row of eight seats for each of the following arrangements? (a) The women are to be seated together. (b) The men and women are to be seated alternately by gender.

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