/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 61 Theater Seating An architect des... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Theater Seating An architect designs a theater with 15 seats in the first row, 18 in the second, 21 in the third, and so on. If the theater is to have a seating capacity of \(870,\) how many rows must the architect use in his design?

Short Answer

Expert verified
The architect must design 20 rows for the theater.

Step by step solution

01

Identify the Pattern

The sequence of seat numbers in each row forms an arithmetic sequence: 15, 18, 21, ... This sequence has a first term \(a_1 = 15\) and a common difference \(d = 3\).
02

Arithmetic Sequence Formula

The number of seats \(a_n\) in the \(n\)-th row is given by the formula for the \(n\)-th term of an arithmetic sequence: \(a_n = a_1 + (n - 1) \times d\). Plugging in the values, we get: \(a_n = 15 + (n - 1) \times 3\).
03

Sum Formula for Arithmetic Series

The sum \(S_n\) of the first \(n\) terms of an arithmetic sequence is given by: \(S_n = \frac{n}{2} (a_1 + a_n)\). The goal is to find \(n\) such that \(S_n = 870\).
04

Express \(a_n\) in Terms of \(n\)

Substitute \(a_n = 15 + (n - 1) \times 3\) into the sum formula: \(S_n = \frac{n}{2} (15 + 15 + 3(n - 1))\).
05

Simplify and Solve for \(n\)

Simplifying, we get: \(S_n = \frac{n}{2} \times (30 + 3n - 3) = \frac{n}{2} \times (3n + 27)\). Set this equal to 870: \( \frac{n}{2} \times (3n + 27) = 870\).
06

Clear the Fraction

Multiply both sides by 2 to eliminate the fraction: \(n(3n + 27) = 1740\).
07

Expand and Rearrange

Expand the equation: \(3n^2 + 27n = 1740\) and then rearrange to form a quadratic equation: \(3n^2 + 27n - 1740 = 0\).
08

Solve the Quadratic Equation

Divide the whole equation by 3 to simplify: \(n^2 + 9n - 580 = 0\). Solve this quadratic using the quadratic formula \(n = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) where \(a = 1\), \(b = 9\), \(c = -580\).
09

Calculate Discriminant

Calculate the discriminant \(b^2 - 4ac = 9^2 - 4 \times 1 \times (-580) = 81 + 2320 = 2401\). Since the discriminant is positive, there are two real solutions.
10

Find Possible Values for \(n\)

Calculate \(n\) using the quadratic formula: \(n = \frac{-9 \pm \,\sqrt{2401}}{2}\). \(\sqrt{2401} = 49\), so the solutions are \(n = \frac{-9 + 49}{2} = 20\) and \(n = \frac{-9 - 49}{2} = -29\).
11

Select the Valid Solution

Since \(n\) must be a positive integer, the number of rows is \(n = 20\).
12

Verification

Substitute \(n=20\) back into the sum formula to verify: \(S_{20} = \frac{20}{2}(15 + 15 + 3(20-1)) = 10(30 + 57) = 870\). This confirms the solution is correct.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

arithmetic series
An arithmetic series is the sum of terms in an arithmetic sequence. An arithmetic sequence is a list of numbers with a constant difference between every two successive terms. For instance, in our theater problem, the sequence of seats is 15, 18, 21, and so on, with each term increasing by 3. The total sum of these terms, when they add up to the theater's seating capacity, forms an arithmetic series.

To find out how many rows the theater has, you need to determine the sum of the series up to the row where the total number of seats equals 870. This is where the sum formula comes into play. Understanding the arithmetic series is crucial because it helps in calculating the total using a straightforward formula, saving time from calculating each term separately.
quadratic equation
A quadratic equation is a type of polynomial equation of the form \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are constants and \( x \) represents an unknown variable. In the context of our problem, the goal was to determine how many rows were needed to reach the seating capacity of 870.

By rearranging our derived formula for the sum of the series, we eventually ended up with a quadratic equation: \( 3n^2 + 27n - 1740 = 0 \). To solve this, it was simplified to \( n^2 + 9n - 580 = 0 \). Solving a quadratic equation is essential when direct calculation isn't feasible, especially when dealing with large numbers or more complex sequences.
sum of arithmetic series
The sum of an arithmetic series can be calculated using the formula \( S_n = \frac{n}{2} (a_1 + a_n) \), where \( n \) is the number of terms, \( a_1 \) is the first term, and \( a_n \) is the last term of the series.

In solving our theater problem, we employed this formula to find \( n \), or the number of rows needed, by substituting known values. We expressed the last term (\( a_n \)) using the sequence formula \( a_n = a_1 + (n - 1) imes d \), where \( d \) is the common difference, lifting the task into a manageable calculation that converts into solving a manageable quadratic equation.
  • Set up the summed equation like \( S_n = 870 \) with the expression for \( a_n \).
  • Worked through it using known algebraic principles to solve the resulting quadratic.
Through this approach, finding the sum of arithmetic series becomes methodical, reducing complex summation into simple algebraic manipulations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An Annuity That Lasts Forever An annuity in perpetuity is one that continues forever. Such annuities are useful in setting up scholarship funds to ensure that the award continues. (a) Draw a time line (as in Example 1 ) to show that to set up an annuity in perpetuity of amount \(R\) per time period, the amount that must be invested now is $$ A_{p}=\frac{R}{1+i}+\frac{R}{(1+i)^{2}}+\frac{R}{(1+i)^{3}}+\cdots+\frac{R}{(1+i)^{n}}+\cdots $$ where \(i\) is the interest rate per time period. (b) Find the sum of the infinite series in part (a) to show that $$ A_{p}=\frac{R}{i} $$ (c) How much money must be invested now at 10\(\%\) per year, compounded annually, to provide an annuity in perpetuity of \(\$ 5000\) per year? The first payment is due in one year. (d) How much money must be invested now at 8\(\%\) per year, compounded quarterly, to provide an annuity in perpetuity of \(\$ 3000\) per year? The first payment is due in one year.

Financing a Car A woman wants to borrow \(\$ 12,000\) in order to buy a car. She wants to repay the loan by monthly installments for 4 years. If the interest rate on this loan is 10\(\frac{1}{2} \%\) per year, compounded monthly, what is the amount of each payment?

Annuity Find the amount of an annuity that consists of 10 annual payments of \(\$ 1000\) each into an account that pays 6\(\%\) interest per year.

Interest Rate Janet's payments on her \(\$ 12,500\) car are \(\$ 420\) a month for 3 years. Assuming that interest is compounded monthly, what interest rate is she paying on the car loan?

39 \(-42\) . Factor using the Binomial Theorem. $$ \begin{array}{l}{(x-1)^{5}+5(x-1)^{4}+10(x-1)^{3}+} \\\ {10(x-1)^{2}+5(x-1)+1}\end{array} $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.