Chapter 12: Problem 56
Write the sum without using sigma notation. $$\sum_{k=6}^{9} k(k+3)$$
Short Answer
Expert verified
The sum is 320.
Step by step solution
01
Analyze Sigma Notation
The sigma notation \( \sum_{k=6}^{9} k(k+3) \) represents the sum of the expression \( k(k+3) \) from \( k = 6 \) to \( k = 9 \). This means we need to substitute each integer from 6 to 9 into the expression \( k(k+3) \) and add the results.
02
Substitute and Expand Terms
Replace \( k \) with each integer value between 6 and 9 in the expression \( k(k+3) \). Calculate each term individually:- For \( k = 6 \): \( 6(6+3) = 6 \times 9 = 54 \)- For \( k = 7 \): \( 7(7+3) = 7 \times 10 = 70 \)- For \( k = 8 \): \( 8(8+3) = 8 \times 11 = 88 \)- For \( k = 9 \): \( 9(9+3) = 9 \times 12 = 108 \)
03
Add the Expanded Terms
Add up the expanded terms from the previous step:- First, add \( 54 + 70 \) to get \( 124 \).- Next, add \( 124 + 88 \) to get \( 212 \).- Finally, add \( 212 + 108 \) to get \( 320 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sigma Notation
Sigma notation is a concise and efficient way to represent the sum of a sequence of expressions. It uses the Greek letter sigma (\(\Sigma\)) to indicate the mathematical process of summation. The notation includes:
- An expression, which is a mathematical formula involving a variable.
- Limits of summation, which specify the starting and ending values for the variable.
- The variable of summation, usually denoted by a letter like \(k\).
Arithmetic Series
An arithmetic series is the result of summing the terms of an arithmetic sequence, where each term is obtained by adding a constant difference to the previous term. Arithmetic sequences are defined by their first term and the common difference between consecutive terms.
For example, consider the sequence: 6, 7, 8, 9. Here, each number is 1 more than the previous number, making 1 the common difference. However, in this exercise, we don't have a classic arithmetic sequence because of the function \(k(k+3)\).
Nonetheless, the arithmetic idea helps us clearly order our tasks. When we compute terms like \(6(6+3)\), \(7(7+3)\), etc., the increasing value of \(k\) ensures we compute these terms in a consistent manner. After calculating each, adding them results in the arithmetic series sum, a typical step in discrete mathematics.
For example, consider the sequence: 6, 7, 8, 9. Here, each number is 1 more than the previous number, making 1 the common difference. However, in this exercise, we don't have a classic arithmetic sequence because of the function \(k(k+3)\).
Nonetheless, the arithmetic idea helps us clearly order our tasks. When we compute terms like \(6(6+3)\), \(7(7+3)\), etc., the increasing value of \(k\) ensures we compute these terms in a consistent manner. After calculating each, adding them results in the arithmetic series sum, a typical step in discrete mathematics.
Summation
Summation involves the addition of a sequence of numbers; it’s a fundamental operation in mathematics. In the exercise, the task was to sum the values resulting from substituting integers 6 to 9 into the expression \(k(k+3)\).
To achieve this, the calculated terms were:\(54, 70, 88,\) and \(108\). These were found by:
To achieve this, the calculated terms were:\(54, 70, 88,\) and \(108\). These were found by:
- Substituting 6 into \(k(k+3)\) to get\(54\)
- Substituting 7 into \(k(k+3)\) to get \(70\)
- Substituting 8 into \(k(k+3)\) to get \(88\)
- Substituting 9 into \(k(k+3)\) to get \(108\)