Chapter 12: Problem 5
Find the first four terms and the 100th term of the sequence. \(a_{n}=\frac{(-1)^{n}}{n^{2}}\)
Short Answer
Expert verified
The first four terms are -1, 1/4, -1/9, 1/16; the 100th term is 1/10000.
Step by step solution
01
Understand the sequence formula
The given sequence is defined as \(a_{n}=\frac{(-1)^{n}}{n^{2}}\). This formula tells us that the \(n\)-th term of the sequence is determined by raising \(-1\) to the power of \(n\), which will alternate the sign of each term, and dividing by \(n^2\).
02
Find the first term
To find the first term \(a_1\), substitute \(n = 1\) into the sequence formula: \(a_1 = \frac{(-1)^{1}}{1^2} = \frac{-1}{1} = -1\).
03
Find the second term
To find the second term \(a_2\), substitute \(n = 2\) into the sequence formula: \(a_2 = \frac{(-1)^{2}}{2^2} = \frac{1}{4}\).
04
Find the third term
To find the third term \(a_3\), substitute \(n = 3\) into the sequence formula: \(a_3 = \frac{(-1)^{3}}{3^2} = \frac{-1}{9}\).
05
Find the fourth term
To find the fourth term \(a_4\), substitute \(n = 4\) into the sequence formula: \(a_4 = \frac{(-1)^{4}}{4^2} = \frac{1}{16}\).
06
Find the 100th term
To find the 100th term \(a_{100}\), substitute \(n = 100\) into the sequence formula: \(a_{100} = \frac{(-1)^{100}}{100^2} = \frac{1}{10000}\). Since \((-1)^{100} = 1\), the term is positive.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Alternating Series
An alternating series is a sequence where the signs of the terms alternate between positive and negative. This usually occurs by raising -1 to an odd or even power. In our sequence formula, \((-1)^n\), the value of \(n\) determines the sign of each term.
- If \(n\) is odd, then the term is negative because \((-1)^{ ext{odd}} = -1\).
- If \(n\) is even, then the term is positive because \((-1)^{ ext{even}} = 1\).
Sequence Formula
The sequence formula is the rule or expression that defines the terms of a sequence.
- For the given exercise, the sequence formula is \(a_{n} = \frac{(-1)^{n}}{n^2}\).
- This formula is a guide to determine the value of each term (\(a_n\)) based on its position in the sequence \(n\).
Exponents
Exponents are a shorthand way of expressing repeated multiplication of a number by itself. For example, \(n^2\) means "\(n\) multiplied by itself" (i.e., \(n \times n \)).In the sequence formula \(a_{n} = \frac{(-1)^{n}}{n^2}\), exponents perform two key functions:
- They affect the sign of the term: \((-1)^{n}\) powers switch the sign depending on whether \(n\) is odd or even.
- They diminish the magnitude of each term, as the square of \(n\), \(n^2\), grows quickly, causing the term to become very small as \(n\) becomes large.
Term Calculation
Term calculation is the process of determining the value of any specific term in a sequence using its sequence formula. In our example, to find a term \(a_n\), you substitute the given \(n\) into the sequence formula \(a_{n} = \frac{(-1)^{n}}{n^2}\).
- For the 1st term, plug \(n=1\), calculating to \(a_1 = \frac{-1}{1} = -1\).
- The 2nd term uses \(n=2\), leading to \(a_2 = \frac{1}{4}\).
- The approach remains constant regardless of \(n\).