Chapter 11: Problem 34
Use a graphing device to graph the conic. $$ x^{2}-4 y^{2}+4 x+8 y=0 $$
Short Answer
Expert verified
The conic is a hyperbola centered at (-2, 1). Graph it using a graphing device.
Step by step solution
01
Rearrange the Equation
Begin by rearranging the given equation to separate terms associated with the same variable:\[x^2 + 4x - 4y^2 + 8y = 0\]
02
Complete the Square for x Terms
For the terms involving x, complete the square:1. Rewrite: \(x^2 + 4x\).2. Half the coefficient of x: \(\frac{4}{2} = 2\).3. Square it: \(2^2 = 4\).4. Add and subtract this inside the equation: \(x^2 + 4x + 4 - 4\).The x terms now become:\[(x+2)^2 - 4\]
03
Complete the Square for y Terms
For the terms involving y, complete the square:1. Rewrite: \(-4(y^2 - 2y)\).2. Half the coefficient of y: \(\frac{-2}{2} = -1\).3. Square it: \((-1)^2 = 1\).4. Add and subtract inside the original equation: \(-4(y^2 - 2y + 1 - 1)\).The y terms become:\[-4(y-1)^2 + 4\]
04
Write the Equation in Standard Form
Combine the newly arranged terms from completing the square:\[(x+2)^2 - 4(y-1)^2 - 4 + 4 = 0\]Which simplifies to:\[(x+2)^2 - 4(y-1)^2 = 0\]
05
Recognize as a Conic Section
Rewrite the equation to standard form:\[(x+2)^2 = 4(y-1)^2\]Recognize this represents a hyperbola.
06
Graph the Conic Section
Using a graphing device, graph the hyperbola given by the equation:The graph shows a hyperbola centered at \((-2, 1)\) with directrices parallel to the y-axis.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Hyperbola
A hyperbola is a type of conic section that can be imagined as the path created by the intersection of a plane and two opposite-facing cones. It has two separate curves, known as branches, which appear as mirrored images along their axes. The general form of a hyperbolic equation is \[ \frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1 \] where
- \((h, k)\) represents the center of the hyperbola,
- \(a\) and \(b\) define the distances from the center to the vertices and co-vertices, respectively.
Completing the Square
Completing the square is an algebraic technique used to simplify quadratic expressions by converting them into a perfect square trinomial. This method is fundamental in obtaining the standard form of a conic section. It involves a few systematic steps:
- First, isolate the terms involving one variable, such as the \(x\) terms.
- Take half of the linear coefficient (the term with \(x\)), square it, and add and subtract this square within the equation.
Step-by-Step
- Divide \(4\) by \(2\), giving \(2\).
- Square \(2\) to get \(4\).
- Add and subtract \(4\) in the equation, transforming it to \((x + 2)^2 - 4\).
Standard Form of a Conic Section
Understanding the standard form of conic sections is crucial to accurately recognize and graph shapes like circles, ellipses, parabolas, and hyperbolas. Each conic has its own distinctive representation:
- Circles: \((x-h)^2 + (y-k)^2 = r^2\)
- Ellipses: \(\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1\)
- Parabolas: \(y = ax^2 + bx + c\)
- Hyperbolas: \(\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1\)