/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 34 Use a graphing device to graph t... [FREE SOLUTION] | 91Ó°ÊÓ

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Use a graphing device to graph the conic. $$ x^{2}-4 y^{2}+4 x+8 y=0 $$

Short Answer

Expert verified
The conic is a hyperbola centered at (-2, 1). Graph it using a graphing device.

Step by step solution

01

Rearrange the Equation

Begin by rearranging the given equation to separate terms associated with the same variable:\[x^2 + 4x - 4y^2 + 8y = 0\]
02

Complete the Square for x Terms

For the terms involving x, complete the square:1. Rewrite: \(x^2 + 4x\).2. Half the coefficient of x: \(\frac{4}{2} = 2\).3. Square it: \(2^2 = 4\).4. Add and subtract this inside the equation: \(x^2 + 4x + 4 - 4\).The x terms now become:\[(x+2)^2 - 4\]
03

Complete the Square for y Terms

For the terms involving y, complete the square:1. Rewrite: \(-4(y^2 - 2y)\).2. Half the coefficient of y: \(\frac{-2}{2} = -1\).3. Square it: \((-1)^2 = 1\).4. Add and subtract inside the original equation: \(-4(y^2 - 2y + 1 - 1)\).The y terms become:\[-4(y-1)^2 + 4\]
04

Write the Equation in Standard Form

Combine the newly arranged terms from completing the square:\[(x+2)^2 - 4(y-1)^2 - 4 + 4 = 0\]Which simplifies to:\[(x+2)^2 - 4(y-1)^2 = 0\]
05

Recognize as a Conic Section

Rewrite the equation to standard form:\[(x+2)^2 = 4(y-1)^2\]Recognize this represents a hyperbola.
06

Graph the Conic Section

Using a graphing device, graph the hyperbola given by the equation:The graph shows a hyperbola centered at \((-2, 1)\) with directrices parallel to the y-axis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hyperbola
A hyperbola is a type of conic section that can be imagined as the path created by the intersection of a plane and two opposite-facing cones. It has two separate curves, known as branches, which appear as mirrored images along their axes. The general form of a hyperbolic equation is \[ \frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1 \] where
  • \((h, k)\) represents the center of the hyperbola,
  • \(a\) and \(b\) define the distances from the center to the vertices and co-vertices, respectively.
The hyperbola in our example, \[ (x+2)^2 - 4(y-1)^2 = 0 \] was rearranged into its standard form, allowing for easier identification as a hyperbola. When graphed, the branches of a hyperbola open away from each other. The line through the center and perpendicular to the directrices is known as the transverse axis, while the conjugate axis is perpendicular to it. Hyperbolas are unique because they often describe phenomena in physics, such as satellite paths and certain reflective properties related to light and sound.
Completing the Square
Completing the square is an algebraic technique used to simplify quadratic expressions by converting them into a perfect square trinomial. This method is fundamental in obtaining the standard form of a conic section. It involves a few systematic steps:
  • First, isolate the terms involving one variable, such as the \(x\) terms.
  • Take half of the linear coefficient (the term with \(x\)), square it, and add and subtract this square within the equation.
For example, starting with the expression \(x^2 + 4x\), we:

Step-by-Step

  • Divide \(4\) by \(2\), giving \(2\).
  • Square \(2\) to get \(4\).
  • Add and subtract \(4\) in the equation, transforming it to \((x + 2)^2 - 4\).
A similar approach is taken with the \(y\)-terms. Completing the square is an invaluable tool in algebra for solving quadratics, recognizing conic sections like hyperbolas, and transforming equations into forms that are easier to analyze and graph.
Standard Form of a Conic Section
Understanding the standard form of conic sections is crucial to accurately recognize and graph shapes like circles, ellipses, parabolas, and hyperbolas. Each conic has its own distinctive representation:
  • Circles: \((x-h)^2 + (y-k)^2 = r^2\)
  • Ellipses: \(\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1\)
  • Parabolas: \(y = ax^2 + bx + c\)
  • Hyperbolas: \(\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1\)
For hyperbolas, the standard form helps illustrate not only the position and orientation of the hyperbola but also key features like its center \((h, k)\), its vertices, and its asymptotes. In the analyzed exercise, \[ (x+2)^2 = 4(y-1)^2 \] could be rearranged and interpreted into standard form, guiding us to identify its center at \((-2, 1)\). Converting equations to their standard form simplifies the graphing process and greatly aids in understanding the conic's properties.

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Most popular questions from this chapter

Find an equation for the ellipse that satisfies the given conditions. Length of major axis \(10,\) foci on \(x\) -axis, ellipse passes through the point \((\sqrt{5}, 2)\)

Find the vertices, foci, and eccentricity of the ellipse. Determine the lengths of the major and minor axes, and sketch the graph. $$ 4 x^{2}+25 y^{2}=100 $$

(a) Use a graphing device to sketch the top half (the portion in the first and second quadrants) of the family of ellipses \(x^{2}+k y^{2}=100\) for \(k=4,10,25,\) and \(50 .\) (b) What do the members of this family of ellipses have in common? How do they differ?

\begin{array}{l}{1-22 \text { a pair of parametric equations is given. }} \\\ {\text { (a) Sketch the curve represented by the parametric equations. }} \\\ {\text { (b) Find a rectangular-coordinate equation for the curve by }} \\\ {\text { eliminating the parameter. }}\end{array} $$ x=\tan t, \quad y=\cot t, \quad 0

Spiral Path of a Dog \(\mathrm{A}\) dog is tied to a circular tree trunk of radius 1 \(\mathrm{ft}\) by a long leash. He has managed to wrap the entire leash around the tree while playing in the yard, and finds himself at the point \((1,0)\) in the figure. Seeing a squirrel, he runs around the tree counterclockwise, keeping the leash taut while chasing the intruder. (a) Show that parametric equations for the dog's path (called an involute of a circle) are \(x=\cos \theta+\theta \sin \theta \quad y=\sin \theta-\theta \cos \theta\) \([\text {Hint: Note that the leash is always tangent to the tree, }\) \(\text { so } O T \text { is perpendicular to } T D .]\) (b) Graph the path of the dog for \(0 \leq \theta \leq 4 \pi\)

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