Chapter 11: Problem 21
(a) Use the discriminant to determine whether the graph of the equation is a parabola, an ellipse, or a hyperbola. (b) Use a rotation of axes to eliminate the \(x y\) -term. (c) Sketch the graph. $$\sqrt{3} x^{2}+3 x y=3$$
Short Answer
Expert verified
The graph represents a hyperbola.
Step by step solution
01
Identify the Equation
Rewrite the given equation \( \sqrt{3}x^2 + 3xy = 3 \) to compare it with the standard conic section equation \( Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0 \). Here, \( A = \sqrt{3}, B = 3, C = 0 \).
02
Calculate the Discriminant
The discriminant \(\Delta\) for a conic section is given by \(\Delta = B^2 - 4AC\). Substitute \(A, B,\) and \(C\) into the formula: \(\Delta = 3^2 - 4(\sqrt{3})(0) = 9\).
03
Determine the Type of Conic
The sign of \(\Delta\) determines the type of conic section. Since \(\Delta > 0\), this indicates a hyperbola.
04
Find Rotation Angle
To eliminate the \(xy\)-term, use the formula \(\cot(2\theta) = \frac{A-C}{B}\). With \(A = \sqrt{3}, B = 3, C = 0\), \(\cot(2\theta) = \frac{\sqrt{3} - 0}{3} = \frac{\sqrt{3}}{3}\).
05
Calculate \(\theta\)
Solve \(\cot(2\theta) = \frac{\sqrt{3}}{3}\) for \(2\theta\). Since \(2\theta\) must match a known cotangent value, choose \(2\theta = 30^\circ\), thus \(\theta = 15^\circ\).
06
Transform the Coordinates
Use the rotation formulas: \(x = x'\cos\theta - y'\sin\theta\) and \(y = x'\sin\theta + y'\cos\theta\) to change variables. Substitute \(\theta = 15^\circ\).
07
Simplify the New Equation
Substitute the expressions from Step 6 into the original equation \(\sqrt{3}x^2 + 3xy = 3\) and simplify. The XY-term should now vanish, leaving a conic section equation in the \(x'y'\)-plane.
08
Sketch the Graph
Using the transformed equation, sketch the hyperbola in the \(x'y'\)-plane. Identify its key features such as asymptotes and vertex to draw an accurate shape of the hyperbola.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Discriminant in Conic Sections
The discriminant is a valuable tool for identifying the type of conic section an equation represents without graphing it. For a conic section equation in the form \[ Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0 \]the discriminant \( \Delta \) is calculated using the formula \[ \Delta = B^2 - 4AC \].
- If \( \Delta = 0 \), the conic is a parabola.
- If \( \Delta > 0 \), it is a hyperbola.
- If \( \Delta < 0 \), the conic is an ellipse.
Exploring Hyperbolas
A hyperbola is a type of conic section that forms when a plane intersects both nappes of a double cone. Hyperbolas are characterized by two distinct, mirror-image curves called branches.
- Unlike ellipses or parabolas, hyperbolas have a transverse and a conjugate axis.
- The transverse axis passes through the vertices of the hyperbola.
- Asymptotes: Two lines that the curve approaches but never touches. They determine the direction of the branches.
The Geometry of Rotation of Axes
Sometimes equations of conics include an \(xy\)-term, which can complicate identification and graphing. To simplify, we can use a rotation of axes.
- The goal of this rotation is often to eliminate the \(xy\)-term from the equation.
- For rotation, utilize the formula \( \cot(2\theta) = \frac{A-C}{B} \) to find the rotation angle \( \theta \).