Chapter 10: Problem 8
Find the inverse of the matrix if it exists. \(\left[\begin{array}{ll}{3} & {4} \\ {7} & {9}\end{array}\right]\)
Short Answer
Expert verified
The inverse of the matrix is \( \begin{pmatrix} -9 & 4 \\ 7 & -3 \end{pmatrix} \).
Step by step solution
01
Determine if the inverse exists
To find the inverse of a matrix, the matrix must be square, and its determinant must be non-zero. Calculate the determinant of the given matrix \( A = \begin{pmatrix} 3 & 4 \ 7 & 9 \end{pmatrix} \). The formula for the determinant of a 2x2 matrix \( \begin{pmatrix} a & b \ c & d \end{pmatrix} \) is \( ad - bc \).
02
Calculate the determinant
Apply the formula to the matrix \( A \):\[ \text{det}(A) = 3 \times 9 - 4 \times 7 = 27 - 28 = -1 \]. Since the determinant is \(-1\), which is not zero, the inverse exists.
03
Apply the formula for the inverse of a 2x2 matrix
For a 2x2 matrix \( \begin{pmatrix} a & b \ c & d \end{pmatrix} \), if the determinant is non-zero, the inverse can be found using the formula \[ A^{-1} = \frac{1}{ad-bc} \begin{pmatrix} d & -b \ -c & a \end{pmatrix} \].
04
Compute the inverse using the calculated determinant
Plug the values into the inverse formula for matrix \( A \):\[ A^{-1} = \frac{1}{-1} \begin{pmatrix} 9 & -4 \ -7 & 3 \end{pmatrix} = \begin{pmatrix} -9 & 4 \ 7 & -3 \end{pmatrix} \].
05
Write down the inverse matrix
The inverse of the matrix \( A \) is given by:\[ A^{-1} = \begin{pmatrix} -9 & 4 \ 7 & -3 \end{pmatrix} \]. This is the inverse of the original matrix.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Determinant of a Matrix
The determinant of a matrix is a special number that can be calculated from its elements. For a 2x2 matrix like the one in our exercise, calculating the determinant is straightforward. A 2x2 matrix has the form:
- \( \begin{pmatrix} a & b \ c & d \end{pmatrix} \)
- \( ad - bc \)
- \( \begin{pmatrix} 3 & 4 \ 7 & 9 \end{pmatrix} \)
- \( \text{det}(A) = 3 \times 9 - 4 \times 7 = 27 - 28 = -1 \)
2x2 Matrix
A 2x2 matrix is one of the simplest types of square matrices and is composed of four elements arranged in two rows and two columns. Here is how you represent it:
- \( \begin{pmatrix} a & b \ c & d \end{pmatrix} \)
- \( \begin{pmatrix} 3 & 4 \ 7 & 9 \end{pmatrix} \)
Inverse Formula for Matrices
The inverse of a matrix is like a reciprocal for numbers; when multiplied by the original matrix, it results in an identity matrix. The identity matrix is the equivalent of 1 in matrix terms. For a 2x2 matrix \( \begin{pmatrix} a & b \ c & d \end{pmatrix} \), the inverse can be calculated if the determinant is not zero.When the determinant \((ad - bc)\) is non-zero, use this formula:
- \( A^{-1} = \frac{1}{ad-bc} \begin{pmatrix} d & -b \ -c & a \end{pmatrix} \)
- \( A^{-1} = \begin{pmatrix} -9 & 4 \ 7 & -3 \end{pmatrix} \)