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Find the complete solution of the linear system, or show that it is inconsistent. $$ \left\\{\begin{aligned} y-2 z &=0 \\ 2 x+3 y &=2 \\\\-x-2 y+z &=-1 \end{aligned}\right. $$

Short Answer

Expert verified
The system is consistent with general solution: \(x = 1 - 3z\), \(y = 2z\), \(z = z\).

Step by step solution

01

Write the System of Equations

Write down the system of linear equations given in the problem, which is: \[y - 2z = 0 \ 2x + 3y = 2 \ -x - 2y + z = -1\]
02

Express y in terms of z

From the first equation \(y - 2z = 0\), solve for \(y\): \(y = 2z\).
03

Substitute y into the Second Equation

Substitute \(y = 2z\) into the second equation \(2x + 3y = 2\): \[2x + 3(2z) = 2\] This simplifies to \(2x + 6z = 2\).
04

Solve for x in Terms of z

Rearrange \(2x + 6z = 2\) to find \(x\): \[2x = 2 - 6z\] \[x = 1 - 3z\].
05

Substitute y and x into the Third Equation

Use \(x = 1 - 3z\) and \(y = 2z\) in the third equation \(-x - 2y + z = -1\):\[-(1 - 3z) - 2(2z) + z = -1\].
06

Simplify and Verify the Solution

Simplify the expression: \[-1 + 3z - 4z + z = -1\]which simplifies to \[-1 = -1\]. Since the equation simplifies to a true statement, the system is consistent.
07

Write the General Solution

Since the system is consistent, write the solution in terms of the parameter \(z\): \(\begin{align*}x &= 1 - 3z \y &= 2z \z &= z \end{align*}\). This represents the family of solutions based on the parameter \(z\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Systems of Equations
In mathematics, a system of equations is a collection of two or more equations with the same set of variables. The goal is to find the values of the variables that satisfy all the equations in the system simultaneously. When dealing with systems of linear equations, we are focused on equations that can be written in the form: \[ a_1x + b_1y + c_1z = d_1 \] These equations represent linear relationships in two or more variables. In practice, linear equations can represent lines, planes or hyperplanes, depending on the number of variables or dimensions involved. To solve a system of equations, there are several methods you can use:
  • Substitution method
  • Elimination method
  • Matrix methods such as Gaussian elimination
Each method has its own strengths and can be more or less convenient depending on the system you're dealing with.Solving systems of equations is a foundational skill in algebra, and it's crucial for understanding complex mathematical concepts later on.
Consistent Systems of Equations
A consistent system of equations is one in which there is at least one set of values for the unknowns that satisfies all the equations in the system. When a system of equations is consistent, it means that there is an intersection point or region where all equations meet or align. In the context of our linear system, consistency was determined when simplifying the third equation resulted in the true statement \(-1 = -1\). This means the equations don't contradict each other, indicating they can simultaneously be true for some values of the variables.A consistent system can have:
  • A unique solution: this occurs when there is exactly one set of values that satisfies all the equations.
  • Infinitely many solutions: this happens when the equations describe the same line, plane, or higher-dimensional object.
In our example, since the system simplifies to a consistent form, we have infinitely many solutions, expressed in a parameterized way.
Parametric Solution in Linear Systems
A parametric solution expresses the solutions of a system of equations in terms of one or more parameters. These parameters freely vary and can help describe the entire set of solutions. In linear systems, when there is more than one variable left free (not all variables can be solved for explicitly), parameters provide an elegant way to capture infinity of solutions.In our exercise, the solved system was described using a parameter \(z\) to provide the solution set:\[ \begin{align*} x &= 1 - 3z \ y &= 2z \ z &= z \end{align*} \]This means you can choose any real value for \(z\), and the equations for \(x\) and \(y\) will provide corresponding values satisfying all equations in the system.Parametric solutions are particularly useful:
  • In systems where the number of equations is less than the number of unknowns.
  • To fully describe the family of solutions in a consistent system with infinitely many solutions.
They offer a comprehensive way to represent solutions and give insight into the relationships between variables within the system.

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Most popular questions from this chapter

19–40 Graph the solution of the system of inequalities. Find the coordinates of all vertices, and determine whether the solution set is bounded. $$\left\\{\begin{aligned} x & \geq 0 \\ y & \geq 0 \\ y & \leq 4 \\ 2 x+y & \leq 8 \end{aligned}\right.$$

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(a) If three points lie on a line, what is the area of the "triangle" that they determine? Use the answer to this question, together with the determinant formula for the area of a triangle, to explain why the points \(\left(a_{1}, b_{1}\right)\) \(\left(a_{2}, b_{2}\right),\) and \(\left(a_{3}, b_{3}\right)\) are collinear if and only if $$ \left|\begin{array}{lll}{a_{1}} & {b_{1}} & {1} \\ {a_{2}} & {b_{2}} & {1} \\\ {a_{3}} & {b_{3}} & {1}\end{array}\right|=0 $$ (b) Use a determinant to check whether each set of points is collinear. Graph them to verify your answer. (i) \((-6,4),(2,10),(6,13)\) (ii) \((-5,10),(2,6),(15,-2)\)

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19–40 Graph the solution of the system of inequalities. Find the coordinates of all vertices, and determine whether the solution set is bounded. $$\left\\{\begin{aligned} x & \geq 0 \\ y & \geq 0 \\ x & \leq 5 \\ x+y & \leq 7 \end{aligned}\right.$$

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