Chapter 1: Problem 46
Evaluate the expression and write the result in the form \(a+b i .\) $$ \sqrt{\frac{1}{3}} \sqrt{-27} $$
Short Answer
Expert verified
The result is \( 0 + 3i \).
Step by step solution
01
Break the Expression
The expression given is \( \sqrt{\frac{1}{3}} \sqrt{-27} \). This can be rewritten as \( \sqrt{\frac{1}{3} \times -27} \), considering the property of square roots that \( \sqrt{a} \times \sqrt{b} = \sqrt{a \times b} \). We aim to evaluate this expression.
02
Simplify Inside the Square Root
Now simplify the product inside the square root: \( \frac{-27}{3} = -9 \). Hence, the expression simplifies to \( \sqrt{-9} \).
03
Identify the Imaginary Part
Recognize that \( \sqrt{-9} = \sqrt{9} \times \sqrt{-1} \). We know \( \sqrt{-1} = i \), where \( i \) is the imaginary unit. Thus, \( \sqrt{-9} = 3i \).
04
Write the Final Result
The result \( 3i \) is already in the form \( a + bi \) where \( a = 0 \) and \( b = 3 \). Therefore, the expression evaluates to \( 0 + 3i \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Imaginary Unit
In the realm of mathematics, the imaginary unit is a pivotal concept denoted by the symbol \( i \). It is defined by the property \( i^2 = -1 \). Understanding this concept is crucial because it allows us to handle square roots of negative numbers, which are not possible within the set of real numbers.
For instance, consider a number such as \( \sqrt{-1} \). In real numbers, this equation would have no solution. However, with the introduction of the imaginary unit \( i \), we can express \( \sqrt{-1} \) as \( i \). This means any square root involving negative numbers can be expressed using \( i \).
Practical use of the imaginary unit often involves multiplying by \( i \). For example, \( \sqrt{-9} \) can be expressed as \( \sqrt{9} \times \sqrt{-1} = 3 \times i = 3i \). This step is essential in converting complex expressions into a standard form. The imaginary unit helps expand our ability to work with numbers beyond the real number line, providing a foundation for complex numbers.
For instance, consider a number such as \( \sqrt{-1} \). In real numbers, this equation would have no solution. However, with the introduction of the imaginary unit \( i \), we can express \( \sqrt{-1} \) as \( i \). This means any square root involving negative numbers can be expressed using \( i \).
Practical use of the imaginary unit often involves multiplying by \( i \). For example, \( \sqrt{-9} \) can be expressed as \( \sqrt{9} \times \sqrt{-1} = 3 \times i = 3i \). This step is essential in converting complex expressions into a standard form. The imaginary unit helps expand our ability to work with numbers beyond the real number line, providing a foundation for complex numbers.
Square Root Properties
The properties of square roots are integral to simplifying and understanding expressions involving both real and complex numbers. A productive approach involves utilizing the identity \( \sqrt{a} \times \sqrt{b} = \sqrt{a \times b} \), which allows us to manipulate individual square root terms more flexibly.
For example, when given a compound square root expression like \( \sqrt{\frac{1}{3}} \times \sqrt{-27} \), you can apply these properties to combine the expressions under a single square root: \( \sqrt{\frac{1}{3} \times -27} \).
For example, when given a compound square root expression like \( \sqrt{\frac{1}{3}} \times \sqrt{-27} \), you can apply these properties to combine the expressions under a single square root: \( \sqrt{\frac{1}{3} \times -27} \).
- This simplifies the computation process significantly, allowing you to deal with a single expression instead of multiple roots.
- Once combined, find the product inside the square root, for instance, simplifying \( \frac{-27}{3} = -9 \).
- Then separate into real and imaginary parts, for example, \( \sqrt{-9} = \sqrt{9} \times \sqrt{-1} = 3i \).
Simplification of Expressions
Simplifying expressions is a critical skill in mathematics, especially when dealing with complex numbers. Simplification often involves breaking down a complex problem into manageable parts and applying known mathematical properties and operations.
Let's look at an example from the complex numbers domain: we have an expression \( \sqrt{\frac{1}{3}} \times \sqrt{-27} \). First, use the property \( \sqrt{a} \times \sqrt{b} = \sqrt{a \times b} \) to consolidate the expression under one square root: \( \sqrt{-9} \).
From there, it's helpful to separate the expression into real and imaginary components, here, recognizing that \( \sqrt{-9} = 3i \). Finally, express this in the form \( a + bi \).
Let's look at an example from the complex numbers domain: we have an expression \( \sqrt{\frac{1}{3}} \times \sqrt{-27} \). First, use the property \( \sqrt{a} \times \sqrt{b} = \sqrt{a \times b} \) to consolidate the expression under one square root: \( \sqrt{-9} \).
From there, it's helpful to separate the expression into real and imaginary components, here, recognizing that \( \sqrt{-9} = 3i \). Finally, express this in the form \( a + bi \).
- In this case, the expression reduces to \( 0 + 3i \).
- This result shows \( a = 0 \) and \( b = 3 \), confirming the expression is purely imaginary.