Chapter 1: Problem 32
Find all real solutions of the equation. \(2 x^{2}-8 x+4=0\)
Short Answer
Expert verified
The real solutions are \( x = 2 + \sqrt{2} \) and \( x = 2 - \sqrt{2} \).
Step by step solution
01
Identify the Quadratic Formula
The equation is a quadratic equation of the form \( ax^2 + bx + c = 0 \). Here, \( a = 2 \), \( b = -8 \), and \( c = 4 \). To find the roots of a quadratic equation, we can use the quadratic formula: \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
02
Calculate the Discriminant
The discriminant is part of the quadratic formula under the square root and is calculated as \( b^2 - 4ac \). Substitute the values:\[(b^2 - 4ac) = (-8)^2 - 4 \times 2 \times 4\]\[ = 64 - 32\]\[ = 32\]
03
Solve Using the Quadratic Formula
Substitute the values for \( a \), \( b \), and the discriminant back into the quadratic formula to find \( x \):\[x = \frac{-(-8) \pm \sqrt{32}}{2 \times 2}\]\[x = \frac{8 \pm \sqrt{32}}{4}\]Since \( \sqrt{32} = \sqrt{16 \cdot 2} = 4\sqrt{2} \), we have:\[x = \frac{8 \pm 4\sqrt{2}}{4}\]
04
Simplify the Solutions
Simplify the expression for each possible value of \( x \):\[x = \frac{8 + 4\sqrt{2}}{4} = 2 + \sqrt{2}\]\[x = \frac{8 - 4\sqrt{2}}{4} = 2 - \sqrt{2}\]So, the solutions are \( x = 2 + \sqrt{2} \) and \( x = 2 - \sqrt{2} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a powerful tool for finding the roots of any quadratic equation, which is an equation of the form \( ax^2 + bx + c = 0 \). Quadratic equations often have two solutions, which can be both real or complex numbers. When solving such equations, the quadratic formula allows you to directly calculate the values of \( x \) that make the equation true. The formula is as follows:
To apply the formula, you'll need to identify and plug in these coefficients correctly. It's crucial to carefully compute the values step-by-step to ensure accuracy, especially the discriminant under the square root.
- \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
To apply the formula, you'll need to identify and plug in these coefficients correctly. It's crucial to carefully compute the values step-by-step to ensure accuracy, especially the discriminant under the square root.
Discriminant
The discriminant is the part of the quadratic formula that lies under the square root: \( b^2 - 4ac \). It is a key factor in determining the nature of the roots of a quadratic equation. Calculating the discriminant helps us understand what kind of solutions the quadratic equation will yield. There are primarily three possibilities:
- If the discriminant is positive, the equation has two distinct real solutions.
- If it is zero, the equation has exactly one real solution, also known as a repeated root.
- If the discriminant is negative, the equation has no real solutions, but two complex solutions.
Real Solutions
Real solutions are the values of \( x \) that satisfy the quadratic equation and are real numbers, unlike complex solutions involving imaginary numbers. Identifying real solutions is a critical step, especially when dealing with physical or real-world problems. The determination of real solutions involves:
These solutions are not only real but distinct, illustrating how solving quadratic equations can yield specific and meaningful results.
- Calculating the discriminant to verify its sign.
- Using the quadratic formula to systematically solve for the exact values of \( x \).
These solutions are not only real but distinct, illustrating how solving quadratic equations can yield specific and meaningful results.