Chapter 1: Problem 31
Find all real solutions of the equation. \(x^{2}+3 x+1=0\)
Short Answer
Expert verified
The real solutions are \( x = \frac{-3 + \sqrt{5}}{2} \) and \( x = \frac{-3 - \sqrt{5}}{2} \).
Step by step solution
01
Identify the Components
The given equation is a quadratic equation of the form: \[ ax^2 + bx + c = 0 \]where \( a = 1 \), \( b = 3 \), and \( c = 1 \). Our goal is to find the values of \( x \) (the roots) that satisfy the equation.
02
Use the Quadratic Formula
The quadratic formula is:\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]Plugging in the values \( a = 1 \), \( b = 3 \), and \( c = 1 \), the formula becomes:\[ x = \frac{-3 \pm \sqrt{3^2 - 4 \cdot 1 \cdot 1}}{2 \cdot 1} \]
03
Calculate the Discriminant
The discriminant \( \Delta \) is the part under the square root in the quadratic formula:\[ \Delta = b^2 - 4ac = 3^2 - 4 \times 1 \times 1 = 9 - 4 \]\[ \Delta = 5 \]Since \( \Delta > 0 \), the quadratic equation has two distinct real solutions.
04
Substitute Values Into the Quadratic Formula
Now substitute \( \Delta = 5 \) into the quadratic formula:\[ x = \frac{-3 \pm \sqrt{5}}{2} \]
05
Simplify to Find Real Solutions
Simplify the expression to find the two real solutions:\[ x_1 = \frac{-3 + \sqrt{5}}{2} \]\[ x_2 = \frac{-3 - \sqrt{5}}{2} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a reliable method used to find the solutions of quadratic equations. A quadratic equation is one that can be arranged in the standard form: \[ ax^2 + bx + c = 0 \]Here, the coefficients \( a \), \( b \), and \( c \) represent known numbers, where \( a eq 0 \).
The quadratic formula itself is expressed as:\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]This formula provides a way to solve for \( x \) and find the roots of the quadratic equation. When using this formula, all you need to do is plug in the values for \( a \), \( b \), and \( c \) from your quadratic equation, and then perform the arithmetic operations one step at a time.
By following these steps systematically, you can find the exact solutions, or roots, for the quadratic equation.
The quadratic formula itself is expressed as:\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]This formula provides a way to solve for \( x \) and find the roots of the quadratic equation. When using this formula, all you need to do is plug in the values for \( a \), \( b \), and \( c \) from your quadratic equation, and then perform the arithmetic operations one step at a time.
By following these steps systematically, you can find the exact solutions, or roots, for the quadratic equation.
Discriminant
The discriminant is a key element in the quadratic formula and plays a crucial role in determining the nature of the roots of a quadratic equation. Mathematically, the discriminant \( \Delta \) is given by:\[ \Delta = b^2 - 4ac \]This component is housed under the square root in the quadratic formula.
Here's what the discriminant tells us:
Here's what the discriminant tells us:
- If \( \Delta > 0 \), there are two distinct real solutions (or roots).
- If \( \Delta = 0 \), there is exactly one real solution, sometimes called a repeated or double root.
- If \( \Delta < 0 \), there are no real solutions; instead, there are two complex solutions.
Real Solutions
Real solutions are the values of \( x \) that satisfy the quadratic equation and fall on the real number line. In the context of a quadratic equation, finding real solutions means determining the points where the parabola represented by the quadratic equation intersects the x-axis.
In our example of \( x^2 + 3x + 1 = 0 \), the discriminant was calculated to be positive as \( \Delta = 5 \), meaning the equation has two distinct real solutions.
The real solutions, therefore, can be calculated using the quadratic formula, resulting in:
In our example of \( x^2 + 3x + 1 = 0 \), the discriminant was calculated to be positive as \( \Delta = 5 \), meaning the equation has two distinct real solutions.
The real solutions, therefore, can be calculated using the quadratic formula, resulting in:
- \( x_1 = \frac{-3 + \sqrt{5}}{2} \)
- \( x_2 = \frac{-3 - \sqrt{5}}{2} \)
Roots of a Quadratic Equation
The roots of a quadratic equation refer to the solutions of the equation where the associated quadratic function equals zero. These roots can be real or complex and are essentially the x-values that make the equation true.
For the quadratic equation \( ax^2 + bx + c = 0 \), the roots are determined using the quadratic formula. Once the values for \( x \) are calculated, you get the roots of the equation.
In our example \( x^2 + 3x + 1 = 0 \), the calculation led to two distinct real roots:
For the quadratic equation \( ax^2 + bx + c = 0 \), the roots are determined using the quadratic formula. Once the values for \( x \) are calculated, you get the roots of the equation.
In our example \( x^2 + 3x + 1 = 0 \), the calculation led to two distinct real roots:
- \( x_1 = \frac{-3 + \sqrt{5}}{2} \)
- \( x_2 = \frac{-3 - \sqrt{5}}{2} \)