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Write each number in scientific notation. $$ 0.000028536 $$

Short Answer

Expert verified
\(2.8536 \times 10^{-5}\)

Step by step solution

01

Identify the Coefficient and Decimal Movement

First, identify the coefficient in the number that, when multiplied by a power of 10, will equal the original number. In this case, the number is 0.000028536. We move the decimal point to the right to get a number between 1 and 10, giving us 2.8536.
02

Determine the Power of 10

Count how many places you moved the decimal point to the right to turn 0.000028536 to 2.8536. The decimal was moved 5 places to the right.
03

Write in Scientific Notation

Express the original number as a product of 2.8536 and 10 raised to the power of the number of decimal places moved, which is -5. Therefore, the scientific notation is \(2.8536 \times 10^{-5}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Decimal Movement
Understanding how decimal movement works is crucial when converting a number to scientific notation. When you have a small number like 0.000028536, the aim is to change it so that it looks like a simple number multiplied by a power of 10. To do this, you need to move the decimal point. Moving the decimal helps you find a simple number called the coefficient, but more on that later.

In the example of 0.000028536, you will move the decimal point to the right until you get a number between 1 and 10. Count each movement as a step. Here, the decimal moves 5 places to the right, landing us at 2.8536, the coefficient. Remember, each move changes the power of 10 by one unit. Since we started moving to the right past zeroes, each step increases the negative exponent.
Coefficient
The next important part of scientific notation is the coefficient. It is the number you get after moving the decimal to create a new number between 1 and 10. This number will be multiplied by a power of 10 to give the original number. Think of it as a way to shrink the original number into something much simpler.

For example, when you shift the decimal in 0.000028536 to the right 5 times, you get 2.8536. That smaller, simpler form of the number—2.8536—is your coefficient. The easier the coefficient, the nicer your number looks in scientific notation. By using coefficients, you simplify reading and writing long numbers, turning them into compact and manageable pieces.
Power of 10
The final piece of scientific notation is involving the power of 10. This part of the notation tells us how many times to multiply or divide the coefficient by 10, to return to the original number. The power is critical because it helps represent very big or very small numbers in a concise form.

In the case of 0.000028536, after moving the decimal rightward 5 times to find the coefficient 2.8536, we record the move as a power of -5. This indicates the original number is smaller and needs five additional zeros on the left to become the coefficient. Thus, the number in scientific notation becomes \(2.8536 \times 10^{-5}\). Negative powers mean the original number was less than one.

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Most popular questions from this chapter

The Form of an Algebraic Expression An algebraic expression may look complicated, but its 'form" is always simple; it must be a sum, a product, a quotient, or a power. For example, consider the following expressions: $$ \begin{array}{ll}{\left(1+x^{2}\right)^{2}+\left(\frac{x+2}{x+1}\right)^{3}} & {(1+x)\left(1+\frac{x+5}{1+x^{4}}\right)} \\\ {\frac{\left(5-x^{3}\right)}{1+\sqrt{1+x^{2}}}} & {\sqrt{\frac{1+x}{1-x}}}\end{array} $$ With appropriate choices for \(A\) and \(B\) , the first has the form \(A+B,\) the second \(A B\) , the third \(A / B,\) and the fourth \(A^{1 / 2}\) . Recognizing the form of an expression helps us expand, simplify, or factor it correctly. Find the form of the following algebraic expressions. $$ \begin{array}{ll}{\text { (a) } x+\sqrt{1+\frac{1}{x}}} & {\text { (b) }\left(1+x^{2}\right)(1+x)^{3}} \\ {\text { (c) } \sqrt[3]{x^{4}\left(4 x^{2}+1\right)}} & {\text { (d) } \frac{1-2 \sqrt{1+x}}{1+\sqrt{1+x^{2}}}}\end{array} $$

Simplify the expression and eliminate any negative exponent(s). $$ (6 y)^{3} $$

Is This Rationalization? In the expression 2\(/ \sqrt{x}\) we would eliminate the radical if we were to square both numerator and denominator. Is this the same thing as rationalizing the denominator?

Factoring \(A^{m}-1\) Verify the factoring formulas in the list by expanding and simplifying the right-hand side in each case. \(A^{2}-1=(A-1)(A+1)\) \(A^{3}-1=(A-1)\left(A^{2}+A+1\right)\) \(A^{4}-1=(A-1)\left(A^{3}+A^{2}+A+1\right)\) Based on the pattern displayed in this list, how do you think \(A^{5}-1\) would factor? Verify your conjecture. Now generalize the pattern you have observed to obtain a factorization formula for \(A^{n}-1,\) where \(n\) is a positive integer.

Simplify the expression and eliminate any negative exponent(s). $$ \left(3 y^{2}\right)\left(4 y^{5}\right) $$

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