/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 \(35-54\) . Perform the addition... [FREE SOLUTION] | 91Ó°ÊÓ

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\(35-54\) . Perform the addition or subtraction and simplify. $$ \frac{1}{x+5}+\frac{2}{x-3} $$

Short Answer

Expert verified
\( \frac{3x + 7}{(x+5)(x-3)} \) is the simplified result.

Step by step solution

01

Identify the Least Common Denominator (LCD)

To add the fractions \( \frac{1}{x+5} \) and \( \frac{2}{x-3} \), we need to have a common denominator. The least common denominator (LCD) for the two fractions is the product of the denominators: \( (x+5)(x-3) \).
02

Rewrite Each Fraction with the LCD

Rewrite each fraction so that they both have the LCD as their denominator. This involves adjusting each fraction:- For \( \frac{1}{x+5} \), multiply both the numerator and denominator by \( (x-3) \):\[\frac{1 \cdot (x-3)}{(x+5)(x-3)} = \frac{x-3}{(x+5)(x-3)}\]- For \( \frac{2}{x-3} \), multiply both the numerator and denominator by \( (x+5) \):\[\frac{2 \cdot (x+5)}{(x+5)(x-3)} = \frac{2x+10}{(x+5)(x-3)}\]
03

Combine the Fractions

Now that both fractions have the same denominator, we can combine them by adding their numerators:\[\frac{x-3 + 2x + 10}{(x+5)(x-3)}\]
04

Simplify the Numerator

Simplify the combined numerator by combining like terms:\[\frac{3x + 7}{(x+5)(x-3)}\]
05

Write the Final Simplified Expression

The final simplified expression is:\[\frac{3x + 7}{(x+5)(x-3)}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Least Common Denominator
When adding or subtracting fractions, whether they are numerical or algebraic, finding a common denominator is crucial. This shared denominator allows us to work with the fractions as parts of a complete whole. For algebraic fractions, the least common denominator (LCD) is particularly important because it unites terms with different denominators, helping us perform operations seamlessly.
In the problem given, we have two fractions: \( \frac{1}{x+5} \) and \( \frac{2}{x-3} \). Their denominators, \( x+5 \) and \( x-3 \), do not easily share a common base. To determine the LCD, we multiply the two denominators together, resulting in \((x+5)(x-3)\).
  • This technique ensures that we account for all parts of each original denominator.
  • The complexity of algebra makes finding the LCD by multiplication an efficient strategy.
Once the common denominator is established, fractions can be rewritten to have this denominator, enabling smooth addition or subtraction.
Simplifying Expressions
Once we've established the least common denominator, it's time to rewrite and then add the fractions. However, just combining isn't enough; the expression needs simplification to ensure it's easy to understand and efficient. Simplifying helps reveal the core function and relationships of variables in the expression.
First, each algebraic fraction is rewritten using the LCD by multiplying the numerator and the denominator by the parts of the LCD that were missing. This process involves:
  • For \( \frac{1}{x+5} \), multiplying the numerator and denominator by \( (x-3) \), resulting in \( \frac{x-3}{(x+5)(x-3)} \).
  • For \( \frac{2}{x-3} \), multiplying the numerator and denominator by \( (x+5) \), giving us \( \frac{2x+10}{(x+5)(x-3)} \).
Once rewritten, add the numerators over the common denominator and combine like terms. This simplifies the expression to \( \frac{3x + 7}{(x+5)(x-3)} \). Simplification ensures the expression is in its most concise and useful form, laying bare the model's essential components.
Algebraic Fractions
An algebraic fraction contains polynomials in its numerator or denominator, and working with them can initially seem complex due to the presence of variables. Understanding how to navigate between these variables is key to successfully handling expressions like the one in the exercise.
The main task revolves around:
  • Properly identifying each component of the algebraic fraction.
  • Utilizing operations like multiplication to find common denominators.
  • Simplifying complex expressions while preserving equality.
In our example, each fraction's unique denominator, \( x+5 \) and \( x-3 \), are expressions rather than just numbers. Navigating these requires embracing principles of algebra such as distribution and factoring for effective management.
Mastering algebraic fractions allows for tackling broader algebraic problems, meaningfully linking different expressions. With practice, managing these fractions becomes second nature, offering insight into more advanced mathematical analyses.

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Most popular questions from this chapter

Factoring \(x^{4}+a x^{2}+b\) A trinomial of the form \(x^{4}+a x^{2}+b\) can sometimes be factored easily. For example \(x^{4}+3 x^{2}-4=\left(x^{2}+4\right)\left(x^{2}-1\right) .\) But \(x^{4}+3 x^{2}+4\) cannot be factored in this way. Instead, we can use the following method. \(x^{4}+3 x^{2}+4=\left(x^{4}+4 x^{2}+4\right)-x^{2} \quad\) Add and subtract \(x^{2}\) \(=\left(x^{2}+2\right)^{2}-x^{2} \quad\) Factor perfect square \(=\left[\left(x^{2}+2\right)-x\right]\left[\left(x^{2}+2\right)+x\right] \quad\) Difference of squares \(=\left(x^{2}-x+2\right)\left(x^{2}+x+2\right)\) Factor the following using whichever method is appropriate. (a) \(x^{4}+x^{2}-2\) (b) \(x^{4}+2 x^{2}+9\) (c) \(x^{4}+4 x^{2}+16\) (d) \(x^{4}+2 x^{2}+1\)

\(65-70\) m Simplify the fractional expression. (Expressions like these arise in calculus.) $$ \frac{\frac{1-(x+h)}{2+(x+h)}-\frac{1-x}{2+x}}{h} $$

Complete the following tables. What happens to the \(n\) th root of 2 as \(n\) gets large? What about the \(n\) th root of \(\frac{1}{2} ?\) \(\begin{array}{|c|c|}\hline n & {2^{1 / n}} \\ \hline 1 & {} \\ {2} & {} \\\ {5} \\ {10} \\ {100} & {} \\ \hline\end{array}\) \(\begin{array}{|c|c|}\hline n & {\left(\frac{1}{2}\right)^{1 / n}} \\ \hline 1 & {} \\ {2} & {} \\ {5} & {} \\ {10} \\ {100} & {} \\ \hline\end{array}\) Construct a similar table for \(n^{1 / n} .\) What happens to the \(n\) th root of \(n\) as \(n\) gets large?

Use scientific notation, the Laws of Exponents, and a calculator to perform the indicated operations. State your answer correct to the number of significant digits indicated by the given data. $$ \frac{1.295643 \times 10^{9}}{\left(3.610 \times 10^{-17}\right)\left(2.511 \times 10^{6}\right)} $$

\(55-64=\) Simplify the compound fractional expression. $$ \frac{\frac{5}{x-1}-\frac{2}{x+1}}{\frac{x}{x-1}+\frac{1}{x+1}} $$

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