Chapter 0: Problem 13
9–16 ? Factor the trinomial. $$ 8 x^{2}-14 x-15 $$
Short Answer
Expert verified
The trinomial \( 8x^2 - 14x - 15 \) factored is \((4x + 3)(2x - 5)\).
Step by step solution
01
Identify coefficients
First, identify the coefficients of the quadratic trinomial in the form \( ax^2 + bx + c \). Here, \( a = 8 \), \( b = -14 \), and \( c = -15 \). This is important for factoring the trinomial.
02
Multiply \( a \) and \( c \)
Multiply the leading coefficient \( a \) and the constant term \( c \). So, \( 8 \times -15 = -120 \). We'll use this product to find two numbers that help us factor the trinomial.
03
Find two numbers that multiply to \(-120\) and sum to \(b\)
Look for two integers whose product is \(-120\) and whose sum is \(b = -14\). The numbers \( -20 \) and \( 6 \) meet these criteria since \( -20 \times 6 = -120 \) and \( -20 + 6 = -14 \).
04
Rewrite the middle term using these numbers
Rewrite the middle term \(-14x\) of the trinomial using the numbers found: \( -20x + 6x \). This changes the expression from \( 8x^2 - 14x - 15 \) to \( 8x^2 - 20x + 6x - 15 \).
05
Group the terms
Group the terms to prepare for factoring by grouping: \( (8x^2 - 20x) + (6x - 15) \).
06
Factor by grouping
Factor out the greatest common factor (GCF) from each group. From the first group, \( 8x^2 - 20x \), factor out \( 4x \) to get \( 4x(2x - 5) \). From the second group, \( 6x - 15 \), factor out \( 3 \) to get \( 3(2x - 5) \).
07
Write the factored form
Notice that both groups now contain the common factor \( (2x - 5) \). Factor this out to get \( (4x + 3)(2x - 5) \), which is the fully factored form of the trinomial.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Expressions
Quadratic expressions are polynomial expressions where the highest-degree term is squared, meaning it is raised to the power of two. These expressions typically appear in the form \( ax^2 + bx + c \), where:
- \( a \) is the coefficient of the \( x^2 \) term.
- \( b \) is the coefficient of the \( x \) term.
- \( c \) is the constant term.
Factoring by Grouping
Factoring by grouping is a method often used to break down more complex polynomials into simpler, product-like forms. This method is handy when dealing with four-term polynomials that arise from breaking and rearranging trinomial quadratic expressions. Here's how the process works in simple steps:
- Start by reorganizing the polynomial into two groups.
- Factor out the greatest common factor from each group.
- Recognize and extract the common factor from the modified groups.
Coefficients Identification
Identifying coefficients is a fundamental step in polynomial factorization. Each term in a polynomial has a coefficient, which is a constant that multiplies the variable. Understanding how to correctly identify these will guide your factorization efforts effectively. For our quadratic trinomial \( ax^2 + bx + c \):
- Coefficient \( a \) belongs to the \( x^2 \) term.
- Coefficient \( b \) pertains to the \( x \) term.
- \( c \) is a constant, or the term with no variable.