/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 68 Solve the formula \(A=\frac{1}{2... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Solve the formula \(A=\frac{1}{2} b h\) for \(h\).

Short Answer

Expert verified
h = \frac{2A}{b}

Step by step solution

01

Understand the problem

The given formula is for the area of a triangle, where A is the area, b is the base, and h is the height. We need to solve this formula for h.
02

Isolate the height (h)

To solve for h, first multiply both sides of the equation by 2 to clear the fraction. This gives us: \( 2A = bh \)
03

Divide by the base (b)

Next, divide both sides of the equation by b to isolate h. This results in: \( h = \frac{2A}{b} \)
04

Write the final formula

Now, we have solved for height (h), and the final formula is: \( h = \frac{2A}{b} \)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Area of a Triangle
To start with, the area of a triangle is an important geometric concept. The formula used to calculate the area of a triangle is given by \(A = \frac{1}{2} bh\). Here, \(A\) represents the area, \(b\) stands for the base, and \(h\) is the height of the triangle. This formula is derived from the fact that a triangle is essentially half of a rectangle. Knowing how to find the area using this formula is crucial for solving many geometry problems. If you visualize a triangle, you'll notice that its height is the perpendicular distance from the base to the opposite vertex. Understanding this concept helps in various applications, like finding the height when the area and the base are known.
Isolating Variables
Isolating variables is a fundamental technique in algebra. This skill involves rearranging an equation to get a specific variable alone on one side of the equation. In the given problem, we are asked to solve for height \(h\) from the area formula \(A = \frac{1}{2} bh\). Isolating \(h\) means we need to manipulate the equation so that \(h\) is by itself. This process often involves a series of steps including addition, subtraction, multiplication, or division. In our problem, we first eliminate the fraction by multiplying both sides by 2. This action simplifies the equation and helps to isolate the desired variable more easily. Mastery over isolating variables not only helps in solving geometric problems but is also widely applicable in various fields of science and mathematics.
Formula Manipulation
Formula manipulation includes altering the structure of a given formula to solve for an unknown variable. In the exercise, we are working with the area formula \(A = \frac{1}{2} bh\). To solve for the height \(h\), we need to manipulate this formula methodically. After clearing the fraction by multiplying both sides by 2, we get \(2A = bh\). This manipulation makes it simpler to solve for \(h\). Next, we divide both sides by the base \(b\), resulting in the final formula \( h = \frac{2A}{b} \). Manipulating formulas requires careful step-by-step operations and ensures all mathematical rules are followed correctly. Proper manipulation allows us to express variables in terms of other known quantities, facilitating easier problem-solving.
Algebraic Equations
Algebraic equations are mathematical statements that show the equality of two expressions. They form the basis of many problem-solving scenarios in mathematics. When solving algebraic equations, you often work towards isolating the variable of interest. In the provided solution, we began with the area formula for a triangle: \(A = \frac{1}{2} bh\). To solve for \(h\), we treat the equation like any algebraic equation, applying operations systematically. First, we multiply both sides by 2 to get rid of the fraction, leading us to \(2A = bh\). Then, we divide both sides by \(b\) to isolate \(h\), giving \( h = \frac{2A}{b} \). Being proficient at manipulating algebraic equations is essential not only for geometry but also for tackling diverse mathematical challenges.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Solve each equation on the interval \(0 \leq \theta<2 \pi\). $$ \sin \theta+\cos \theta=\sqrt{2} $$

True or False \(\csc ^{-1} 0.5\) is not defined.

True or False \(\sin ^{2} \theta=1-\cos ^{2} \theta\)

Problems 83 and 84 require the following discussion: When granular materials are allowed to fall freely, they form conical (cone-shaped) piles. The naturally occurring angle, measured from the horizontal, at which the loose material comes to rest is called the angle of repose and varies for different materials. The angle of repose \(\theta\) is related to the height \(h\) and the base radius \(r\) of the conical pile by the equation \(\theta=\cot ^{-1} \frac{r}{h} .\) See the illustration. Angle of Repose: De-icing Salt Due to potential transportation issues (for example, frozen waterways), de-icing salt used by highway departments in the Midwest must be ordered early and stored for future use. When de-icing salt is stored in a pile 14 feet high, the diameter of the base of the pile is 45 feet. (a) Find the angle of repose for de-icing salt. (b) What is the base diameter of a pile that is 17 feet high? (c) What is the height of a pile that has a base diameter of approximately 122 feet?

Angle of Repose: Bunker Sand The steepness of sand bunkers on a golf course is affected by the angle of repose of the sand (a larger angle of repose allows for steeper bunkers). A freestanding pile of loose sand from a United States Golf Association (USGA) bunker had a height of 4 feet and a base diameter of approximately 6.68 feet. (a) Find the angle of repose for USGA bunker sand. Artillery A projectile fired into the first quadrant from the origin of a rectangular coordinate system will pass through the point \((x, y)\) at time \(t\) according to the relationship \(\cot \theta=\frac{2 x}{2 y+g t^{2}},\) where \(\theta=\) the angle of elevation of the launcher and \(g=\) the acceleration due to gravity \(=32.2\) feet/second \(^{2}\). An artilleryman is firing at an enemy bunker located 2450 feet up the side of a hill that is 6175 feet away. He fires a round, and exactly 2.27 seconds later he scores a direct hit. (a) What angle of elevation did he use? (b) If the angle of elevation is also given by \(\sec \theta=\frac{v_{0} t}{x}\) where \(v_{0}\) is the muzzle velocity of the weapon, find the muzzle velocity of the artillery piece he used.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.