Chapter 8: Problem 64
Establish each identity. \(\tan \frac{v}{2}=\csc v-\cot v\)
Short Answer
Expert verified
\(\tan \frac{v}{2} = \text{csc}(v) - \text{cot}(v)\)
Step by step solution
01
Rewrite the trigonometric functions using their definitions
Recall that \(\tan \frac{v}{2}\) is the tangent of half an angle and by the definition, \(\tan \frac{v}{2} = \frac{\text{sin}(\frac{v}{2})}{\text{cos}(\frac{v}{2})}\). Now we must also recall that \(\text{csc}(v) = \frac{1}{\text{sin}(v)}\) and \(\text{cot}(v) = \frac{\text{cos}(v)}{\text{sin}(v)}\).
02
Use trigonometric identities for half-angle formulas
The half-angle identities can be used: \(\text{sin}\frac{v}{2} = \text{sqrt}\frac{1 - \text{cos}(v)}{2}\) and \(\text{cos}\frac{v}{2} = \text{sqrt}\frac{1 + \text{cos}(v)}{2}\). Therefore, \(\tan \frac{v}{2} = \frac{\text{sin}\frac{v}{2}}{\text{cos}\frac{v}{2}} = \frac{\text{sqrt}\frac{1 - \text{cos}(v)}{2}}{\text{sqrt}\frac{1 + \text{cos}(v)}{2}} = \text{sqrt}\frac{1 - \text{cos}(v)}{1 + \text{cos}(v)}\).
03
Rewrite \(\text{csc}(v) - \text{cot}(v)\) with their definitions
We can rewrite the right-hand side using definitions: \(\text{csc}(v) - \text{cot}(v) = \frac{1}{\text{sin}(v)} - \frac{\text{cos}(v)}{\text{sin}(v)} = \frac{1 - \text{cos}(v)}{\text{sin}(v)} = \frac{1 - \text{cos}(v)}{\text{sqrt}(1 - \text{cos}^2(v))}\).
04
Simplify the expression
Notice that \(\text{sin}^2(v) = 1 - \text{cos}^2(v)\), so \(\text{sin}(v) = \text{sqrt}(1 - \text{cos}^2(v))\). This rewrites the denominator and matches: \(\frac{1 - \text{cos}(v)}{\text{sqrt}(1 - \text{cos}^2(v))} = \text{sqrt}\frac{1 - \text{cos}(v)}{1 + \text{cos}(v)}\). This confirms the identity \(\tan \frac{v}{2} = \text{csc}(v) - \text{cot}(v)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Half-Angle Formulas
Understanding half-angle formulas is crucial for establishing various trigonometric identities. These formulas express trigonometric functions of half-angles in terms of the trigonometric functions of the original angle. This becomes especially useful when solving complex trigonometric expressions and proofs.
For sine and cosine, the half-angle identities are:
For example, \(\text{cos}(2u) = 2 \text{cos}^2(u) - 1\) can be rewritten to \(\text{cos}(u) = \text{sqrt} \frac{1 + \text{cos}(2u)}{2}\). Similarly, half-angle formulas help simplify many trigonometric problems efficiently.
For sine and cosine, the half-angle identities are:
- \(\text{sin} \frac{v}{2} = \text{sqrt} \frac{1 - \text{cos}(v)}{2}\)
- \(\text{cos} \frac{v}{2} = \text{sqrt} \frac{1 + \text{cos}(v)}{2}\)
For example, \(\text{cos}(2u) = 2 \text{cos}^2(u) - 1\) can be rewritten to \(\text{cos}(u) = \text{sqrt} \frac{1 + \text{cos}(2u)}{2}\). Similarly, half-angle formulas help simplify many trigonometric problems efficiently.
Tangent of Half an Angle
The tangent of half an angle can also be expressed using half-angle formulas. Specifically, it can be rephrased as: \(\tan \frac{v}{2} = \frac{\text{sin}(\frac{v}{2})}{\text{cos}(\frac{v}{2})}\).
Using the half-angle identities for sine and cosine mentioned above, we substitute to get: \(\tan \frac{v}{2} = \frac{\text{sqrt}\frac{1 - \text{cos}(v)}{2}}{\text{sqrt}\frac{1 + \text{cos}(v)}{2}}\).
By simplifying the expression, we arrive at: \(\tan \frac{v}{2} = \text{sqrt}\frac{1 - \text{cos}(v)}{1 + \text{cos}(v)}\).
This formula is beneficial for problems that require manipulating angles within the range of 0 to \(2\pi\), enabling easier simplifications of trigonometric identities and equations.
Using the half-angle identities for sine and cosine mentioned above, we substitute to get: \(\tan \frac{v}{2} = \frac{\text{sqrt}\frac{1 - \text{cos}(v)}{2}}{\text{sqrt}\frac{1 + \text{cos}(v)}{2}}\).
By simplifying the expression, we arrive at: \(\tan \frac{v}{2} = \text{sqrt}\frac{1 - \text{cos}(v)}{1 + \text{cos}(v)}\).
This formula is beneficial for problems that require manipulating angles within the range of 0 to \(2\pi\), enabling easier simplifications of trigonometric identities and equations.
Sine and Cosine Definitions
The definitions of sine and cosine are fundamental to understanding and using trigonometric identities. In a right-angled triangle:
- \(\text{sin}(v) = \frac{\text{opposite}}{\text{hypotenuse}}\)
- \(\text{cos}(v) = \frac{\text{adjacent}}{\text{hypotenuse}}\)
- \(\text{sin}(v)\) corresponds to the y-coordinate of the point on the unit circle.
- \(\text{cos}(v)\) corresponds to the x-coordinate.