/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 Find the exact value of each exp... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the exact value of each expression. $$ \cot \left[\sin ^{-1}\left(-\frac{1}{2}\right)\right] $$

Short Answer

Expert verified
\(-\sqrt{3}\)

Step by step solution

01

- Identify the Inverse Sine Argument

Examine the argument within the inverse sine function. Here, it is \(-\frac{1}{2}\).
02

- Determine the Angle

Identify the angle \(\theta\) such that \(\theta = \sin^{-1}(-\frac{1}{2})\). The sine of this angle must equal \(-\frac{1}{2}\).
03

- Find \(\theta\) in the Correct Quadrant

\(\theta\) corresponding to \(\theta = \sin^{-1}(-\frac{1}{2})\) is found in the fourth quadrant (since \(\theta\) must be within \[-\frac{\pi}{2}, \frac{\pi}{2}\]). Therefore, \(\theta = -\frac{\pi}{6}\).
04

- Calculate the Cotangent

Now that \(\theta = -\frac{\pi}{6}\), calculate the cotangent of \(\theta\). We use the identity: \(\text{cot}(\theta) = \frac{\text{cos}(\theta)}{\text{sin}(\theta)}\).
05

- Evaluate the Sine and Cosine

For \(\theta = -\frac{\pi}{6}\): \(\text{sin}(-\frac{\pi}{6}) = -\frac{1}{2}\) and \(\text{cos}(-\frac{\pi}{6}) = \frac{\sqrt{3}}{2}\).
06

- Compute the Cotangent Value

Using the values found, calculate \(\text{cot}(-\frac{\pi}{6}) = \frac{\text{cos}(-\frac{\pi}{6})}{\text{sin}(-\frac{\pi}{6})} = \frac{\frac{\sqrt{3}}{2}}{-\frac{1}{2}} = -\sqrt{3}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cotangent
Cotangent is a trigonometric function, often abbreviated as \(\text{cot}\). It is the reciprocal of the tangent function, and it can be expressed as \[\text{cot}(\theta) = \frac{1}{\text{tan}(\theta)}\].

Another common definition is that \[\text{cot}(\theta) = \frac{\text{cos}(\theta)}{\text{sin}(\theta)}\].

This means to find the cotangent of any angle, you need to divide the cosine of that angle by the sine. The cotangent function is particularly useful in various trigonometric calculations.

For example, if you have an angle \(\theta=−\frac{\pi}{6}\), you first find \(\text{cos}(-\frac{\pi}{6})\) and \(\text{sin}(-\frac{\pi}{6})\). For this angle, \(\text{cos}(-\frac{\pi}{6}) = \frac{\sqrt{3}}{2}\) and \(\text{sin}(-\frac{\pi}{6}) = -\frac{1}{2}\).

Using these values, you calculate \[\text{cot}(-\frac{\pi}{6}) = \frac{\frac{\sqrt{3}}{2}}{-\frac{1}{2}} = -\sqrt{3}\].
Inverse Sine
The inverse sine function, also known as arcsine, is denoted as \(\sin^{-1}(x)\) or \(\arcsin(x)\). This function returns the angle whose sine is a given number.

For instance, \(\sin^{-1}(-\frac{1}{2})\) gives the angle whose sine value is \(−\frac{1}{2}\).

In general, the range of the inverse sine function is \[-\frac{\pi}{2},\frac{\pi}{2}\]. This means it returns angles within this interval.

For the example given, \(\sin^{-1}(-\frac{1}{2}) = -\frac{\pi}{6}\). To check this, recognize that \(\sin(-\frac{\pi}{6}) = -\frac{1}{2}\).
Trigonometric Identities
Trigonometric identities are formulas that involve trigonometric functions and are true for every value of the occurring variables.

Some fundamental identities include:

  • Pythagorean Identity: \[\sin^2(\theta) + \cos^2(\theta) = 1\]
  • Reciprocal Identities: \[\sec(\theta) = \frac{1}{\cos(\theta)}, \text{csc}(\theta) = \frac{1}{\sin(\theta)}, \text{cot}(\theta) = \frac{1}{\tan(\theta)}\]
  • Quotient Identities: \[\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}, \text{cot}(\theta) = \frac{\cos(\theta)}{\sin(\theta)}\]


Using these identities helps solve many trigonometric problems.

For example, to find the cotangent, we use \(\text{cot}(\theta) = \frac{\cos(\theta)}{\sin(\theta)}\), which simplifies our calculations.
Unit Circle
The unit circle is a circle with a radius of 1, centered at the origin of the coordinate plane. It is widely used in trigonometry due to its simplicity.

Every point \(P(x,y)\) on the unit circle satisfies the equation \[x^2 + y^2 = 1\].

In the context of trigonometric functions:
  • The \(x\)-coordinate of a point on the unit circle represents \(\cos(\theta)\) for some angle \(\theta\).
  • The \(y\)-coordinate represents \(\sin(\theta)\).
This makes it easy to find sine and cosine values for various angles.
For the angle \(−\frac{\pi}{6}\), the corresponding point on the unit circle would be \(\left(\frac{\sqrt{3}}{2}, -\frac{1}{2}\right)\). Here, \(\frac{\sqrt{3}}{2}\) is \(\cos(−\frac{\pi}{6})\), and \(−\frac{1}{2}\) is \(\sin(\−\frac{\pi}{6})\).
Angles in Radians
Radians are a way of measuring angles other than degrees. One radian is the angle made when the arc length is equal to the radius of the circle.

To convert between degrees and radians, use the following conversions:
  • Degrees to Radians: \[\text{radians} = \frac{\text{degrees} \cdot \pi}{180}\]
  • Radians to Degrees: \[\text{degrees} = \frac{\text{radians} \cdot 180}{\pi}\]


Common angle conversions include:
  • \(\frac{\pi}{6} = 30^{\circ}\)
  • \(\frac{\pi}{4} = 45^{\circ}\)
  • \(\frac{\pi}{3} = 60^{\circ}\)
  • \(\frac{\pi}{2} = 90^{\circ}\)

In our example, \(\−\frac{\pi}{6}\) is the radian measure for \(−30^{\circ}\).

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Most popular questions from this chapter

True or False $$\tan \theta \cdot \cos \theta=\sin \theta \text { for any } \theta \neq(2 k+1) \frac{\pi}{2}$$

Find the exact value, if any, of each composite function. If there is no value, state it is "not defined." Do not use a calculator. \(\sin ^{-1}\left[\sin \left(-\frac{3 \pi}{4}\right)\right]\)

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Problems 83 and 84 require the following discussion: When granular materials are allowed to fall freely, they form conical (cone-shaped) piles. The naturally occurring angle, measured from the horizontal, at which the loose material comes to rest is called the angle of repose and varies for different materials. The angle of repose \(\theta\) is related to the height \(h\) and the base radius \(r\) of the conical pile by the equation \(\theta=\cot ^{-1} \frac{r}{h} .\) See the illustration. Angle of Repose: De-icing Salt Due to potential transportation issues (for example, frozen waterways), de-icing salt used by highway departments in the Midwest must be ordered early and stored for future use. When de-icing salt is stored in a pile 14 feet high, the diameter of the base of the pile is 45 feet. (a) Find the angle of repose for de-icing salt. (b) What is the base diameter of a pile that is 17 feet high? (c) What is the height of a pile that has a base diameter of approximately 122 feet?

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