Chapter 8: Problem 3
True or False The graph of \(y=\cos x\) is decreasing on the interval \([0, \pi]\)
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Chapter 8: Problem 3
True or False The graph of \(y=\cos x\) is decreasing on the interval \([0, \pi]\)
These are the key concepts you need to understand to accurately answer the question.
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Based on material learned earlier in the course. The purpose of these problems is to keep the material fresh in your mind so that you are better prepared for the final exam. Convert \(\frac{17 \pi}{6}\) to degrees.
Area under a Curve The area under the graph of \(y=\frac{1}{\sqrt{1-x^{2}}}\) and above the \(x\) -axis between \(x=a\) and \(x=b\) is given by $$ \sin ^{-1} b-\sin ^{-1} a $$ (a) Find the exact area under the graph of \(y=\frac{1}{\sqrt{1-x^{2}}}\) and above the \(x\) -axis between \(x=0\) and \(x=\frac{\sqrt{3}}{2}\). (b) Find the exact area under the graph of \(y=\frac{1}{\sqrt{1-x^{2}}}\) and above the \(x\) -axis between \(x=-\frac{1}{2}\) and \(x=\frac{1}{2}\)
The function \(f(x)=\frac{3-x}{2 x-5}\) is one-to-one. Find \(f^{-1}\).
If \(\sin \theta=-\frac{\sqrt{10}}{10}\) and \(\cos \theta=\frac{3 \sqrt{10}}{10},\) find the exact value of each of the four remaining trigonometric functions.
Movie Theater Screens Suppose that a movie theater has a screen that is 28 feet tall. When you sit down, the bottom of the screen is 6 feet above your eye level. The angle formed by drawing a line from your eye to the bottom of the screen and another line from your eye to the top of the screen is called the viewing angle. In the figure, \(\theta\) is the viewing angle. Suppose that you sit \(x\) feet from the screen. The viewing angle \(\theta\) is given by the function $$ \theta(x)=\tan ^{-1}\left(\frac{34}{x}\right)-\tan ^{-1}\left(\frac{6}{x}\right) $$ (a) What is your viewing angle if you sit 10 feet from the screen? 15 feet? 20 feet? (b) If there are 5 feet between the screen and the first row of seats and there are 3 feet between each row and the row behind it, which row results in the largest viewing angle? (c) Using a graphing utility, graph $$ \theta(x)=\tan ^{-1}\left(\frac{34}{x}\right)-\tan ^{-1}\left(\frac{6}{x}\right) $$ What value of \(x\) results in the largest viewing angle?
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