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Based on material learned earlier in the course. The purpose of these problems is to keep the material fresh in your mind so that you are better prepared for the final exam. Write as a single logarithm: $$ 3 \log _{7} x+2 \log _{7} y-5 \log _{7} z $$

Short Answer

Expert verified
\( 3 \text{log}_{7} x+2 \text{log}_{7} y-5 \text{log}_{7} z= \text{log}_{7} (x^3 y^2 z^5)\)

Step by step solution

01

Apply the Power Rule

Using the power rule of logarithms, which states that \(\b \times \text{log}_{a}=\text{log}_{a}(x^b)\), rewrite each term. \( 3 \text{log}_{7} (x) = \text{log}_{7} (x^3) 2 \text{log}_{7} (y) = \text{log}_{7} (y^2) -5 \text{log}_{7} (z) = \text{log}_{7} (z^{-5}) \)
02

Combine the Logarithms

Next, combine the logarithms using the properties of logarithms. The sum of logarithms translates into the logarithm of the product, and the difference of logarithms translates into the logarithm of a quotient. \(\text{log}_{7} (x^3) + \text{log}_{7} (y^2) - \text{log}_{7} (z^{-5}) = \text{log}_{7} \frac{x^3 \times y^2}{z^{-5}} \)
03

Simplify the Expression

Simplify the equation \(\text{log}_{7} \frac{x^3 \times y^2}{z^{-5}}\) further by taking into account that dividing by a negative exponent is equivalent to multiplying: \(\frac{1}{z^{-5}} = z^{5}\). Hence: \(\text{log}_{7} \frac{x^3 \times y^2}{z^{-5}}= \text{log}_{7} (x^3 \times y^2 \times z^5)\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

power rule of logarithms
The power rule of logarithms is a very powerful tool. It helps simplify expressions involving logarithms with coefficients. When you have a term like \(a \text{log}_{b}(x)\), you can rewrite it using the power rule: \(\text{log}_{b}(x^a)\). This changes the coefficient into an exponent of the argument inside the logarithm.

Let's break down the example given in the exercise:
  • \(3 \text{log}_{7}(x)\) becomes \(\text{log}_{7}(x^3)\)
  • \(2 \text{log}_{7}(y)\) becomes \(\text{log}_{7}(y^2)\)
  • and \(-5 \text{log}_{7}(z)\) becomes \(\text{log}_{7}(z^{-5})\).

By using the power rule, we turn multiplication outside the logarithm into exponentiation inside the logarithm.
properties of logarithms
Combining logarithms is another important step based on their properties. When you have the sum of logarithms with the same base, you can combine them into a single logarithm of their product. Similarly, the difference of logarithms can be rewritten as a single logarithm of their quotient. This process requires knowing a few basic logarithm properties:
  • The product property: \(\text{log}_{b}(m) + \text{log}_{b}(n) = \text{log}_{b}(mn)\)
  • The quotient property: \(\text{log}_{b}(m) - \text{log}_{b}(n) = \text{log}_{b}(m/n)\)

In our exercise, we applied these properties:
  • \(\text{log}_{7}(x^3) + \text{log}_{7}(y^2)\) combines into \(\text{log}_{7}(x^3 \times y^2)\)
  • \(\text{log}_{7}(x^3 \times y^2) - \text{log}_{7}(z^{-5})\) simplifies into \(\text{log}_{7}((x^3 \times y^2) / z^{-5})\)

These properties simplify the expression by reducing multiple logarithms into a single one.
logarithmic simplification
Finally, let's touch on logarithmic simplification. This involves using multiple properties and rules to simplify our expression fully. In the previous steps, we've reached the expression: \(\text{log}_{7}\frac{x^3 \times y^2}{z^{-5}}\). We can further simplify by considering the exponent rules. Know that dividing by a negative exponent is the same as multiplying by the positive exponent. This helps us turn the expression into a cleaner form: \(\frac{1}{z^{-5}} = z^{5}\).

So, \(\text{log}_{7}\frac{x^3 \times y^2}{z^{-5}} = \text{log}_{7}(x^3 \times y^2 \times z^5)\).

This final step gives us a single, simplified logarithm. It encapsulates the original multiple terms into an easy-to-use format. Simplification helps in solving and understanding more complex logarithmic equations later on.

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Most popular questions from this chapter

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