Chapter 7: Problem 95
State the domain of \(f(x)=\ln (5 x+2)\)
Short Answer
Expert verified
The domain of \(f(x) = \text{ln}(5x + 2)\) is \((- \frac{2}{5}, \infty)\).
Step by step solution
01
Understand the Logarithmic Function
The natural logarithm function, denoted as \(\text{ln}(x)\), is defined only for positive arguments, that is, \(\text{ln}(x)\) is defined if and only if \(x > 0\). Thus, any function inside the natural logarithm must be greater than zero.
02
Set the Argument Greater Than Zero
For the function \(f(x) = \text{ln}(5x + 2)\), the argument (5x + 2) must be greater than zero. So, set up the inequality: \(5x + 2 > 0\).
03
Solve the Inequality
Solve the inequality \(5x + 2 > 0\) to find the domain of the function.\(5x + 2 > 0\) Subtract 2 from both sides:\(5x > -2\). Divide both sides by 5:\(x > -\frac{2}{5}\).
04
State the Domain
The domain of \(f(x) = \text{ln}(5x + 2)\) is the set of all x values such that \(x > -\frac{2}{5}\). In interval notation, this is written as \((- \frac{2}{5}, \infty)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
natural logarithm
The natural logarithm, represented as \(\text{ln}(x)\), is a special logarithm with the base e (approximately 2.718).
It is important to understand that natural logarithm functions are only defined for positive values of x.
This means \(\text{ln}(x)\) only exists when x > 0, making it crucial to ensure any arguments within the natural logarithm are positive.
For instance, if we have \(\text{ln}(5x + 2)\), the expression inside, 5x + 2, must be greater than 0.
It is important to understand that natural logarithm functions are only defined for positive values of x.
This means \(\text{ln}(x)\) only exists when x > 0, making it crucial to ensure any arguments within the natural logarithm are positive.
For instance, if we have \(\text{ln}(5x + 2)\), the expression inside, 5x + 2, must be greater than 0.
inequalities
Inequalities are mathematical expressions involving symbols like >, <, ≥, and ≤ to show the relative sizes of two values.
To find the domain of \(\text{ln}(5x + 2)\), we need to set up an inequality because the argument of the logarithm must be positive.
We set the inequality as 5x + 2 > 0.
Solving this step-by-step involves:
To find the domain of \(\text{ln}(5x + 2)\), we need to set up an inequality because the argument of the logarithm must be positive.
We set the inequality as 5x + 2 > 0.
Solving this step-by-step involves:
- Subtracting 2 from both sides: 5x + 2 - 2 > 0 - 2 gives 5x > -2
- Dividing both sides by 5: \(\frac{5x}{5} > \frac{-2}{5}\), which simplifies to x > -\frac{2}{5}
interval notation
Interval notation is a way to represent the set of all numbers between two endpoints.
It uses parentheses ( ) for open intervals, which do not include the endpoints, and brackets [ ] for closed intervals, which do include the endpoints.
In our case, the solution to the inequality x > -2/5 is an open interval because -2/5 is not included.
Therefore, the domain in interval notation is written as \((- \frac{2}{5}, \infty)\).
The left parenthesis indicates that -2/5 is not included, while the infinity symbol \(\infty\) suggests that there is no upper limit.
It uses parentheses ( ) for open intervals, which do not include the endpoints, and brackets [ ] for closed intervals, which do include the endpoints.
In our case, the solution to the inequality x > -2/5 is an open interval because -2/5 is not included.
Therefore, the domain in interval notation is written as \((- \frac{2}{5}, \infty)\).
The left parenthesis indicates that -2/5 is not included, while the infinity symbol \(\infty\) suggests that there is no upper limit.
function domain
The domain of a function includes all the input values (x-values) that will produce a valid output.
For the logarithmic function \(f(x) = \text{ln}(5x + 2)\), the domain is determined by ensuring that the argument of \(\text{ln}\) remains positive.
This involves setting up and solving the inequality 5x + 2 > 0, which gives x > -2/5.
Therefore, the domain of \(\text{ln}(5x + 2)\) is all x such that x > -2/5.
In interval notation, we represent this as \((- \frac{2}{5}, \infty)\), indicating the range of x-values for which the function is defined.
For the logarithmic function \(f(x) = \text{ln}(5x + 2)\), the domain is determined by ensuring that the argument of \(\text{ln}\) remains positive.
This involves setting up and solving the inequality 5x + 2 > 0, which gives x > -2/5.
Therefore, the domain of \(\text{ln}(5x + 2)\) is all x such that x > -2/5.
In interval notation, we represent this as \((- \frac{2}{5}, \infty)\), indicating the range of x-values for which the function is defined.