Chapter 6: Problem 112
Solve each equation. $$ 4 e^{x+1}=5 $$
Short Answer
Expert verified
x = \( \text{ln}\bigg(\frac{5}{4}\bigg) - 1 \)
Step by step solution
01
Isolate the exponential term
Start by isolating the exponential term on one side of the equation. Divide both sides by 4 to get: \[ e^{x+1} = \frac{5}{4} \]
02
Apply the natural logarithm
Take the natural logarithm (\( \text{ln}() \)) of both sides to remove the exponent. This will give: \[ \text{ln}(e^{x+1}) = \text{ln}\bigg(\frac{5}{4}\bigg) \]
03
Simplify using logarithmic properties
Use the property \( \text{ln}(e^y) = y \) to simplify the left side of the equation: \[ x+1 = \text{ln}\bigg(\frac{5}{4}\bigg) \]
04
Solve for x
Subtract 1 from both sides to isolate \( x \): \[ x = \text{ln}\bigg(\frac{5}{4}\bigg) - 1 \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
exponential functions
Exponential functions are mathematical expressions where a constant base is raised to a variable exponent. The general form is \(a^x\), where 'a' is the base and 'x' is the exponent. These functions are pivotal because they grow very quickly.
For example, in the equation \(4e^{x+1} = 5\), \(e\) (approximately 2.718) is the base and \(x+1\) is the exponent. Exponential functions are commonly found in problems involving growth and decay.
Some properties include:
For example, in the equation \(4e^{x+1} = 5\), \(e\) (approximately 2.718) is the base and \(x+1\) is the exponent. Exponential functions are commonly found in problems involving growth and decay.
Some properties include:
- The value of an exponential function never reaches zero.
- It is always positive.
- Exponential growth means the function doubles at a consistent rate.
natural logarithm
The natural logarithm, denoted as \( \text{ln}() \), is a logarithm with base 'e'. It's an inverse operation to exponentiation with base 'e'. Applying \( \text{ln}() \) to both sides of an equation helps to 'undo' the exponentiation.
For instance, in the equation \[ e^{x+1} = \frac{5}{4} \], we apply \( \text{ln}() \) to both sides to get \[ \text{ln}(e^{x+1}) = \text{ln}\bigg( \frac{5}{4} \bigg) \].
This operation simplifies the problem efficiently.
Natural logarithms have several notable properties:
For instance, in the equation \[ e^{x+1} = \frac{5}{4} \], we apply \( \text{ln}() \) to both sides to get \[ \text{ln}(e^{x+1}) = \text{ln}\bigg( \frac{5}{4} \bigg) \].
This operation simplifies the problem efficiently.
Natural logarithms have several notable properties:
- \( \text{ln}(1) = 0 \)
- \( \text{ln}(e) = 1 \)
- \( \text{ln}(a \times b) = \text{ln}(a) + \text{ln}(b) \)
- \( \text{ln}(a^b) = b \times \text{ln}(a) \)
- They are the inverse of exponentiation: \( \text{ln}(e^x) = x \)
logarithmic properties
Logarithmic properties are essential tools for solving exponential equations. They help transform multiplicative relationships into additive ones, making equations easier to handle.
Key properties include:
By knowing how and when to apply these properties, solving exponential equations becomes a manageable task.
Key properties include:
- \( \text{ln}(a \times b) = \text{ln}(a) + \text{ln}(b) \)
- \( \text{ln}( \frac{a}{b} ) = \text{ln}(a) - \text{ln}(b) \)
- \( \text{ln}(a^b) = b \times \text{ln}(a) \)
- Inverse property: \( \text{ln}(e^x) = x \)
By knowing how and when to apply these properties, solving exponential equations becomes a manageable task.