/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 107 Solve each equation. $$ \log... [FREE SOLUTION] | 91影视

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Chapter 6: Problem 107

Solve each equation. $$ \log _{2} 8^{x}=-6 $$

Short Answer

Expert verified
x = -2

Step by step solution

01

Recall the properties of logarithms

Remember that logarithms have properties that can simplify expressions. One such property is \(\log_b(a^c) = c \log_b(a)\). This will help to simplify the given equation.
02

Apply the property to the given equation

We begin by applying the property \(\log_b(a^c) = c \log_b(a)\) to the equation \(\log_{2} 8^{x} = -6\). This simplifies to \(x \log_{2} 8 = -6\).
03

Calculate the logarithm

Next, determine the value of \(\log_{2} 8\). Since \(8 = 2^3\), we have \(\log_{2} 8 = \log_{2} 2^3 = 3\). This gives us the equation \(x \cdot 3 = -6\).
04

Solve for x

Now, solve the equation \(3x = -6\) by dividing both sides by 3: \(x = \frac{-6}{3} = -2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

logarithm properties
Understanding the properties of logarithms is key to solving logarithmic equations. One essential property is the power rule of logarithms, which states that \( \log_b(a^c) = c \log_b(a) \ \). This rule allows us to bring the exponent in a logarithmic expression to the front. Another important property is the change of base formula: \( \log_b(a) = \frac{\log_c(a)}{\log_c(b)} \ \). These properties help us simplify and solve logarithmic equations effectively.
solving equations
To solve logarithmic equations, we use logarithm properties to simplify. Let鈥檚 illustrate with our example. Given the equation \( \log_{2} 8^{x} = -6 \ \), we start by applying the logarithm power rule \( \log_b(a^c) = c \log_b(a) \ \). This transforms the given equation into \ x \log_{2} 8 = -6 \. Next, we calculate \ \log_{2} 8 \, knowing that 8 can be expressed as \ 2^3 \:. \ \log_{2} 8 = \log_{2} 2^3 = 3 \. Substituting back, we get \ 3x = -6 \. Finally, solve for \ x \ by dividing both sides by 3, resulting in \ x = -2 \$.
change of base formula
The change of base formula \(\frac{\log_c(a)}{\log_c(b)} \) is a handy tool when dealing with logarithms of different bases. If you need to evaluate a logarithm in a base that your calculator doesn't support directly, you can convert it using the change of base formula. For instance, to find \ \log_2 8 \, if your calculator only has base-10 or natural log (ln), you can use \ \log_2 8 = \frac{\log_{10} 8}{\log_{10} 2} \ or \ \log_2 8 = \frac{\ln 8}{\ln 2} \. This formula ensures flexibility and can assist in various logarithmic calculations.

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Most popular questions from this chapter

Strontium-90 is a radioactive material that decays according to the function \(A(t)=A_{0} e^{-0.0244 t}\) where \(A_{0}\) is the initial amount present and \(A\) is the amount present at time \(t\) (in years). Assume that a scientist has a sample of 500 grams of strontium-90. (a) What is the decay rate of strontium-90? (b) How much strontium-90 is left after 10 years? (c) When will 400 grams of strontium-90 be left? (d) What is the half-life of strontium-90?

Find an exponential function whose graph has the horizontal asymptote \(y=-3\) and contains the points (0,-2) and (-2,1).

The bacteria in a 4-liter container double every minute. After 60 minutes the container is full. How long did it take to fill half the container?

Uninhibited growth can be modeled by exponential functions other than \(A(t)=A_{0} e^{k t} .\) For example, if an initial population \(P_{0}\) requires \(n\) units of time to double, then the function \(P(t)=P_{0} \cdot 2^{t / n}\) models the size of the population at time t. Likewise, a population requiring \(n\) units of time to triple can be modeled by \(P(t)=P_{0} \cdot 3^{t / n}\). The population of a town is growing exponentially. (a) If its population doubled in size over an 8 -year period and the current population is 25,000 , write an exponential function of the form \(P(t)=P_{0} \cdot 2^{t / n}\) that models the population. (b) What will the population be in 3 years? (c) When will the population reach \(80,000 ?\) (d) Express the model from part (a) in the form \(A(t)=A_{0} e^{k t}\).

Based on material learned earlier in the course. The purpose of these problems is to keep the material fresh in your mind so that you are better prepared for the final exam. Solve: \(x-16 \sqrt{x}+48=0\)
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