/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 44 Find a polynomial function whose... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find a polynomial function whose real zeros and degree are given. Answers will vary depending on the choice of the leading coefficient. $$ \text { Zeros: }-4,0,2 ; \text { degree } 3 $$

Short Answer

Expert verified
\( f(x) = a(x^3 + 2x^2 - 8x) \)

Step by step solution

01

Identify the zeros

The real zeros given are \(-4, 0, 2\). These zeros will be the roots of our polynomial.
02

Write the factors

Since the polynomial has zeros at \(-4, 0, 2\), the factors are \((x + 4), x, (x - 2)\).
03

Form the polynomial

Multiply the factors to form the polynomial: \[ f(x) = a(x + 4)x(x - 2) \]Where \(a\) is the leading coefficient.
04

Expand the polynomial

Expand the product to obtain the polynomial. First expand two of the factors:\[ (x + 4)x = x^2 + 4x \]Then multiply by the remaining factor:\[ (x^2 + 4x)(x - 2) = x^3 - 2x^2 + 4x^2 - 8x \]Combine like terms:\[ x^3 + 2x^2 - 8x \]
05

Include the leading coefficient

Include the leading coefficient \(a\) in the polynomial: \[ f(x) = a(x^3 + 2x^2 - 8x) \]where \(a\) can be any real number other than zero.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Real Zeros
Real zeros of a polynomial function are the x-values at which the function equals zero. These values are also known as the roots or solutions of the polynomial equation.
For example, given the zeros -4, 0, and 2, these represent the points at which the polynomial touches or crosses the x-axis.
If you substitute these values into the polynomial, the result will be zero.
These zeros help us write the polynomial in factor form.
If:
  f(x) 
, the polynomial, is given by
 f(x) = a(x + 4)x(x - 2)
, where a is a leading coefficient.
By knowing the real zeros you can easily determine the factors.
Roots of Polynomials
Roots of a polynomial are the solutions to the equation formed when the polynomial is set equal to zero.
If you know the roots of a polynomial, you can express the polynomial as a product of linear factors. For instance, given the roots -4, 0, and 2 for a degree 3 polynomial, the polynomial can be expressed as:
 f(x) = a(x + 4)x(x - 2)
, where a is the leading coefficient.
Remember that the degree of the polynomial tells us the maximum number of roots it can have, including multiplicities.
This means a polynomial of degree 3 can have up to 3 real roots.
Understanding roots is crucial for both solving polynomial equations and analyzing their shapes.
Expanding Polynomial
Expanding a polynomial means expressing it as a sum of terms by multiplying its factors.
Let's consider the polynomial
 f(x) = a(x+4)x(x-2). 
To expand it, you would first multiply pairs of factors and then combine like terms.
First, multiply the first two factors:
 (x + 4)x = x^2 + 4x 
, and then multiply this result by the remaining factor:
 (x^2 + 4x)(x - 2) 
: Step by step: 1. Multiply the term x^2 by (x-2):
x^3 - 2x^2

2. Multiply the term 4x by (x-2):
4x^2 - 8x
.
3. Combine like terms to get the expanded form:
f(x) = x^3 + 2x^2 - 8x
,
with the leading coefficient a included, you'll get the general form of f(x) = a(x^3 + 2x^2 - 8x). Expanding a polynomial helps us to see each individual term, making it easier to compute values or perform other operations, like finding derivatives.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.