Chapter 4: Problem 11
True or False The \(y\) -coordinate of the vertex of \(f(x)=-x^{2}+4 x+5\) is \(f(2)\)
Short Answer
Expert verified
True
Step by step solution
01
Identify the standard form of a quadratic function
The given function is in the form of a quadratic function: ewline ewline \(f(x) = -x^{2} + 4x + 5 \). ewline ewline A quadratic function is generally represented as \(f(x) = ax^{2} + bx + c\). In this case, \(a = -1\), \(b = 4\), and \(c = 5\).
02
Find the x-coordinate of the vertex
The x-coordinate of the vertex of a quadratic function \(f(x) = ax^{2} + bx + c\) is given by the formula: ewline ewline \(x = -\frac{b}{2a}\). ewline ewline Substitute \(a = -1\) and \(b = 4\) into this formula: ewline ewline \(x = -\frac{4}{2(-1)}\) ewline \(x = 2\).
03
Find the y-coordinate of the vertex
To find the y-coordinate of the vertex, substitute the x-coordinate back into the original function \(f(x)\). In this case, substitute \(x = 2\) into \(f(x) = -x^{2} + 4x + 5\): ewline ewline \(f(2) = -(2)^{2} + 4(2) + 5\) ewline \(f(2) = -4 + 8 + 5\) ewline \(f(2) = 9\). ewline ewline Thus, the y-coordinate of the vertex is \(9\).
04
Analyze the given statement
The given statement claims that the y-coordinate of the vertex of \(f(x) = -x^{2} + 4x + 5\) is \(f(2)\). ewline ewline From the previous step, we found that \(f(2) = 9\), which is indeed the y-coordinate of the vertex. ewline ewline Therefore, the given statement is true.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
quadratic function
Understanding what a quadratic function is can aid in solving many mathematical problems. A quadratic function is a type of polynomial function where the highest degree of the variable is 2. This gives the function its characteristic parabolic shape. The general form of a quadratic function is represented as:
\textstyle f(x) = ax^2 + bx + c\textstyle<, where:
The quadratic function can open upwards or downwards depending on the sign of \(a\). If \(a > 0\), the parabola opens upwards. If \(a < 0\), it opens downwards. In our example, we have \(f(x) = -x^2 + 4x + 5\), which means:
\textstyle f(x) = ax^2 + bx + c\textstyle<, where:
- \(a\) is the coefficient of \(x^2\)
- \(b\) is the coefficient of \(x\)
- \(c\) is the constant term
The quadratic function can open upwards or downwards depending on the sign of \(a\). If \(a > 0\), the parabola opens upwards. If \(a < 0\), it opens downwards. In our example, we have \(f(x) = -x^2 + 4x + 5\), which means:
- \(a = -1\)
- \(b = 4\)
- \(c = 5\)
vertex formula
The vertex of a quadratic function is a crucial point on the graph of the function. It represents the minimum or maximum value the function can take. To determine this vertex, we use the vertex formula. The x-coordinate of the vertex for the quadratic function \(f(x) = ax^2 + bx + c\) is given by the formula:
\textstyle x = -\frac{b}{2a}\textstyle<.
Let's find the x-coordinate for our function where \(a = -1\) and \(b = 4\):
\textstyle x = -\frac{4}{2(-1)} = 2\textstyle<.
Having the x-coordinate of 2, we can now plug it into our function \(f(x) = -x^2 + 4x + 5\) to find the y-coordinate:
\textstyle f(2) = -(2)^2 + 4(2) + 5\textstyle<
= -4 + 8 + 5 = 9.
So, the vertex of the function is at \((2, 9)\). This means that at \(x = 2\), the function reaches its highest point (since the parabola opens downwards) which is \(y = 9\).
\textstyle x = -\frac{b}{2a}\textstyle<.
Let's find the x-coordinate for our function where \(a = -1\) and \(b = 4\):
\textstyle x = -\frac{4}{2(-1)} = 2\textstyle<.
Having the x-coordinate of 2, we can now plug it into our function \(f(x) = -x^2 + 4x + 5\) to find the y-coordinate:
\textstyle f(2) = -(2)^2 + 4(2) + 5\textstyle<
= -4 + 8 + 5 = 9.
So, the vertex of the function is at \((2, 9)\). This means that at \(x = 2\), the function reaches its highest point (since the parabola opens downwards) which is \(y = 9\).
standard form of quadratic
The standard form of a quadratic function is vital for understanding its properties and helping to find its vertex efficiently. The standard form is written as \(f(x) = ax^2 + bx + c\), where \(a\), \(b\), and \(c\) are constants. Knowing this allows us to easily apply the vertex formula and other techniques.
- This form makes it straightforward to identify the coefficients \(a\), \(b\), and \(c\).
- It simplifies the process of finding the vertex and factoring the quadratic if necessary.
- \(a = -1\)
- \(b = 4\)
- \(c = 5\)
For our specific function, \(f(x) = -x^2 + 4x + 5\), we recognized that: