/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 95 Draw the graph of a function tha... [FREE SOLUTION] | 91Ó°ÊÓ

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Draw the graph of a function that has the following properties: domain: all real numbers; range: all real numbers; intercepts: (0,-3) and (3,0)\(;\) a local maximum value of -2 at \(-1 ;\) a local minimum value of -6 at \(2 .\) Compare your graph with those of others. Comment on any differences.

Short Answer

Expert verified
A possible function is \( f(x) = -x^3 + x - 3 \). It meets all given properties including intercepts and local maxima/minima.

Step by step solution

01

- Determine the Function Type

Given the properties, propose a possible function type. Since the function has a local maximum and minimum, a polynomial function, specifically a cubic function, is a good candidate.
02

- Create General Form of the Function

A general cubic function can be written as: \[ f(x) = ax^3 + bx^2 + cx + d \]
03

- Use Intercepts to Form Equations

Utilize the y-intercept (0, -3) and x-intercept (3,0) to form equations: \[ f(0) = -3 \rightarrow d = -3 \]\[ f(3) = 0 \rightarrow 27a + 9b + 3c - 3 = 0 \]
04

- Use Critical Points

Calculate the first derivative of the function and set it to zero to find critical points:\[ f'(x) = 3ax^2 + 2bx + c \]Given maximum at x = -1:\[ f'(-1) = 0 \rightarrow 3a(-1)^2 + 2b(-1) + c = 0 \rightarrow 3a - 2b + c = 0 \]Given minimum at x = 2:\[ f'(2) = 0 \rightarrow 3a(2)^2 + 2b(2) + c = 0 \rightarrow 12a + 4b + c = 0 \]
05

- Solve the System of Equations

Solve the system of equations using the equations from intercept and critical points:\[ d = -3 \]\[ 27a + 9b + 3c - 3 = 0 \]\[ 3a - 2b + c = 0 \]\[ 12a + 4b + c = 0 \]
06

- Find Function Coefficients

After solving, determine the values of a, b, and c. One possible solution is:\[ a = -1, b = 0, c = 1 \]Thus, the function is: \[ f(x) = -x^3 + x - 3 \]
07

- Draw the Graph

Plot the cubic function \( f(x) = -x^3 + x - 3 \) on a graph, ensuring it meets the given properties.
08

- Compare with Others

Compare the graph with others. Differences may include minor variations in the shape based on different coefficients, but the general features (intercepts, local max/min) should be consistent.
09

- Comment on Differences

Comment on any differences observed, focusing on how alternative solutions also satisfy the function's properties using different coefficients or transformations.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polynomial Functions
Polynomial functions are mathematical expressions involving a sum of powers in one or more variables multiplied by coefficients. In our exercise, we are working with a cubic polynomial function, because cubic functions can have one local maximum and one local minimum. For a function to be a polynomial, its powers need to be whole numbers.

For a cubic function, the general form is: \[ f(x) = ax^3 + bx^2 + cx + d \]Here, a, b, c, and d are coefficients. Understanding how these coefficients change the shape of the graph is key.

For instance, the term \[ ax^3 \] determines the end behavior of the function - whether it goes to infinity or negative infinity as x becomes very large. The coefficient 'a' does more than just stretch or compress the graph; it determines whether the graph opens upwards (positive 'a') or downwards (negative 'a').

By analyzing polynomial functions, we can also understand the symmetry of the graph and potential points of inflection.
Graphing Techniques
When graphing polynomial functions like the cubic function \[ f(x) = -x^3 + x - 3 \], there are several essential techniques:

1. **Intercepts** - Determine where the function crosses the x-axis (x-intercepts) and y-axis (y-intercepts). Our given function has intercepts at (0, -3) and (3, 0). These points help in plotting the graph correctly.

2. **Critical Points** - Find the critical points by taking the first derivative and setting it equal to zero. This helps locate the local maxima and minima. For our function, the local maximum is at x = -1 and the local minimum is at x = 2.

3. **Behavior Analysis** - Examine the end behavior of the graph. Since our function is cubic, it has one tail going to positive or negative infinity and the other tail going to the opposite infinity.

4. **First Derivative Test** - Checking where the first derivative transitions from positive to negative or negative to positive helps us identify whether we have a local maximum or a minimum at the critical points.

By using these techniques, you can graph any polynomial function accurately.
Local Maximum and Minimum
Local maximums and minimums are specific points where the function reaches a highest or lowest value within a certain interval.

For our cubic function, the local maximum is at x = -1, with a value of -2. This means as you move left to right through x = -1, the function increases to -2 and then starts to decrease.

The local minimum is at x = 2, with a value of -6. This means as you move left to right through x = 2, the function decreases to -6 and then starts to increase.

To find these points analytically:
  • Take the derivative of the function.
  • Set it to zero to find potential maxima and minima.
  • Use the second derivative to confirm whether each critical point is indeed a maximum or minimum.
Here's the derivative of our function: \[ f'(x) = 3ax^2 + 2bx + c \]
We use the critical points found earlier (\[ f'(-1) = 0 \rightarrow 3a - 2b + c = 0 \] and \[ f'(2) = 0 \rightarrow 12a + 4b + c = 0 \]) to identify and confirm the local extrema.

Understanding local maxima and minima not only helps in graphing but also has applications in various optimization problems.

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Most popular questions from this chapter

Stopping Distance When the driver of a vehicle observes an impediment, the total stopping distance involves both the reaction distance \(R\) (the distance the vehicle travels while the driver moves his or her foot to the brake pedal) and the braking distance \(B\) (the distance the vehicle travels once the brakes are applied). For a car traveling at a speed of \(v\) miles per hour, the reaction distance \(R\), in feet, can be estimated by \(R(v)=2.2 v .\) Suppose that the braking distance \(B,\) in feet, for a car is given by \(B(v)=0.05 v^{2}+0.4 v-15\) (a) Find the stopping distance function $$ D(v)=R(v)+B(v) $$ (b) Find the stopping distance if the car is traveling at a speed of \(60 \mathrm{mph}\). (c) Interpret \(D(60)\)

Cost of Transatlantic Travel A Boeing 747 crosses the Atlantic Ocean (3000 miles) with an airspeed of 500 miles per hour. The cost \(C\) (in dollars) per passenger is given by $$ C(x)=100+\frac{x}{10}+\frac{36,000}{x} $$ where \(x\) is the ground speed (airspeed \(\pm\) wind). (a) What is the cost per passenger for quiescent (no wind) conditions? (b) What is the cost per passenger with a head wind of 50 miles per hour? (c) What is the cost per passenger with a tail wind of 100 miles per hour? (d) What is the cost per passenger with a head wind of 100 miles per hour?

Show that a constant function \(f(x)=b\) has an average rate of change of \(0 .\) Compute the average rate of change of \(y=\sqrt{4-x^{2}}\) on the interval \([-2,2] .\) Explain how this can happen.

Find the function that is finally graphed after each of the following transformations is applied to the graph of \(y=\sqrt{x}\) in the order stated. (1) Vertical stretch by a factor of 3 (2) Shift up 4 units (3) Shift left 5 units

The slope of the secant line containing the two points \((x, f(x))\) and \((x+h, f(x+h))\) on the graph of a function \(y=f(x)\) may be given as \(m_{\mathrm{sec}}=\frac{f(x+h)-f(x)}{(x+h)-x}=\frac{f(x+h)-f(x)}{h} \quad h \neq 0\) (a) Express the slope of the secant line of each function in terms of \(x\) and \(h\). Be sure to simplify your answer. (b) Find \(m_{\text {sec }}\) for \(h=0.5,0.1\), and 0.01 at \(x=1 .\) What value does \(m_{\text {sec }}\) approach as h approaches \(0 ?\) (c) Find an equation for the secant line at \(x=1\) with \(h=0.01\). (d) Use a graphing utility to graph fand the secant line found in part ( \(c\) ) in the same viewing window. Problems \(85-92\) require the following discussion of a secant line. The slope of the secant line containing the two points \((x, f(x))\) and \((x+h, f(x+h))\) on the graph of a function \(y=f(x)\) may be given as \(m_{\mathrm{sec}}=\frac{f(x+h)-f(x)}{(x+h)-x}=\frac{f(x+h)-f(x)}{h} \quad h \neq 0\) (a) Express the slope of the secant line of each function in terms of \(x\) and \(h\). Be sure to simplify your answer. (b) Find \(m_{\text {sec }}\) for \(h=0.5,0.1\), and 0.01 at \(x=1 .\) What value does \(m_{\text {sec }}\) approach as h approaches \(0 ?\) (c) Find an equation for the secant line at \(x=1\) with \(h=0.01\). (d) Use a graphing utility to graph fand the secant line found in part ( \(c\) ) in the same viewing window. \(f(x)=x^{2}+2 x\)

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