Chapter 3: Problem 69
Complete the square of each quadratic expression. Then graph each function using graphing techniques. $$ f(x)=2 x^{2}-12 x+19 $$
Short Answer
Expert verified
The function in vertex form is \( f(x) = 2(x - 3)^{2} + 1 \) with vertex \((3, 1)\).
Step by step solution
01
Identify the Quadratic Coefficient
Given the quadratic expression is in the form: \[ f(x) = ax^{2} + bx + c \] where \(a = 2\), \(b = -12\), and \(c = 19\). The first step is to identify these coefficients.
02
Factor Out the Leading Coefficient from the First Two Terms
Factor out the coefficient of the \(x^{2}\) term (which is 2) from the first two terms in the expression: \[ f(x) = 2(x^{2} - 6x) + 19 \].
03
Complete the Square
To complete the square, take half of the coefficient of \(x\) (which is -6), square it, and add and subtract this value inside the parentheses: \[ x^{2} - 6x \rightarrow x^{2} - 6x + 9 - 9 \]. This results in: \[ f(x) = 2(x^{2} - 6x + 9 - 9) + 19 \] or \[ f(x) = 2((x - 3)^{2} - 9) + 19 \].
04
Simplify the Expression
Distribute the 2 and combine like terms: \[ f(x) = 2(x - 3)^{2} - 18 + 19 \]. This simplifies to: \[ f(x) = 2(x - 3)^{2} + 1 \]. The quadratic is now in the form \(a(x - h)^{2} + k\), which makes it easier to graph.
05
Determine the Vertex and Graph the Function
The vertex form of the quadratic equation \(f(x) = 2(x - 3)^{2} + 1\) reveals the vertex \((h, k) = (3, 1)\). The coefficient 2 indicates a vertical stretch. Hence, the parabola opens upwards with the vertex at (3, 1). Plot the vertex and additional points, then draw the parabola to graph the function.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Expression
A quadratic expression is a polynomial of degree 2. This means the highest power of the variable (usually x) is 2. In general form, a quadratic expression is written as: \[ ax^{2} + bx + c \] where:
- a, b, and c are constants
- x is the variable
Vertex Form
The vertex form of a quadratic expression is especially useful for graphing. The vertex form is given by: \[ f(x) = a(x - h)^{2} + k \] where:
- (h, k) is the vertex of the parabola
- a determines the 'vertical stretch' or 'compression'
Graphing Quadratic Functions
Graphing quadratic functions becomes simpler once you have the function in vertex form. The steps for graphing are as follows:
- Identify the vertex (h, k)
- Determine the direction of the parabola (upwards if a > 0, downwards if a < 0)
- Identify the vertical stretch or compression
Parabola Vertex
The vertex of a parabola gives you the highest or lowest point, depending on the direction it opens. It’s a crucial point in graphing as it helps to understand the shape and position. From the vertex form \[ f(x) = a(x - h)^{2} + k \], the vertex is simply given by:
- \[ h \] is the value that makes \[ (x - h)^{2} \] zero
- \[ k \] is the value of the function at \[ x = h \]
Vertical Stretch
The coefficient 'a' in the quadratic expression affects how 'stretched' or 'compressed' the parabola is vertically. When \[ |a| > 1 \], the parabola is vertically stretched, making it narrower. When \[ 0 < |a| < 1 \], the parabola is compressed, making it wider. For our function, \[ f(x) = 2(x - 3)^{2} + 1 \], the coefficient 2 indicates a vertical stretch. This means the parabola will be narrower compared to \[ f(x) = (x - 3)^{2} + 1 \]. This vertical stretch influences the curvature of the graph and directly impacts how steep or shallow the parabola appears.