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91Ó°ÊÓ

Determine algebraically whether each function is even, odd, or neither. \(f(x)=x+|x|\)

Short Answer

Expert verified
Neither

Step by step solution

01

Definition of Even and Odd Functions

A function is even if it satisfies the condition \[ f(x) = f(-x) \] for all x in its domain. A function is odd if it satisfies the condition \[ f(-x) = -f(x) \] for all x in its domain.
02

Substitute -x into the Function

To determine if the function \[ f(x) = x + |x| \] is even or odd, substitute \[ -x \] into the function: \[ f(-x) = -x + |-x| \].
03

Simplify the Expression for f(-x)

Recall that the absolute value function \[ |x| \] is always non-negative. Hence, \[ |-x| = |x| \]. Now simplify \[ f(-x) = -x + |x| \].
04

Compare f(x) and f(-x)

Compare \[ f(x) = x + |x| \] with \[ f(-x) = -x + |x| \].
05

Determine If Function is Even, Odd or Neither

Since \[ f(x) \] does not equal \[ f(-x) \] (i.e., \[ x + |x| eq -x + |x| \]), the function is not even. Similarly, \[ f(-x) \] does not equal \[ -f(x) \] (i.e., \[ -x + |x| eq -(x + |x|) \]), so the function is not odd either.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Algebraic Functions
An algebraic function is a function that can be defined using basic algebraic operations such as addition, subtraction, multiplication, and division, as well as taking roots. These functions are typically composed of polynomials and can include variables with exponents.
In our exercise, the function given is: \[ f(x) = x + |x| \]
This is an algebraic function because it involves basic algebraic operations and the absolute value of a variable. Understanding how to manipulate these types of functions is essential for solving various kinds of problems in math.

Key points to consider:
  • Algebraic operations are the building blocks of algebraic functions.
  • They can be visualized using graphs.
  • Knowing how algebraic functions behave helps solve equations and inequalities.
Absolute Value
The absolute value function, denoted as \(|x|\), measures the distance of a number from zero on the number line, ignoring direction. Therefore, \(|x|\) is always non-negative. For any real number \(x\), \(|x| = x\) if \(x \geq 0\), and \(|x| = -x\) if \(x < 0\).
In our function, \(f(x) = x + |x|\), understanding the absolute value is crucial because it affects how we interpret \(f(-x)\).
When substituting \(-x\) into the absolute value function:
\( f(-x) = -x + |-x| = -x + |x| \)
This reveals that the function combines linear and absolute value terms, and their interaction depending on the sign of \(x\) will determine the overall behavior of \(f(x)\).
Function Symmetry
The symmetry of a function helps in determining whether a function is even, odd, or neither. For a function \(f(x)\):
**Even Function:** \(f(x) = f(-x)\). This implies that the function is symmetric about the y-axis.
**Odd Function:** \(f(-x) = -f(x)\). This implies that the function has rotational symmetry about the origin.
**Neither:** If a function does not satisfy either condition, it is neither even nor odd.
For our function:
\[ f(x) = x + |x| \text{ and } f(-x) = -x + |x| \]
Clearly, \(f(x)\) does not equal \(f(-x)\) and \(f(-x)\) does not equal \(-f(x)\), indicating the function is neither even nor odd. Understanding such symmetry can be valuable for graphing and integration.
Key points:
  • Even functions have y-axis symmetry.
  • Odd functions have origin symmetry.
  • Symmetry is a powerful tool in solving and simplifying problems.
Domain and Range
The domain of a function is the set of all possible input values (x-values) for which the function is defined. The range is the set of all possible output values (y-values). For our function \(f(x) = x + |x|\), both domain and range are straightforward.

The **domain** of \(f(x)\) is all real numbers (\(\textbf{R}\)) because we can substitute any real number for \(x\) in the expression \(x + |x|\).
The **range** of \(f(x)\) also turns out to be all real numbers (\(\textbf{R}\)), because the combination of linear and absolute value terms can produce any real number output depending on positive or negative inputs.
  • The domain gives us the permissible x-values.
  • The range tells us the possible y-values.
  • Understanding these concepts ensures a function is well-defined and helps in graphing it correctly.

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Most popular questions from this chapter

Minimum Payments for Credit Cards Holders of credit cards issued by banks, department stores, oil companies, and so on, receive bills each month that state minimum amounts that must be paid by a certain due date. The minimum due depends on the total amount owed. One such credit card company uses the following rules: For a bill of less than $$\$ 10$$ the entire amount is due. For a bill of at least $$\$ 10$$ but less than $$\$ 500$$, the minimum due is $$\$ 10$$. A minimum of $$\$ 30$$ is due on a bill of at least $$\$ 500$$ but less than $$\$ 1000$$, a minimum of $$\$ 50$$ is due on a bill of at least $$\$ 1000$$ but less than $$\$ 1500,$$ and a minimum of $$\$ 70$$ is due on bills of $$\$ 1500$$ or more. Find the function \(f\) that describes the minimum payment due on a bill of \(x\) dollars. Graph \(f\)

Use a graphing utility. Graph \(y=x^{3}\). Then on the same screen graph \(y=(x-1)^{3}+2\). Could you have predicted the result?

Show that a constant function \(f(x)=b\) has an average rate of change of \(0 .\) Compute the average rate of change of \(y=\sqrt{4-x^{2}}\) on the interval \([-2,2] .\) Explain how this can happen.

The slope of the secant line containing the two points \((x, f(x))\) and \((x+h, f(x+h))\) on the graph of a function \(y=f(x)\) may be given as \(m_{\mathrm{sec}}=\frac{f(x+h)-f(x)}{(x+h)-x}=\frac{f(x+h)-f(x)}{h} \quad h \neq 0\) (a) Express the slope of the secant line of each function in terms of \(x\) and \(h\). Be sure to simplify your answer. (b) Find \(m_{\text {sec }}\) for \(h=0.5,0.1\), and 0.01 at \(x=1 .\) What value does \(m_{\text {sec }}\) approach as h approaches \(0 ?\) (c) Find an equation for the secant line at \(x=1\) with \(h=0.01\). (d) Use a graphing utility to graph fand the secant line found in part ( \(c\) ) in the same viewing window. Problems \(85-92\) require the following discussion of a secant line. The slope of the secant line containing the two points \((x, f(x))\) and \((x+h, f(x+h))\) on the graph of a function \(y=f(x)\) may be given as \(m_{\mathrm{sec}}=\frac{f(x+h)-f(x)}{(x+h)-x}=\frac{f(x+h)-f(x)}{h} \quad h \neq 0\) (a) Express the slope of the secant line of each function in terms of \(x\) and \(h\). Be sure to simplify your answer. (b) Find \(m_{\text {sec }}\) for \(h=0.5,0.1\), and 0.01 at \(x=1 .\) What value does \(m_{\text {sec }}\) approach as h approaches \(0 ?\) (c) Find an equation for the secant line at \(x=1\) with \(h=0.01\). (d) Use a graphing utility to graph fand the secant line found in part ( \(c\) ) in the same viewing window. \(f(x)=2 x^{2}-3 x+1\)

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