/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 43 Determine algebraically whether ... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine algebraically whether each function is even, odd, or neither. \(f(x)=x+|x|\)

Short Answer

Expert verified
Neither

Step by step solution

01

Definition of Even and Odd Functions

A function is even if it satisfies the condition \[ f(x) = f(-x) \] for all x in its domain. A function is odd if it satisfies the condition \[ f(-x) = -f(x) \] for all x in its domain.
02

Substitute -x into the Function

To determine if the function \[ f(x) = x + |x| \] is even or odd, substitute \[ -x \] into the function: \[ f(-x) = -x + |-x| \].
03

Simplify the Expression for f(-x)

Recall that the absolute value function \[ |x| \] is always non-negative. Hence, \[ |-x| = |x| \]. Now simplify \[ f(-x) = -x + |x| \].
04

Compare f(x) and f(-x)

Compare \[ f(x) = x + |x| \] with \[ f(-x) = -x + |x| \].
05

Determine If Function is Even, Odd or Neither

Since \[ f(x) \] does not equal \[ f(-x) \] (i.e., \[ x + |x| eq -x + |x| \]), the function is not even. Similarly, \[ f(-x) \] does not equal \[ -f(x) \] (i.e., \[ -x + |x| eq -(x + |x|) \]), so the function is not odd either.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Algebraic Functions
An algebraic function is a function that can be defined using basic algebraic operations such as addition, subtraction, multiplication, and division, as well as taking roots. These functions are typically composed of polynomials and can include variables with exponents.
In our exercise, the function given is: \[ f(x) = x + |x| \]
This is an algebraic function because it involves basic algebraic operations and the absolute value of a variable. Understanding how to manipulate these types of functions is essential for solving various kinds of problems in math.

Key points to consider:
  • Algebraic operations are the building blocks of algebraic functions.
  • They can be visualized using graphs.
  • Knowing how algebraic functions behave helps solve equations and inequalities.
Absolute Value
The absolute value function, denoted as \(|x|\), measures the distance of a number from zero on the number line, ignoring direction. Therefore, \(|x|\) is always non-negative. For any real number \(x\), \(|x| = x\) if \(x \geq 0\), and \(|x| = -x\) if \(x < 0\).
In our function, \(f(x) = x + |x|\), understanding the absolute value is crucial because it affects how we interpret \(f(-x)\).
When substituting \(-x\) into the absolute value function:
\( f(-x) = -x + |-x| = -x + |x| \)
This reveals that the function combines linear and absolute value terms, and their interaction depending on the sign of \(x\) will determine the overall behavior of \(f(x)\).
Function Symmetry
The symmetry of a function helps in determining whether a function is even, odd, or neither. For a function \(f(x)\):
**Even Function:** \(f(x) = f(-x)\). This implies that the function is symmetric about the y-axis.
**Odd Function:** \(f(-x) = -f(x)\). This implies that the function has rotational symmetry about the origin.
**Neither:** If a function does not satisfy either condition, it is neither even nor odd.
For our function:
\[ f(x) = x + |x| \text{ and } f(-x) = -x + |x| \]
Clearly, \(f(x)\) does not equal \(f(-x)\) and \(f(-x)\) does not equal \(-f(x)\), indicating the function is neither even nor odd. Understanding such symmetry can be valuable for graphing and integration.
Key points:
  • Even functions have y-axis symmetry.
  • Odd functions have origin symmetry.
  • Symmetry is a powerful tool in solving and simplifying problems.
Domain and Range
The domain of a function is the set of all possible input values (x-values) for which the function is defined. The range is the set of all possible output values (y-values). For our function \(f(x) = x + |x|\), both domain and range are straightforward.

The **domain** of \(f(x)\) is all real numbers (\(\textbf{R}\)) because we can substitute any real number for \(x\) in the expression \(x + |x|\).
The **range** of \(f(x)\) also turns out to be all real numbers (\(\textbf{R}\)), because the combination of linear and absolute value terms can produce any real number output depending on positive or negative inputs.
  • The domain gives us the permissible x-values.
  • The range tells us the possible y-values.
  • Understanding these concepts ensures a function is well-defined and helps in graphing it correctly.

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Most popular questions from this chapter

Effect of Gravity on Earth If a rock falls from a height of 20 meters on Earth, the height \(H\) (in meters) after \(x\) seconds is approximately $$ H(x)=20-4.9 x^{2} $$ (a) What is the height of the rock when \(x=1\) second? When \(x=1.1\) seconds? When \(x=1.2\) seconds? (b) When is the height of the rock 15 meters? When is it 10 meters? When is it 5 meters? (c) When does the rock strike the ground?

Answer the questions about each function. $$f(x)=\frac{12 x^{4}}{x^{2}+1}$$ (a) Is the point (-1,6) on the graph of \(f ?\) (b) If \(x=3,\) what is \(f(x) ?\) What point is on the graph of \(f ?\) (c) If \(f(x)=1,\) what is \(x ?\) What point(s) are on the graph of \(f ?\) (d) What is the domain of \(f ?\) (e) List the \(x\) -intercepts, if any, of the graph of \(f\). (f) List the \(y\) -intercept, if there is one, of the graph of \(f\).

\(G(x)=-x^{4}+32 x^{2}+144\) (a) Determine whether \(G\) is even, odd, or neither. (b) There is a local maximum value of 400 at \(x=4\). Find a second local maximum value. (c) Suppose the area of the region enclosed by the graph of \(G\) and the \(x\) -axis between \(x=0\) and \(x=6\) is 1612.8 square units. Using the result from (a), determine the area of the region enclosed by the graph of \(G\) and the \(x\) -axis between \(x=-6\) and \(x=0\).

(a) Find the domain of each function. (b) Locate any intercepts. (c) Graph each function. (d) Based on the graph, find the range. $$f(x)=\left\\{\begin{array}{ll}2 x & \text { if } x \neq 0 \\\1 & \text { if } x=0\end{array}\right.$$

The slope of the secant line containing the two points \((x, f(x))\) and \((x+h, f(x+h))\) on the graph of a function \(y=f(x)\) may be given as \(m_{\mathrm{sec}}=\frac{f(x+h)-f(x)}{(x+h)-x}=\frac{f(x+h)-f(x)}{h} \quad h \neq 0\) (a) Express the slope of the secant line of each function in terms of \(x\) and \(h\). Be sure to simplify your answer. (b) Find \(m_{\text {sec }}\) for \(h=0.5,0.1\), and 0.01 at \(x=1 .\) What value does \(m_{\text {sec }}\) approach as h approaches \(0 ?\) (c) Find an equation for the secant line at \(x=1\) with \(h=0.01\). (d) Use a graphing utility to graph fand the secant line found in part ( \(c\) ) in the same viewing window. Problems \(85-92\) require the following discussion of a secant line. The slope of the secant line containing the two points \((x, f(x))\) and \((x+h, f(x+h))\) on the graph of a function \(y=f(x)\) may be given as \(m_{\mathrm{sec}}=\frac{f(x+h)-f(x)}{(x+h)-x}=\frac{f(x+h)-f(x)}{h} \quad h \neq 0\) (a) Express the slope of the secant line of each function in terms of \(x\) and \(h\). Be sure to simplify your answer. (b) Find \(m_{\text {sec }}\) for \(h=0.5,0.1\), and 0.01 at \(x=1 .\) What value does \(m_{\text {sec }}\) approach as h approaches \(0 ?\) (c) Find an equation for the secant line at \(x=1\) with \(h=0.01\). (d) Use a graphing utility to graph fand the secant line found in part ( \(c\) ) in the same viewing window. \(f(x)=x^{2}+2 x\)

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