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Let \(P=(x, y)\) be a point on the graph of \(y=x^{2}-8\) (a) Express the distance \(d\) from \(P\) to the point (0,-1) as a function of \(x\). (b) What is \(d\) if \(x=0 ?\) (c) What is \(d\) if \(x=-1 ?\) (d) Use a graphing utility to graph \(d=d(x)\). (e) For what values of \(x\) is \(d\) smallest?

Short Answer

Expert verified
(a) \(d = \sqrt{x^4 - 13x^2 + 49}\) (b) \(d = 7\) (c) \(d = \sqrt{37}\) (d) Graph the function \(d(x)\). (e) \(d\) is minimized at \(x = 0\).

Step by step solution

01

Express the coordinates of point P in terms of x

Given point P on the graph of the function, point P can be expressed as \(P = (x, x^2 - 8)\).
02

Write the distance formula

The distance \(d\) between point \(P\) and point \((0, -1)\) can be calculated using the distance formula: \( d = \sqrt{(x - 0)^2 + (y + 1)^2} \).
03

Substitute the coordinates of point P

Substitute \(x\) for \(x\) and \(x^2 - 8\) for \(y\) into the distance formula: \[ d = \sqrt{x^2 + ((x^2 - 8) + 1)^2} \].
04

Simplify the expression

Simplify the expression inside the distance formula: \[ d = \sqrt{x^2 + (x^2 - 7)^2} \].
05

Expand and simplify further

Expand the inner square term and simplify: \[ d = \sqrt{x^2 + x^4 - 14x^2 + 49} \]\[ d = \sqrt{x^4 - 13x^2 + 49} \].
06

Substitute x = 0

Substitute \(x = 0\) in the function to find \(d\): \[ d = \sqrt{0^4 - 13(0)^2 + 49} = \sqrt{49} = 7 \].
07

Substitute x = -1

Substitute \(x = -1\) in the function to find \(d\): \[ d = \sqrt{(-1)^4 - 13(-1)^2 + 49} = \sqrt{1 - 13 + 49} = \sqrt{37} \].
08

Graph the function

Use a graphing utility to graph the function \(d(x) = \sqrt{x^4 - 13x^2 + 49}\).
09

Determine for what values of x is d smallest

By analyzing or using the graphing utility, find the values of \(x\) that minimize the distance function \(d(x)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

distance formula
To understand the distance formula, consider two points in a coordinate plane: Point A \((x_1, y_1)\) and Point B \((x_2, y_2)\). The distance \(d\) between these points is given by the formula:
\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]
This formula is derived from the Pythagorean theorem applied to the horizontal and vertical distances between the points. It calculates the straight-line distance.
In our exercise, we use the distance formula to find the distance between a point \(P = (x, y)\) on the curve \((y=x^2-8)\) and the fixed point \( (0, -1)\).
By substituting \((x, x^2 - 8)\) for \(P\) and \((0, -1)\) for the other point, our formula becomes:
\[ d = \sqrt{x^2 + ((x^2 - 8) + 1)^2} \]
Simplifying this, we get:
\[ d = \sqrt{x^4 - 13x^2 + 49} \]
This expression helps in finding specific distances when \(x\) is 0 or -1, and also aids in graphing the distance function.
graphing functions
Graphing functions is a central concept in algebra and trigonometry. It involves plotting the values of a function to visualize its behavior. In this exercise, we graph the distance function:
\[ d(x) = \sqrt{x^4 - 13x^2 + 49} \]
To graph a function, follow these steps:
  • Identify the domain of the function—values for which the function is defined.
  • Calculate specific points by substituting various \(x\) values into the function.
  • Plot these points on a coordinate system.
  • Connect the points smoothly following the function's trend.

Using a graphing utility simplifies this process, as it can automatically produce the graph when you input the function.
In our case, using such a utility, we can see how \d(x)\ behaves for different \x\ values and identify where the function reaches its minimum value, which helps answer part (e) of the exercise.
minimizing functions
Minimizing a function means finding the input value (or values) where the function reaches its lowest point. This is often crucial in problems involving optimization.
For the function \d(x) = \sqrt{x^4 - 13x^2 + 49}\, we want to determine the \x\ value(s) that yield the smallest distance.
Here's the approach to minimize the function:
  • Graph the function to visually identify the minima.
  • Use calculus techniques, such as finding the derivative \(d'(x)\), and setting it to 0 to find critical points: \[ d'(x) = \frac{d}{dx}\left( \sqrt{x^4 - 13x^2 + 49} \right) = 0 \] .
  • Analyze these critical points to determine which gives the minimum value.

In our exercise, using these methods, we determine that \d(x)\ has its smallest value at specific \x\ values, providing a clear solution to part (e). Understanding minima gives insights into the behavior of functions and their practical applications in various fields.

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