/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 Multiple Choice To test whether ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Multiple Choice To test whether the graph of an equation is symmetric with respect to the origin, replace __________ in the equation and simplify. If an equivalent equation results, then the graph is symmetric with respect to the origin. \ (a) \(x\) by \(-x\) (b) \(y\) by \(-y\) (c) \(x\) by \(-x\) and \(y\) by \(-y\) (d) \(x\) by \(-y\) and \(y\) by \(-x\)

Short Answer

Expert verified
(c) Replace both \(x\) and \(-x\), and \(y\) with \(-y\)

Step by step solution

01

Understanding Symmetry with Respect to the Origin

For a graph to be symmetric with respect to the origin, it means that if a point \((x, y)\) exists on the graph, then the point \((-x, -y)\) must also exist on the graph. This involves changing both the x-coordinate and the y-coordinate to their opposites.
02

Apply Changes to the Equation

Replace every occurrence of \(x\) with \(-x\) and \(y\) with \(-y\) in the equation.
03

Check for Equivalence

Simplify the resulting equation. If the simplified equation is identical to the original equation, then the graph is symmetric with respect to the origin.
04

Correct Answer Identification

According to our understanding and steps outlined, the correct choice must replace both \(x\) and \(y\) with their negatives.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

graph symmetry
Graph symmetry is an important concept in understanding the visual properties of equations. There are different types of symmetries such as symmetry about the x-axis, symmetry about the y-axis, and symmetry about the origin. For symmetry with respect to the origin, if a point \((x, y)\) is on the graph, then the point \((-x, -y)\) must also be present. This means that the graph looks the same if it's rotated 180 degrees around the origin. To test this symmetry, we replace every \(x\) with \(-x\) and every \(y\) with \(-y\) in the equation and check if the resulting equation is the same as the original.
equation transformation
The process of checking for symmetry involves transforming the equation. To test for origin symmetry, we perform the following steps:
  • Replace every \(x\) in the equation with \(-x\).
  • Replace every \(y\) in the equation with \(-y\).

Let's say we start with an equation like \(y = x^2 + 1\). After transforming, we get \(-y = (-x)^2 + 1\). Simplifying this, we find \(-y = x^2 + 1\). This transformed equation is not the same as the original, meaning the graph is not symmetric with respect to the origin. You must always simplify and compare with the original to confirm.
coordinate changes
Making coordinate changes is a crucial part of testing symmetry. Here, we swap \(x\) for \(-x\) and \(y\) for \(-y\). This flips the coordinates over both the x-axis and y-axis, effectively rotating them by 180 degrees around the origin. Understanding this, if you have the equation \(x^2 + y^2 = 1\), and you replace \(x\) with \(-x\) and \(-y\), it remains the same: \((-x)^2 + (-y)^2 = 1\). As the squares of the negatives are equal to the squares of the positives, the equation retains its original form under these changes.
algebra
Algebra is the mathematical study that helps us simplify and manipulate equations to check for symmetry. When you replace \(-x\) and \(-y\), you apply your algebraic skills to simplify the expression. Your goal is to determine if the new equation is algebraically equivalent to the original. For example, consider \( y = x^3\). Apply the changes: \(-y = (-x)^3\) simplifies to \(-y = -x^3\). This new equation \(-y = -x^3\) does match the form of the original \(y = x^3\) when multiplied by -1, confirming symmetry. Mastery of algebra allows you to navigate through these transformations and verifications with confidence.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

U.S. Advertising Share A report showed that Internet ads accounted for \(19 \%\) of all U.S. advertisement spending when print ads (magazines and newspapers) accounted for \(26 \%\) of the spending. The report further showed that Internet ads accounted for \(35 \%\) of all advertisement spending when print ads accounted for \(16 \%\) of the spending. (a) Write a linear equation that relates that percent \(y\) of print ad spending to the percent \(x\) of Internet ad spending. (b) Find the intercepts of the graph of your equation. (c) Do the intercepts have any meaningful interpretation? (d) Predict the percent of print ad spending if Internet ads account for \(39 \%\) of all advertisement spending in the United States.

Are based on material learned earlier in the course. The purpose of these problems is to keep the material fresh in your mind so that you are better prepared for the final exam. Rationalize the denominator: $$ \frac{\sqrt{x+1}+\sqrt{x}}{\sqrt{x+1}-\sqrt{x}} $$

If the equation of a circle is \(x^{2}+y^{2}=r^{2}\) and the equation of a tangent line is \(y=m x+b,\) show that: (a) \(r^{2}\left(1+m^{2}\right)=b^{2}\) [Hint: The quadratic equation \(x^{2}+(m x+b)^{2}=r^{2}\) has exactly one solution.] (b) The point of tangency is \(\left(\frac{-r^{2} m}{b}, \frac{r^{2}}{b}\right)\). (c) The tangent line is perpendicular to the line containing the center of the circle and the point of tangency.

Cost Equation The fixed costs of operating a business are the costs incurred regardless of the level of production. Fixed costs include rent, fixed salaries, and costs of leasing machinery. The variable costs of operating a business are the costs that change with the level of output. Variable costs include raw materials, hourly wages, and electricity. Suppose that a manufacturer of jeans has fixed daily costs of \(\$ 1200\) and variable costs of \(\$ 20\) for each pair of jeans manufactured. Write a linear equation that relates the daily cost \(C,\) in dollars, of manufacturing the jeans to the number \(x\) of jeans manufactured. What is the cost of manufacturing 400 pairs of jeans? 740 pairs?

Can the equation of every line be written in slope-intercept form? Why?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.