/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 Graph \((x-2)^{2}+(y+1)^{2}=9\)... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Graph \((x-2)^{2}+(y+1)^{2}=9\)

Short Answer

Expert verified
The graph is a circle centered at (2, -1) with a radius of 3.

Step by step solution

01

Identify the Type of Graph

The given equation \((x-2)^{2}+(y+1)^{2}=9\) is in the form of the standard equation of a circle \((x-h)^{2}+(y-k)^{2}=r^{2}\).
02

Determine the Center of the Circle

From the standard equation \((x-h)^{2}+(y-k)^{2}=r^{2}\), compare and identify the center (h, k). Here, \(h = 2\) and \(k = -1\). Thus, the center of the circle is (2, -1).
03

Calculate the Radius

Compare the equation \((x-2)^{2}+(y+1)^{2}=9\) to the standard form. We identify \(r^2 = 9\), so the radius \(r = \sqrt{9} = 3\).
04

Plot the Graph

With the center at (2, -1) and a radius of 3, plot the point (2, -1) on a coordinate plane and draw a circle with a radius of 3 units around this center.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

standard equation of a circle
The standard equation of a circle is crucial in understanding how to graph a circle. It is generally written as \( (x-h)^{2}+(y-k)^{2}=r^{2} \). In this form:
\[(x-h)^{2}+(y-k)^{2}=r^{2}\]

Where:
  • \

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.