Chapter 12: Problem 49
Find the partial fraction decomposition of each rational expression. $$ \frac{2 x+3}{x^{4}-9 x^{2}} $$
Short Answer
Expert verified
\[\frac{2x + 3}{x^4 - 9x^2} = \frac{-2/3}{x} + \frac{-1/3}{x^2} + \frac{2/3}{x + 3} + \frac{2/3}{x - 3}\]
Step by step solution
01
Factor the Denominator
First, factor the denominator. The given denominator is \(x^4 - 9x^2\). This can be factored as follows:\[ x^4 - 9x^2 = x^2 (x^2 - 9) = x^2 (x + 3)(x - 3)\] So, the factored form of the denominator is \(x^2 (x + 3)(x - 3)\).
02
Write the Partial Fraction Decomposition Form
Express the given fraction as a sum of partial fractions. Since the denominator is \(x^2 (x + 3)(x - 3)\), the partial fraction decomposition will have terms involving these factors:\[ \frac{2x + 3}{x^4 - 9x^2} = \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x + 3} + \frac{D}{x - 3}\] where \(A\), \(B\), \(C\), and \(D\) are constants to be determined.
03
Create a Common Denominator
Multiply each term by the common denominator \(x^2 (x + 3)(x - 3)\) to clear the fractions:\[2x + 3 = A x (x+3)(x-3) + B (x+3)(x-3) + C x^2 (x-3) + D x^2 (x+3)\]
04
Expand and Collect Like Terms
Expand each term on the right-hand side to simplify:\[2x + 3 = A (x^3 - 3x) + B (x^2 - 9) + C x^3 - 3C x^2 + D x^3 + 3D x^2\]Combine like terms:\[2x + 3 = (A + C + D)x^3 + (-3A - 3C + 3D)x^2 + (-3A + 0B)x + (-9B)\]
05
Equate Coefficients
Compare the coefficients of like terms on both sides of the equation:For the coefficient of \(x^3\):\[0 = A + C + D\]For the coefficient of \(x^2\):\[0 = -3A - 3C + 3D\]For the coefficient of \(x\):\[2 = -3A\]For the constant term:\[3 = -9B\]
06
Solve the System of Equations
Solve the system of equations to find the values of \(A\), \(B\), \(C\), and \(D\):From \(2 = -3A\):\[A = -\frac{2}{3}\]From \(3 = -9B\):\[B = -\frac{1}{3}\]Substitute \(A = -\frac{2}{3}\) into the other equations:From \(0 = A + C + D\):\[0 = -\frac{2}{3} + C + D\Rightarrow C + D = \frac{2}{3}\]From \(0 = -3A - 3C + 3D\):\[0 = -3(-\frac{2}{3}) - 3C + 3D\Rightarrow 2 - 3C + 3D = 0\Rightarrow -3C + 3D = -2\Rightarrow D - C = \frac{2}{3}\]Solve for \(C\) and \(D\):Adding the two equations involving \(C\) and \(D\):\[C + D = \frac{2}{3} + D - C = \frac{2}{3}\Rightarrow 2D = \frac{4}{3}\Rightarrow D = \frac{2}{3}\]Therefore, \(C = 0\).
07
Write the Final Decomposition
Using the values found, write the partial fraction decomposition:\[ \frac{2x + 3}{x^4 - 9x^2} = \frac{-2/3}{x} + \frac{-1/3}{x^2} + \frac{2/3}{x + 3} + \frac{2/3}{x - 3}\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Factoring Polynomials
Factoring polynomials is a crucial step in partial fraction decomposition. In this scenario, our start point is the polynomial denominator:\[ x^4 - 9x^2 \].Factoring involves breaking down this expression into simpler polynomial factors. Notice that both terms share a common factor of \( x^2 \), allowing us to factor out \( x^2 \):\[ x^4 - 9x^2 = x^2(x^2 - 9) \].The next step involves recognizing the difference of squares in \( x^2 - 9 \), which can be factored further:\[ x^2 - 9 = (x + 3)(x - 3) \].Combining these results, we get the complete factored form:\[ x^4 - 9x^2 = x^2 (x + 3)(x - 3) \].Understanding how to factor polynomials simplifies many algebra problems, including working with rational expressions.
Rational Expressions
A rational expression is a fraction where both the numerator and the denominator are polynomials. For our example, the rational expression is:\[ \frac{2x + 3}{x^4 - 9x^2} \].Our task here is to decompose this into simpler fractions. Partial fraction decomposition allows us to express this complex fraction as a sum of simpler ones. After factoring the denominator, our rational expression looks like this:\[ \frac{2x + 3}{x^2(x + 3)(x - 3)} \].We then assume it can be written as:\[ \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x + 3} + \frac{D}{x - 3} \].Each term now represents a simpler fraction, making the expression easier to handle and integrate. Working with rational expressions requires a good grasp of factoring and basic algebraic manipulation.
Solving Systems of Equations
The partial fraction decomposition process involves determining constants (\( A, B, C, \) and \( D \)), leading us to a system of linear equations. After expressing the given fraction as partial fractions and finding a common denominator, we get:\[ 2x + 3 = A x (x+3)(x-3) + B (x+3)(x-3) + C x^2 (x-3) + D x^2 (x+3) \].Expanding and collecting like terms, we then compare coefficients to form equations like:\[ 0 = A + C + D \]\[ 0 = -3A - 3C + 3D \]\[ 2 = -3A \]\[ 3 = -9B \].These lead to a system of linear equations, which we solve step by step:
- From \( 2 = -3A \): \( A = -\frac{2}{3} \).
- From \( 3 = -9B \): \( B = -\frac{1}{3} \).
Algebra
Algebra is the broader mathematical discipline that deals with symbols and the rules for manipulating those symbols. In partial fraction decomposition, we use various fundamental algebraic techniques:
- Factoring polynomials
- Manipulating rational expressions
- Solving systems of equations