/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 80 Hyperbolic Mirrors Hyperbolas ha... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Hyperbolic Mirrors Hyperbolas have interesting reflective properties that make them useful for lenses and mirrors. For example, if a ray of light strikes a convex hyperbolic mirror on a line that would (theoretically) pass through its rear focus, it is reflected through the front focus. This property, and that of the parabola, were used to develop the Cassegrain telescope in \(1672 .\) The focus of the parabolic mirror and the rear focus of the hyperbolic mirror are the same point. The rays are collected by the parabolic mirror, then reflected toward the (common) focus, and thus are reflected by the hyperbolic mirror through the opening to its front focus, where the eyepiece is located. If the equation of the hyperbola is \(\frac{y^{2}}{9}-\frac{x^{2}}{16}=1\) and the focal length (distance from the vertex to the focus) of the parabola is \(6,\) find the equation of the parabola.

Short Answer

Expert verified
The equation of the parabola is \(y = \frac{1}{24}x^2\).

Step by step solution

01

- Identify the properties of the given hyperbola

The equation of the hyperbola is \(\frac{y^2}{9} - \frac{x^2}{16} = 1\). This is a vertical hyperbola with semimajor axis length \(a = \sqrt{9} = 3\) and semiminor axis length \(b = \sqrt{16} = 4\). The distance from the center to each focus is given by \(c = \sqrt{a^2 + b^2} = \sqrt{9 + 16} = \sqrt{25} = 5\). Therefore, the foci are located at \((0, \pm 5)\).
02

- Understand the parabolic mirror's focal length

The parabolic mirror shares the same focus point as the hyperbolic mirror, which is at \((0, 5)\). The focal length (distance from the vertex to the focus) given for the parabola is \6\ units.
03

- Determine the vertex form of the parabolic equation

A parabola with its vertex at the origin \((0, 0)\) and opening upwards can be expressed as \(y = \frac{1}{4f}x^2\), where \(f\) is the focal length. In this case, \(f = 6\).
04

- Substitute the focal length into the parabolic equation

Using the focal length, the equation becomes \(y = \frac{1}{4 \times 6} x^2 = \frac{1}{24}x^2\). Therefore, the equation of the parabola is \(y = \frac{1}{24}x^2\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

hyperbola
A hyperbola is a type of conic section formed by the intersection of a plane with a double cone. The defining feature of a hyperbola is that it consists of two separate curves, called branches, that mirror each other. The standard form of a hyperbola's equation is \(\frac{y^2}{a^2} - \frac{x^2}{b^2} = 1\) for hyperbolas that open vertically, as in our exercise example, or \(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\) for those that open horizontally. Each branch approaches a pair of straight lines called asymptotes but never actually meets them. Important properties include:

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An Explosion Two recording devices are set 2400 feet apart, with the device at point \(A\) to the west of the device at point \(B\). At a point between the devices 300 feet from point \(B,\) a small amount of explosive is detonated. The recording devices record the time until the sound reaches each. How far directly north of point \(B\) should a second explosion be done so that the measured time difference recorded by the devices is the same as that for the first detonation?

Parametric equations of four plane curves are given. Graph each of them, indicating the orientation. \(\begin{array}{ll}C_{1}: & x(t)=t, \quad y(t)=\sqrt{1-t^{2}} ; \quad-1 \leq t \leq 1 \\ C_{2}: & x(t)=\sin t, \quad y(t)=\cos t ; \quad 0 \leq t \leq 2 \pi \\\ C_{3}: & x(t)=\cos t, \quad y(t)=\sin t ; \quad 0 \leq t \leq 2 \pi \\\ C_{4}: & x(t)=\sqrt{1-t^{2}}, \quad y(t)=t ; \quad-1 \leq t \leq 1\end{array}\)

A racetrack is in the shape of an ellipse 100 feet long and 50 feet wide. What is the width 10 feet from a vertex?

A rectangle is inscribed in an ellipse with major axis of length 14 meters and minor axis of length 4 meters. Find the maximum area of a rectangle inscribed in the ellipse. Round your answer to two decimal places.

Use the fact that the orbit of a planet about the Sun is an ellipse, with the Sun at one focus. The aphelion of a planet is its greatest distance from the Sun, and the perihelion is its shortest distance. The mean distance of a planet from the Sun is the length of the semimajor axis of the elliptical orbit. The mean distance of Earth from the Sun is 93 million miles. If the aphelion of Earth is 94.5 million miles, what is the perihelion? Find an equation for the orbit of Earth around the Sun.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.