/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 76 A reflecting telescope contains ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A reflecting telescope contains a mirror shaped like a paraboloid of revolution. If the mirror is 4 inches across at its opening and is 3 inches deep, where will the collected light be concentrated?

Short Answer

Expert verified
The collected light will be concentrated 1 inch above the vertex.

Step by step solution

01

- Understand the Geometry

Identify that the mirror is shaped like a paraboloid. The problem gives the diameter (4 inches) and the depth (3 inches) of the mirror.
02

- Establish the Paraboloid Equation

Use the standard form of a parabola equation, which can be written as \(y = ax^2\). Since the diameter is 4 inches, the radius is 2 inches. Place the vertex of the parabola at the origin (0, 0) so the depth (\(y=3\)) corresponds to when \(x=2\).
03

- Solve for 'a'

Substitute the given values into the equation: \(3 = a(2)^2\). Then solve for the constant \(a\): \a = \frac{3}{4}\.
04

- Determine the Focus

Recall that for a parabola in the form \(y = ax^2\), the distance between the vertex and the focus is given by \(\frac{1}{4a}\). Substitute the previously found value of \(a\): \frac{1}{4 \times \frac{3}{4}} = \frac{1}{3}.\.
05

- Conclusion

Thus, all collected light will be concentrated at a point 1 inch above the vertex.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

paraboloid of revolution
A reflecting telescope uses a mirror shaped like a paraboloid of revolution. This shape is created by rotating a parabola around its axis. It is widely used because it directs incoming light rays to a single point, known as the focus.

In the exercise, the mirror has a diameter (or width) of 4 inches and a depth of 3 inches. When rotating a parabola to form this shape, it creates a 3D object. This unique design helps in gathering light and improving image quality.

To understand how the mirror collects light, we need to delve into the core geometry of the paraboloid.
parabola equation
The equation of a parabola is fundamental in solving this problem. It looks like this in its standard form:

\(y = ax^2\)

Here, 'y' is the depth, and 'x' represents the horizontal distance from the central axis of the parabola.

The mirror described in the problem has a diameter of 4 inches, therefore, the radius is 2 inches. The depth of the mirror is given as 3 inches. By positioning the vertex of the parabola at the origin (0, 0), this means when \(x=2, y=3\).

To find the specific value of 'a', we substitute the known values into the equation, \(3 = a(2)^2\), and solve for 'a':

\(a = \frac{3}{4}\).

Now, the equation of our specific parabola becomes \(y = \frac{3}{4}x^2\).
mirror geometry
Understanding the geometry of the mirror is crucial for solving where the light will be concentrated. Since the mirror is a paraboloid of revolution, each cross-section parallel to the axis of the parabola is a parabola.

The light rays parallel to the axis reflect off the surface and converge at a point known as the focal point. This property makes paraboloids highly efficient in focusing light.

When light hits the mirror, it reflects following the rule: the angle of incidence equals the angle of reflection. In a paraboloid, this reflection results in light rays converging at one specific point, making it ideal for telescopes.
focus calculation
Finding the focus of a parabola helps determine where the light collected by the telescope mirror will be concentrated. For a parabola of the form \(y = ax^2\), the distance from the vertex to the focus is given by:

\[\frac{1}{4a}\].

With 'a' calculated earlier as \(\frac{3}{4}\), we substitute it into the focus formula:
\[\frac{1}{4 \times \frac{3}{4}} = \frac{1}{3}\].

The focus, therefore, lies \( \frac{1}{3} \) inches above the vertex.

In conclusion, the reflecting mirror in this telescope will concentrate all collected light at a point 1 inch above the vertex, making it an efficient design for focusing incoming light rays.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Graph each function. Be sure to label any intercepts. [Hint: Notice that each function is half a hyperbola.] \(f(x)=-\sqrt{9+9 x^{2}}\)

Use the fact that the orbit of a planet about the Sun is an ellipse, with the Sun at one focus. The aphelion of a planet is its greatest distance from the Sun, and the perihelion is its shortest distance. The mean distance of a planet from the Sun is the length of the semimajor axis of the elliptical orbit. A planet orbits a star in an elliptical orbit with the star located at one focus. The perihelion of the planet is 5 million miles. The eccentricity \(e\) of a conic section is \(e=\frac{c}{a} .\) If the eccentricity of the orbit is \(0.75,\) find the aphelion of the planet.

Graph each function. Be sure to label any intercepts. [Hint: Notice that each function is half a hyperbola.] \(f(x)=\sqrt{16+4 x^{2}}\)

Analyze each equation. \(\frac{(x-3)^{2}}{4}-\frac{y^{2}}{25}=1\)

Suppose that Karla hits a golf ball off a cliff 300 meters high with an initial speed of 40 meters per second at an angle of \(45^{\circ}\) to the horizontal on the Moon (gravity on the Moon is one-sixth of that on Earth). (a) Find parametric equations that model the position of the ball as a function of time. (b) How long is the ball in the air? (c) Determine the horizontal distance that the ball travels. (d) When is the ball at its maximum height? Determine the maximum height of the ball. (e) Using a graphing utility, simultaneously graph the equations found in part (a).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.