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Based on material learned earlier in the course. The purpose of these problems is to keep the material fresh in your mind so that you are better prepared for the final exam. If \(f(x)=\frac{1}{4} x^{3}+1\) and \(g(x)=\frac{3}{4} x^{2},\) find all numbers \(c\) in the interval [0,2] where \(g(c)\) equals the average rate of change of \(f\) over the interval.

Short Answer

Expert verified
The number \(c\) in the interval [0, 2] is \(\frac{2\sqrt{3}}{3}\).

Step by step solution

01

- Define the given functions

The given functions are: \[ f(x) = \frac{1}{4}x^3 + 1 \] \[ g(x) = \frac{3}{4}x^2 \]
02

- Calculate the average rate of change of f(x) over [0,2]

The average rate of change of a function \(f(x)\) over an interval \([a,b]\) is given by: \[ \text{Average Rate of Change} = \frac{f(b) - f(a)}{b - a} \] For the interval [0,2], \(a=0\) and \(b=2\). First compute \(f(2)\) and \(f(0)\): \[ f(2) = \frac{1}{4}(2)^3 + 1 = \frac{1}{4} \cdot 8 + 1 = 2 + 1 = 3 \] \[ f(0) = \frac{1}{4}(0)^3 + 1 = 0 + 1 = 1 \] Hence, the average rate of change is: \[ \frac{3 - 1}{2 - 0} = \frac{2}{2} = 1 \]
03

- Set g(c) equal to the average rate of change

We need to find the value of \(c\) in the interval [0,2] for which \( g(c) \) equals the average rate of change of \( f(x) \): \[ g(c) = 1 \] Given \( g(x) = \frac{3}{4} x^2 \), set \( g(c) = 1 \): \[ \frac{3}{4} c^2 = 1 \]
04

- Solve for c

Isolate the variable \(c\): \[ c^2 = \frac{4}{3} \] Take the square root of both sides: \[ c = \pm \sqrt{\frac{4}{3}} \] Since \( \sqrt{\frac{4}{3}} = \frac{2}{\sqrt{3}} = \frac{2 \sqrt{3}}{3} \), we have: \[ c = \pm \frac{2 \sqrt{3}}{3} \] Only positive values in the interval [0,2] are relevant, so: \[ c = \frac{2 \sqrt{3}}{3} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

rate of change
The rate of change measures how a function's output changes as its input changes. In simpler terms, it tells us how quickly a function is increasing or decreasing. When you determine the average rate of change over an interval for a function, you're essentially finding the slope of the line that connects the two points on the function at the ends of the interval.
For instance, if a function is represented by the equation \( f(x) = \frac{1}{4} x^3 + 1 \), and you want to find the average rate of change over the interval \([0,2]\), you would use the formula:
\[ \text{Average Rate of Change} = \frac{f(b) - f(a)}{b - a} \]
Here, \(a = 0\) and \(b = 2\). You calculate the function values at these points, \( f(2) \) and \( f(0) \), and then plug them into the formula to find the average rate of change.
This step is crucial for understanding how the function behaves between the given points.
interval
An interval refers to a continuous range of values, often used to specify the region over which certain calculations are performed. In this case, our interval is \[ [0, 2] \]. This means we're looking at all the points between 0 and 2, inclusive.
Intervals can be open, closed, or half-open, which affects whether the endpoints are included.
  • A \[ [a, b] \] is a closed interval where both ends are included.
  • A \[ (a, b) \] is an open interval where neither endpoint is included.
  • A \[ [a, b) \] or \[ (a, b] \] is a half-open interval that includes only one endpoint.

Here, \[ [0, 2] \] is a closed interval, meaning we include both 0 and 2 in our calculations. This is important for finding the average rate of change, as we need to evaluate the function at both endpoints.
function evaluation
Function evaluation is the process of determining the output of a function for specific input values. In our scenario, we need to evaluate the functions \( f(x) = \frac{1}{4} x^3 + 1 \) and \( g(x) = \frac{3}{4} x^2 \) at particular points.
For example, to calculate the average rate of change of \( f(x) \) over the interval \[ [0, 2] \], we start by finding \( f(2) \) and \( f(0) \):
\[ f(2) = \frac{1}{4} (2)^3 + 1 = 3 \]
\[ f(0) = \frac{1}{4} (0)^3 + 1 = 1 \]
These evaluations allow us to compute the average rate of change, which is then set equal to \( g(c) \) to find the specific value of \( c \) that matches this rate of change within the given interval.
Without accurate function evaluation, we wouldn’t be able to reliably determine the behavior of the function over an interval or find specific values that meet certain criteria.

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