Chapter 11: Problem 6
Graph each function. Be sure to label all the intercepts. $$f(x)=\sqrt{16-4 x^{2}}$$
Short Answer
Expert verified
The x-intercepts are \( (2,0) \) and \((-2,0)\), and the y-intercept is \((0, 4)\).
Step by step solution
01
Understand the Function
The function given is \(f(x) = \sqrt{16-4x^2}\). This is a square root function, and the expression inside the square root must be non-negative.
02
Find the Domain
To ensure the expression under the square root is non-negative, solve the inequality \(16 - 4x^2 \geq 0\). This simplifies to \(4(4 - x^2) \geq 0\), or \(4 - x^2 \geq 0\). Thus, \(-2 \leq x \leq 2\).
03
Find the Intercepts
To find the x-intercepts, set \(f(x) = 0\). Solve \(\sqrt{16-4x^2} = 0\), which implies \(16 - 4x^2 = 0\). Solving this gives \(x = \pm 2\). So, the x-intercepts are at \( (2,0) \) and \((-2,0)\). To find the y-intercept, set \(x = 0\), which results in \(f(0) = \sqrt{16} = 4\). Thus, the y-intercept is at \((0, 4)\).
04
Plot the Function
Plot the points determined in Step 3 on the coordinate plane. These include \((2, 0)\), \((-2, 0)\), and \((0, 4)\). The function \(f(x)\) reaches zero at \(x = \pm 2\) and peaks at \(x = 0\).
05
Sketch the Graph
Using the intercepts and the characteristics of the square root function, sketch the graph. The curve opens downward from the peak at \(x = 0\) and touches the x-axis at \(x = \pm 2\). Ensure the curve stays within the domain determined in Step 2.
06
Label the Intercepts
Finally, label the intercepts on the graph: \((2, 0)\), \((-2, 0)\), and \((0, 4)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
domain of a function
The domain of a function is the set of all possible input values (x-values) that the function can accept. For the function \(f(x) = \sqrt{16 - 4x^2}\), the expression inside the square root, \(16 - 4x^2\), must be non-negative. This is because the square root of a negative number is not defined within the set of real numbers. To find the domain, we set up the inequality: \(16 - 4x^2 \geq 0\). Simplifying, we get \(4(4 - x^2) \geq 0\), which leads to \(4 - x^2 \geq 0\). Solving for \(x\), we find that \( -2 \leq x \leq 2\). Thus, the domain of the function is \[-2, 2\]\. This means that \(x\) can take any value from \(-2\) to \(2\), inclusive.
The concept of domain is crucial in understanding which values are valid inputs for a function. Without determining the domain, we might incorrectly assume the function is valid for all \(x\)-values, leading to errors in graphing and solving the function.
The concept of domain is crucial in understanding which values are valid inputs for a function. Without determining the domain, we might incorrectly assume the function is valid for all \(x\)-values, leading to errors in graphing and solving the function.
intercepts of a function
Intercepts are points where the graph of a function crosses the axes. There are two types of intercepts: x-intercepts and y-intercepts.
To find the x-intercepts of \(f(x) = \sqrt{16 - 4x^2}\), set the function equal to zero: \(\sqrt{16 - 4x^2} = 0\). Solving \(16 - 4x^2 = 0\) yields \(x = \pm 2\). Therefore, the x-intercepts are at points \((2, 0)\) and \((-2, 0)\). These are the points where the graph touches the x-axis.
To find the y-intercept, set \(x = 0\), and solve for \(f(0)\):\(f(0) = \sqrt{16} = 4\). Thus, the y-intercept is at \((0, 4)\). This is the point where the graph touches the y-axis.
Labeling these intercepts on the graph helps in sketching the function accurately, showing where it crosses the axes.
To find the x-intercepts of \(f(x) = \sqrt{16 - 4x^2}\), set the function equal to zero: \(\sqrt{16 - 4x^2} = 0\). Solving \(16 - 4x^2 = 0\) yields \(x = \pm 2\). Therefore, the x-intercepts are at points \((2, 0)\) and \((-2, 0)\). These are the points where the graph touches the x-axis.
To find the y-intercept, set \(x = 0\), and solve for \(f(0)\):\(f(0) = \sqrt{16} = 4\). Thus, the y-intercept is at \((0, 4)\). This is the point where the graph touches the y-axis.
Labeling these intercepts on the graph helps in sketching the function accurately, showing where it crosses the axes.
inequalities
Inequalities are mathematical expressions involving the symbols \(<\), \(>\), \(≤\), and \(≥\). They are used to describe the range of values that satisfy a particular condition. In the context of graphing functions, inequalities help determine the domain and valid x-values.
For the function \(f(x) = \sqrt{16 - 4x^2}\), the inequality \(16 - 4x^2 \geq 0\) is set up to ensure the expression inside the square root is non-negative. Solving this inequality involves a few steps:
For the function \(f(x) = \sqrt{16 - 4x^2}\), the inequality \(16 - 4x^2 \geq 0\) is set up to ensure the expression inside the square root is non-negative. Solving this inequality involves a few steps:
- First, recognize that \(16 - 4x^2\) is a quadratic expression.
- Factor it as \(4(4 - x^2) \geq 0\).
- Next, rewrite it as \(4 - x^2 \geq 0\).
- Finally, solve the inequality to find \(-2 \leq x \leq 2\).