/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 Graph the plane curve whose para... [FREE SOLUTION] | 91Ó°ÊÓ

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Graph the plane curve whose parametric equations are given, and show its orientation. Find the rectangular equation of each curve. $$ x(t)=\sqrt{2 t}, \quad y(t)=4 t ; \quad t \geq 0 $$

Short Answer

Expert verified
The rectangular equation is \( y = 2x^2 \). Orient the graph with arrows in the direction of increasing \( t \).

Step by step solution

01

- Identify parametric equations

The given parametric equations are: \[ x(t) = \sqrt{2t} \] and \[ y(t) = 4t \]. These equations define the coordinates \( (x, y) \) of a point in the plane as functions of the parameter \( t \), with \( t \geq 0 \).
02

- Determine the range for \( t \)

Since \( t \geq 0 \), this constrains the values of \( x \) and \( y \) to the specified domain of the parameter \( t \). This ensures that both \( x(t) \geq 0 \) and \( y(t) \geq 0 \).
03

- Graph the parametric equations

To graph the parametric equations, evaluate them for different values of \( t \) within the valid range, and plot the corresponding \( (x, y) \) points:For sample values:- When \( t = 0 \), \( x(0) = \sqrt{2 \cdot 0} = 0 \) and \( y(0) = 4 \cdot 0 = 0 \).- When \( t = 1 \), \( x(1) = \sqrt{2 \cdot 1} = \sqrt{2} \) and \( y(1) = 4 \cdot 1 = 4 \).- When \( t = 2 \), \( x(2) = \sqrt{2 \cdot 2} = 2 \) and \( y(2) = 4 \cdot 2 = 8 \).Plot these points on a graph and draw a smooth curve through them while indicating the orientation by showing arrows from the points corresponding to the increasing values of \( t \).
04

- Find the rectangular equation

Express \( t \) in terms of \( x \):\[ x = \sqrt{2t} \rightarrow t = \frac{x^2}{2} \]Substitute \( t \) into the equation for \( y \):\[ y = 4t \rightarrow y = 4 \left( \frac{x^2}{2} \right) = 2x^2 \]Therefore, the rectangular equation is \( y = 2x^2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Plane Curve
A plane curve is a path traced by a moving point in a plane, represented by parametric equations. In this exercise, the parametric equations are given as: \[ x(t) = \sqrt{2t} \] and \[ y(t) = 4t \]. These equations show how the coordinates of a point change with the parameter \( t \). As \( t \) increases, the point moves along the curve in the plane. This curve is a graphical way to understand how the relationship between \( x \) and \( y \) evolves with respect to \( t \). For instance, replacing different values of \( t \) like \( t = 0, 1, 2 \) in these equations gives corresponding points that can be plotted to visualize the curve.
Graphing
Graphing parametric equations involves plotting points for various values of \( t \) and connecting them smoothly. Here are steps to graph the given parametric equations:
  • Choose values of \( t \) within the allowed range, which is \( t \geq 0 \) in this case.
  • Calculate \( x(t) \) and \( y(t) \) for these values.
  • Plot the corresponding points \( (x, y) \) on the Cartesian plane.
  • Connect the points with a smooth curve and indicate the direction of increasing \( t \) using arrows.
For example:
  • When \( t = 0 \), \( x(0) = 0 \) and \( y(0) = 0 \).
  • When \( t = 1 \), \( x(1) = \sqrt{2} \) and \( y(1) = 4 \).
  • When \( t = 2 \), \( x(2) = 2 \) and \( y(2) = 8 \).
Placing these points on the graph and linking them gives us the shape of the curve. The direction of the arrows shows the orientation, which follows the values of increasing \( t \), making it clear how the curve is traced out.
Rectangular Equation
Converting from parametric to rectangular form involves eliminating the parameter \( t \). To find the rectangular equation from the given parametric equations: \[ x(t) = \sqrt{2t} \] and \[ y(t) = 4t \], we start by expressing one of the parameters in terms of \( t \). For example, \[ x = \sqrt{2t} \] can be rewritten as: \[ t = \frac{x^2}{2} \]. Next, we substitute this expression for \( t \) back into the equation for \( y \): \[ y = 4t \Rightarrow y = 4 \left( \frac{x^2}{2} \right) = 2x^2 \]. This resulting equation \( y = 2x^2 \) is the rectangular form and shows the relationship between \( x \) and \( y \) directly without involving the parameter \( t \). This form is often simpler and matches the typical Cartesian coordinate system representation.
Parametric to Rectangular Conversion
Converting parametric equations to rectangular equations can simplify the understanding and graphing of the curve. Here’s a step-by-step approach using our example:
  • Identify the parametric equations: \[ x(t) = \sqrt{2t} \] and \[ y(t) = 4t \].
  • Solve one of the parametric equations for \( t \). In this case, from \[ x(t) = \sqrt{2t} \], we get \[ t = \frac{x^2}{2} \].
  • Substitute \( t \) into the other parametric equation. Using \[ t = \frac{x^2}{2} \], substitute into \[ y(t) = 4t \], yielding \[ y = 4 \left( \frac{x^2}{2} \right) = 2x^2 \].
The final result is the rectangular equation \( y = 2x^2 \). This equation is free of the parameter \( t \), making it easier to interpret and plot on standard Cartesian coordinates. This technique is versatile and can be applied to various parametric equations to facilitate problem-solving and graphing in mathematics.

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Most popular questions from this chapter

Billy hit a baseball with an initial speed of 125 feet per second at an angle of \(40^{\circ}\) to the horizontal. The ball was hit at a height of 3 feet above the ground. (a) Find parametric equations that model the position of the ball as a function of time. (b) How long was the ball in the air? (c) Determine the horizontal distance that the ball traveled. (d) When was the ball at its maximum height? Determine the maximum height of the ball. (e) Using a graphing utility, simultaneously graph the equations found in part (a).

The pedals of an elliptical exercise machine travel an elliptical path as the user is exercising. If the stride length (length of the major axis) for one machine is 20 inches and the maximum vertical pedal displacement (length of the minor axis) is 9 inches, find the equation of the pedal path, assuming it is centered at the origin.

Jodi's bus leaves at 5: 30 pM and accelerates at the rate of 3 meters per second per second. Jodi, who can run 5 meters per second, arrives at the bus station 2 seconds after the bus has left and runs for the bus. (a) Find parametric equations that model the motions of the bus and Jodi as a function of time. [Hint: The position \(s\) at time \(t\) of an object having acceleration \(a\) is \(\left.s=\frac{1}{2} a t^{2} .\right]\) (b) Determine algebraically whether Jodi will catch the bus. If so, when? (c) Simulate the motion of the bus and Jodi by graphing simultaneously the equations found in part (a).

A football is in the shape of a prolate spheroid, which is simply a solid obtained by rotating an ellipse \(\left(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1\right)\) about its major axis. An inflated NFL football averages 11.125 inches in length and 28.25 inches in center circumference. If the volume of a prolate spheroid is \(\frac{4}{3} \pi a b^{2},\) how much air does the football contain? (Neglect material thickness.)

Use the fact that the orbit of a planet about the Sun is an ellipse, with the Sun at one focus. The aphelion of a planet is its greatest distance from the Sun, and the perihelion is its shortest distance. The mean distance of a planet from the Sun is the length of the semimajor axis of the elliptical orbit. The mean distance of Earth from the Sun is 93 million miles. If the aphelion of Earth is 94.5 million miles, what is the perihelion? Find an equation for the orbit of Earth around the Sun.

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