Chapter 1: Problem 50
Solve each inequality. Express your answer using set notation or interval notation. Graph the solution set. $$ |2-3 x|>1 $$
Short Answer
Expert verified
The solution in interval notation is \((-\infty, \frac{1}{3}) \cup (1, \infty)\).
Step by step solution
01
Understand the Absolute Value Inequality
We start with the inequality \(|2-3x| > 1\). Absolute value inequalities of the form \(|A| > B\) can be split into two separate inequalities: \(A > B\) or \(A < -B\).
02
Create Two Inequalities
Split \(|2 - 3x| > 1\) into two cases: \(2 - 3x > 1\) and \(2 - 3x < -1\).
03
Solve the First Inequality
Solve \(2 - 3x > 1\): \2 - 3x > 1\-3x > -1\text{ (subtract 2 from both sides)}\x < \frac{1}{3}\text{ (divide by -3 and reverse the inequality sign)}
04
Solve the Second Inequality
Solve \(2 - 3x < -1\): \2 - 3x < -1\-3x < -3\text{ (subtract 2 from both sides)}\x > 1\text{ (divide by -3 and reverse the inequality sign)}
05
Combine the Two Solutions
Combine the results from both inequalities: \(x < \frac{1}{3}\) or \(x > 1\).
06
Express in Interval Notation
In interval notation, the solution is \((-\infty, \frac{1}{3}) \cup (1, \infty)\).
07
Graph the Solution Set
Graph the solution on the number line: open circles at \(\frac{1}{3}\) and 1, with shading to the left of \(\frac{1}{3}\) and to the right of 1.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
inequality solving
In this example, we're solving the absolute value inequality \(|2-3x|>1\). When dealing with absolute value inequalities of the form \(|A| > B\), we split it into two separate inequalities: \(A > B\) or \( A < -B\). This approach helps us get rid of the absolute value sign and makes the problem more manageable. Here, we split \(|2-3x|>1\) into two inequalities: \(2 - 3x > 1\) and \(2 - 3x < -1\). Then, we solve each inequality one by one. First, for \(2 - 3x > 1\), subtract 2 from both sides to get \(-3x > -1\). Divide both sides by -3, remembering to reverse the inequality sign, so \(x < \frac{1}{3}\). Similarly, for \(2 - 3x < -1\), subtract 2 from both sides to get \(-3x < -3\). Then divide by -3 and reverse the inequality sign to get \(x > 1\). Combining these, our solution is \(x < \frac{1}{3}\) or \(x > 1\).
interval notation
Interval notation is a concise way of writing subsets of the real number line. We use it to express the solution sets of inequalities. The solution from our previous example, \(x < \frac{1}{3}\) and \(x > 1\), can be written in interval notation as \((-\rightarrow, \frac{1}{3}) \bigcup (1, \rightarrow)\). This means we're including all values less than \( \frac{1}{3}\) and all values greater than 1. In interval notation:
- \(-\rightarrow\) represents all values less than a certain number extending to negative infinity.
- \(\rightarrow \) represents all values greater than a certain number extending to positive infinity.
inequality graphing
To visualize the solution, we graph it on a number line. This helps us see the ranges of values that satisfy the inequality. For our solution, \(x < \frac{1}{3}\) or \(x > 1\), we'll show this using the following steps:
- Draw a number line.
- Mark open circles at \( \frac{1}{3} \) and 1, as these points are not included in our solution.
- Shade the regions to the left of \( \frac{1}{3} \) and to the right of 1.
absolute value properties
Absolute value inequalities use properties of absolute values to break down complex expressions. Recall that the absolute value \(|A|\) represents the distance of \( A \) from zero on a number line. This distance can never be negative. For an absolute value inequality like \(|2-3x| > 1\), we're looking for all \( x \) values where the distance between \(2-3x\) and 0 is greater than 1. This results in forming two separate inequalities because we consider both the positive and negative sides:
- \(A > B\) covers the scenario where \(A\) is positive and greater than \(B\).
- \(A < -B\) covers the scenario where \(A\) is negative and less than \(-B\).